这很简短，而且应该在PHP4+中工作。

function getDatesFromRange($start, $end){
    $dates = array($start);
    while(end($dates) < $end){
        $dates[] = date('Y-m-d', strtotime(end($dates).' +1 day'));
    }
    return $dates;
}

  function GetDays($sStartDate, $sEndDate){  
      // Firstly, format the provided dates.  
      // This function works best with YYYY-MM-DD  
      // but other date formats will work thanks  
      // to strtotime().  
      $sStartDate = gmdate("Y-m-d", strtotime($sStartDate));  
      $sEndDate = gmdate("Y-m-d", strtotime($sEndDate));  

      // Start the variable off with the start date  
     $aDays[] = $sStartDate;  

     // Set a 'temp' variable, sCurrentDate, with  
     // the start date - before beginning the loop  
     $sCurrentDate = $sStartDate;  

     // While the current date is less than the end date  
     while($sCurrentDate < $sEndDate){  
       // Add a day to the current date  
       $sCurrentDate = gmdate("Y-m-d", strtotime("+1 day", strtotime($sCurrentDate)));  

       // Add this new day to the aDays array  
       $aDays[] = $sCurrentDate;  
     }  

     // Once the loop has finished, return the  
     // array of days.  
     return $aDays;  
   }  

使用像

GetDays('2007-01-01', '2007-01-31'); 

下面是一个函数，它将从两个方向返回日期范围，适用于PHP >=5.2.2:

function createRange($start, $end, $format = 'Y-m-d') {
    $start  = new DateTime($start);
    $end    = new DateTime($end);
    $invert = $start > $end;

    $dates = array();
    $dates[] = $start->format($format);
    while ($start != $end) {
        $start->modify(($invert ? '-' : '+') . '1 day');
        $dates[] = $start->format($format);
    }
    return $dates;
}

使用的例子:

print_r(createRange('2010-10-01', '2010-10-05'));
/*Array
(
    [0] => 2010-10-01
    [1] => 2010-10-02
    [2] => 2010-10-03
    [3] => 2010-10-04
    [4] => 2010-10-05
)*/

print_r(createRange('2010-10-05', '2010-10-01', 'j M Y'));
/*Array
(
    [0] => 5 Oct 2010
    [1] => 4 Oct 2010
    [2] => 3 Oct 2010
    [3] => 2 Oct 2010
    [4] => 1 Oct 2010
)*/

demo

简单却有魅力:

    $period = new DatePeriod(new DateTime('2015-01-01'), new DateInterval('P1D'), new DateTime('2015-01-15 +1 day'));
    foreach ($period as $date) {
        $dates[] = $date->format("Y-m-d");
    }

    //ONLY SHOWING
    echo '<pre>';
    var_dump($dates);
    echo '</pre>';
    exit();

请注意，ViNce提供的答案不包括期间的结束日期。

如果你使用的是PHP 5.3+，你最好使用这样的函数:

/**
 * Generate an array of string dates between 2 dates
 *
 * @param string $start Start date
 * @param string $end End date
 * @param string $format Output format (Default: Y-m-d)
 *
 * @return array
 */
function getDatesFromRange($start, $end, $format = 'Y-m-d') {
    $array = array();
    $interval = new DateInterval('P1D');

    $realEnd = new DateTime($end);
    $realEnd->add($interval);

    $period = new DatePeriod(new DateTime($start), $interval, $realEnd);

    foreach($period as $date) { 
        $array[] = $date->format($format); 
    }

    return $array;
}

然后，你可以像预期的那样调用函数:

getDatesFromRange('2010-10-01', '2010-10-05');

运行演示

关于DatePeriod类的注意:您可以使用DatePeriod的第4个参数来排除开始日期(DatePeriod::EXCLUDE_START_DATE)，但此时不能包括结束日期。

为了让穆斯塔法的回答更完整，这绝对是最简单和最有效的方法:

function getDatesFromRange($start_date, $end_date, $date_format = 'Y-m-d')
   {
      $dates_array = array();
      for ($x = strtotime($start_date); $x <= strtotime($end_date); $x += 86400) {
         array_push($dates_array, date($date_format, $x));
      }

      return $dates_array;
   }

   // see the dates in the array
   print_r( getDatesFromRange('2017-02-09', '2017-02-19') );

如果在调用函数时添加第三个参数，您甚至可以更改默认的输出日期格式，否则它将使用默认格式，即设置为'Y-m-d'。

我希望它能帮助你:)