预期的输入:

getDatesFromRange( '2010-10-01', '2010-10-05' );

预期的输出:

Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )

当前回答

有很多方法可以做到这一点,但最后这都取决于您使用的PHP版本。以下是所有解决方案的总结:

获取PHP版本:

echo phpinfo();

PHP 5。+。

$period = new DatePeriod(
     new DateTime('2010-10-01'),
     new DateInterval('P1D'),
     new DateTime('2010-10-05')
);

PHP 4 +

/**
 * creating between two date
 * @param string since
 * @param string until
 * @param string step
 * @param string date format
 * @return array
 * @author Ali OYGUR <alioygur@gmail.com>
 */
function dateRange($first, $last, $step = '+1 day', $format = 'd/m/Y' ) { 

    $dates = array();
    $current = strtotime($first);
    $last = strtotime($last);

    while( $current <= $last ) { 

        $dates[] = date($format, $current);
        $current = strtotime($step, $current);
    }

    return $dates;
}

PHP < 4

你应该升级:)

其他回答

使用DateTime对象的PHP 5.2解决方案。但是startDate必须在endDate之前。

function createRange($startDate, $endDate) {
    $tmpDate = new DateTime($startDate);
    $tmpEndDate = new DateTime($endDate);

    $outArray = array();
    do {
        $outArray[] = $tmpDate->format('Y-m-d');
    } while ($tmpDate->modify('+1 day') <= $tmpEndDate);

    return $outArray;
}

使用:

$dates = createRange('2010-10-01', '2010-10-05');

$日期包含:

Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )       

这是另一个解决方案。请核对一下。

$first = '10/30/2017'; //starting date
$last= '10/11/2017';   //ending date
$first_time_arr=explode('/',$first); 
$last_time_arr=explode('/',$last);
//create timestamp of starting date
$start_timestamp=mktime(0,0,0, $first_time_arr[0], $first_time_arr[1],$first_time_arr[2]);
//create timestamp of ending date
$end_timestamp=mktime(0,0,0, $last_time_arr[0], $last_time_arr[1],$last_time_arr[2]);
$date_arr=array();
for($i=$start_timestamp;$i<=$end_timestamp;$i=$i+86400){
    $date_arr[]=date("Y-m-d",$i); //this will save all dates in array
}

为了让穆斯塔法的回答更完整,这绝对是最简单和最有效的方法:

function getDatesFromRange($start_date, $end_date, $date_format = 'Y-m-d')
   {
      $dates_array = array();
      for ($x = strtotime($start_date); $x <= strtotime($end_date); $x += 86400) {
         array_push($dates_array, date($date_format, $x));
      }

      return $dates_array;
   }

   // see the dates in the array
   print_r( getDatesFromRange('2017-02-09', '2017-02-19') );

如果在调用函数时添加第三个参数,您甚至可以更改默认的输出日期格式,否则它将使用默认格式,即设置为'Y-m-d'。

我希望它能帮助你:)

简短的函数。PHP 5.3及更高版本。可以采用strtotime可以理解的任何日期格式的可选第三个参数。如果end < start自动反转方向。

function getDatesFromRange($start, $end, $format='Y-m-d') {
    return array_map(function($timestamp) use($format) {
        return date($format, $timestamp);
    },
    range(strtotime($start) + ($start < $end ? 4000 : 8000), strtotime($end) + ($start < $end ? 8000 : 4000), 86400));
}

测试:

date_default_timezone_set('Europe/Berlin');
print_r(getDatesFromRange( '2016-7-28','2016-8-2' ));
print_r(getDatesFromRange( '2016-8-2','2016-7-28' ));
print_r(getDatesFromRange( '2016-10-28','2016-11-2' ));
print_r(getDatesFromRange( '2016-11-2','2016-10-28' ));
print_r(getDatesFromRange( '2016-4-2','2016-3-25' ));
print_r(getDatesFromRange( '2016-3-25','2016-4-2' ));
print_r(getDatesFromRange( '2016-8-2','2016-7-25' ));
print_r(getDatesFromRange( '2016-7-25','2016-8-2' ));

输出:

Array ( [0] => 2016-07-28 [1] => 2016-07-29 [2] => 2016-07-30 [3] => 2016-07-31 [4] => 2016-08-01 [5] => 2016-08-02 ) 
Array ( [0] => 2016-08-02 [1] => 2016-08-01 [2] => 2016-07-31 [3] => 2016-07-30 [4] => 2016-07-29 [5] => 2016-07-28 ) 
Array ( [0] => 2016-10-28 [1] => 2016-10-29 [2] => 2016-10-30 [3] => 2016-10-31 [4] => 2016-11-01 [5] => 2016-11-02 ) 
Array ( [0] => 2016-11-02 [1] => 2016-11-01 [2] => 2016-10-31 [3] => 2016-10-30 [4] => 2016-10-29 [5] => 2016-10-28 ) 
Array ( [0] => 2016-04-02 [1] => 2016-04-01 [2] => 2016-03-31 [3] => 2016-03-30 [4] => 2016-03-29 [5] => 2016-03-28 [6] => 2016-03-27 [7] => 2016-03-26 [8] => 2016-03-25 ) 
Array ( [0] => 2016-03-25 [1] => 2016-03-26 [2] => 2016-03-27 [3] => 2016-03-28 [4] => 2016-03-29 [5] => 2016-03-30 [6] => 2016-03-31 [7] => 2016-04-01 [8] => 2016-04-02 ) 
Array ( [0] => 2016-08-02 [1] => 2016-08-01 [2] => 2016-07-31 [3] => 2016-07-30 [4] => 2016-07-29 [5] => 2016-07-28 [6] => 2016-07-27 [7] => 2016-07-26 [8] => 2016-07-25 ) 
Array ( [0] => 2016-07-25 [1] => 2016-07-26 [2] => 2016-07-27 [3] => 2016-07-28 [4] => 2016-07-29 [5] => 2016-07-30 [6] => 2016-07-31 [7] => 2016-08-01 [8] => 2016-08-02 )

我认为这是最简短的答案

按照您的喜好编辑代码

for ($x=strtotime('2015-12-01');$x<=strtotime('2015-12-30');$x+=86400)
echo date('Y-m-d',$x);