预期的输入:
getDatesFromRange( '2010-10-01', '2010-10-05' );
预期的输出:
Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )
预期的输入:
getDatesFromRange( '2010-10-01', '2010-10-05' );
预期的输出:
Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )
当前回答
我认为这是最简短的答案
按照您的喜好编辑代码
for ($x=strtotime('2015-12-01');$x<=strtotime('2015-12-30');$x+=86400)
echo date('Y-m-d',$x);
其他回答
这很简短,而且应该在PHP4+中工作。
function getDatesFromRange($start, $end){
$dates = array($start);
while(end($dates) < $end){
$dates[] = date('Y-m-d', strtotime(end($dates).' +1 day'));
}
return $dates;
}
// will return dates array
function returnBetweenDates( $startDate, $endDate ){
$startStamp = strtotime( $startDate );
$endStamp = strtotime( $endDate );
if( $endStamp > $startStamp ){
while( $endStamp >= $startStamp ){
$dateArr[] = date( 'Y-m-d', $startStamp );
$startStamp = strtotime( ' +1 day ', $startStamp );
}
return $dateArr;
}else{
return $startDate;
}
}
returnBetweenDates( '2014-09-16', '2014-09-26' );
// print_r( returnBetweenDates( '2014-09-16', '2014-09-26' ) );
它将返回如下所示的数组:
Array
(
[0] => 2014-09-16
[1] => 2014-09-17
[2] => 2014-09-18
[3] => 2014-09-19
[4] => 2014-09-20
[5] => 2014-09-21
[6] => 2014-09-22
[7] => 2014-09-23
[8] => 2014-09-24
[9] => 2014-09-25
[10] => 2014-09-26
)
为了让穆斯塔法的回答更完整,这绝对是最简单和最有效的方法:
function getDatesFromRange($start_date, $end_date, $date_format = 'Y-m-d')
{
$dates_array = array();
for ($x = strtotime($start_date); $x <= strtotime($end_date); $x += 86400) {
array_push($dates_array, date($date_format, $x));
}
return $dates_array;
}
// see the dates in the array
print_r( getDatesFromRange('2017-02-09', '2017-02-19') );
如果在调用函数时添加第三个参数,您甚至可以更改默认的输出日期格式,否则它将使用默认格式,即设置为'Y-m-d'。
我希望它能帮助你:)
public static function countDays($date1,$date2)
{
$date1 = strtotime($date1); // or your date as well
$date2 = strtotime($date2);
$datediff = $date1 - $date2;
return floor($datediff/(60*60*24));
}
public static function dateRange($date1,$date2)
{
$count = static::countDays($date1,$date2) + 1;
$dates = array();
for($i=0;$i<$count;$i++)
{
$dates[] = date("Y-m-d",strtotime($date2.'+'.$i.' days'));
}
return $dates;
}
简单却有魅力:
$period = new DatePeriod(new DateTime('2015-01-01'), new DateInterval('P1D'), new DateTime('2015-01-15 +1 day'));
foreach ($period as $date) {
$dates[] = $date->format("Y-m-d");
}
//ONLY SHOWING
echo '<pre>';
var_dump($dates);
echo '</pre>';
exit();