使用DateTime对象的PHP 5.2解决方案。但是startDate必须在endDate之前。

function createRange($startDate, $endDate) {
    $tmpDate = new DateTime($startDate);
    $tmpEndDate = new DateTime($endDate);

    $outArray = array();
    do {
        $outArray[] = $tmpDate->format('Y-m-d');
    } while ($tmpDate->modify('+1 day') <= $tmpEndDate);

    return $outArray;
}

使用:

$dates = createRange('2010-10-01', '2010-10-05');

$日期包含:

Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )       

  function GetDays($sStartDate, $sEndDate){  
      // Firstly, format the provided dates.  
      // This function works best with YYYY-MM-DD  
      // but other date formats will work thanks  
      // to strtotime().  
      $sStartDate = gmdate("Y-m-d", strtotime($sStartDate));  
      $sEndDate = gmdate("Y-m-d", strtotime($sEndDate));  

      // Start the variable off with the start date  
     $aDays[] = $sStartDate;  

     // Set a 'temp' variable, sCurrentDate, with  
     // the start date - before beginning the loop  
     $sCurrentDate = $sStartDate;  

     // While the current date is less than the end date  
     while($sCurrentDate < $sEndDate){  
       // Add a day to the current date  
       $sCurrentDate = gmdate("Y-m-d", strtotime("+1 day", strtotime($sCurrentDate)));  

       // Add this new day to the aDays array  
       $aDays[] = $sCurrentDate;  
     }  

     // Once the loop has finished, return the  
     // array of days.  
     return $aDays;  
   }  

使用像

GetDays('2007-01-01', '2007-01-31'); 

这是非常灵活的。

/**
 * Creating date collection between two dates
 *
 * <code>
 * <?php
 * # Example 1
 * date_range("2014-01-01", "2014-01-20", "+1 day", "m/d/Y");
 *
 * # Example 2. you can use even time
 * date_range("01:00:00", "23:00:00", "+1 hour", "H:i:s");
 * </code>
 *
 * @author Ali OYGUR <alioygur@gmail.com>
 * @param string since any date, time or datetime format
 * @param string until any date, time or datetime format
 * @param string step
 * @param string date of output format
 * @return array
 */
function date_range($first, $last, $step = '+1 day', $output_format = 'd/m/Y' ) {

    $dates = array();
    $current = strtotime($first);
    $last = strtotime($last);

    while( $current <= $last ) {

        $dates[] = date($output_format, $current);
        $current = strtotime($step, $current);
    }

    return $dates;
}

下面是一个函数，它将从两个方向返回日期范围，适用于PHP >=5.2.2:

function createRange($start, $end, $format = 'Y-m-d') {
    $start  = new DateTime($start);
    $end    = new DateTime($end);
    $invert = $start > $end;

    $dates = array();
    $dates[] = $start->format($format);
    while ($start != $end) {
        $start->modify(($invert ? '-' : '+') . '1 day');
        $dates[] = $start->format($format);
    }
    return $dates;
}

使用的例子:

print_r(createRange('2010-10-01', '2010-10-05'));
/*Array
(
    [0] => 2010-10-01
    [1] => 2010-10-02
    [2] => 2010-10-03
    [3] => 2010-10-04
    [4] => 2010-10-05
)*/

print_r(createRange('2010-10-05', '2010-10-01', 'j M Y'));
/*Array
(
    [0] => 5 Oct 2010
    [1] => 4 Oct 2010
    [2] => 3 Oct 2010
    [3] => 2 Oct 2010
    [4] => 1 Oct 2010
)*/

demo

这很简短，而且应该在PHP4+中工作。

function getDatesFromRange($start, $end){
    $dates = array($start);
    while(end($dates) < $end){
        $dates[] = date('Y-m-d', strtotime(end($dates).' +1 day'));
    }
    return $dates;
}

我认为这是最简短的答案

按照您的喜好编辑代码

for ($x=strtotime('2015-12-01');$x<=strtotime('2015-12-30');$x+=86400)
echo date('Y-m-d',$x);