预期的输入:

getDatesFromRange( '2010-10-01', '2010-10-05' );

预期的输出:

Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )

当前回答

function createDateRangeArray($strDateFrom,$strDateTo)
{
    // takes two dates formatted as YYYY-MM-DD and creates an
    // inclusive array of the dates between the from and to dates.

    // could test validity of dates here but I'm already doing
    // that in the main script

    $aryRange = [];

    $iDateFrom = mktime(1, 0, 0, substr($strDateFrom, 5, 2), substr($strDateFrom, 8, 2), substr($strDateFrom, 0, 4));
    $iDateTo = mktime(1, 0, 0, substr($strDateTo, 5, 2), substr($strDateTo, 8, 2), substr($strDateTo, 0, 4));

    if ($iDateTo >= $iDateFrom) {
        array_push($aryRange, date('Y-m-d', $iDateFrom)); // first entry
        while ($iDateFrom<$iDateTo) {
            $iDateFrom += 86400; // add 24 hours
            array_push($aryRange, date('Y-m-d', $iDateFrom));
        }
    }
    return $aryRange;
}

来源:http://boonedocks.net/mike/archives/137-Creating-a-Date-Range-Array-with-PHP.html

其他回答

这是非常灵活的。

/**
 * Creating date collection between two dates
 *
 * <code>
 * <?php
 * # Example 1
 * date_range("2014-01-01", "2014-01-20", "+1 day", "m/d/Y");
 *
 * # Example 2. you can use even time
 * date_range("01:00:00", "23:00:00", "+1 hour", "H:i:s");
 * </code>
 *
 * @author Ali OYGUR <alioygur@gmail.com>
 * @param string since any date, time or datetime format
 * @param string until any date, time or datetime format
 * @param string step
 * @param string date of output format
 * @return array
 */
function date_range($first, $last, $step = '+1 day', $output_format = 'd/m/Y' ) {

    $dates = array();
    $current = strtotime($first);
    $last = strtotime($last);

    while( $current <= $last ) {

        $dates[] = date($output_format, $current);
        $current = strtotime($step, $current);
    }

    return $dates;
}

这很简短,而且应该在PHP4+中工作。

function getDatesFromRange($start, $end){
    $dates = array($start);
    while(end($dates) < $end){
        $dates[] = date('Y-m-d', strtotime(end($dates).' +1 day'));
    }
    return $dates;
}
function getWeekdayDatesFrom($format, $start_date_epoch, $end_date_epoch, $range) {

    $dates_arr = array();

    if( ! $range) {
        $range = round(abs($start_date_epoch-$end_date_epoch)/86400) + 1;
    } else {
        $range = $range + 1; //end date inclusive
    }

    $current_date_epoch = $start_date_epoch;

    for($i = 1; $i <= $range; $i+1) {

        $d = date('N',  $current_date_epoch);

        if($d <= 5) { // not sat or sun
            $dates_arr[] = "'".date($format, $current_date_epoch)."'";
        }

        $next_day_epoch = strtotime('+'.$i.'day', $start_date_epoch);
        $i++;
        $current_date_epoch = $next_day_epoch;

    }

    return $dates_arr;
} 

请注意,ViNce提供的答案不包括期间的结束日期。

如果你使用的是PHP 5.3+,你最好使用这样的函数:

/**
 * Generate an array of string dates between 2 dates
 *
 * @param string $start Start date
 * @param string $end End date
 * @param string $format Output format (Default: Y-m-d)
 *
 * @return array
 */
function getDatesFromRange($start, $end, $format = 'Y-m-d') {
    $array = array();
    $interval = new DateInterval('P1D');

    $realEnd = new DateTime($end);
    $realEnd->add($interval);

    $period = new DatePeriod(new DateTime($start), $interval, $realEnd);

    foreach($period as $date) { 
        $array[] = $date->format($format); 
    }

    return $array;
}

然后,你可以像预期的那样调用函数:

getDatesFromRange('2010-10-01', '2010-10-05');

运行演示

关于DatePeriod类的注意:您可以使用DatePeriod的第4个参数来排除开始日期(DatePeriod::EXCLUDE_START_DATE),但此时不能包括结束日期。

你必须添加$end->modify('+1 day')来包含间隔的最后一天,例如,如果不使用modify()方法,一月份将有31天而不是30天。 这个版本的代码将包括间隔的最后一天:

$begin = new DateTime( '2018-08-01' );
$end = new DateTime( '2018-08-31' );
$end = $end->modify( '+1 day' ); 

$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval ,$end);

foreach($daterange as $date){
    echo $date->format("Ymd") . "<br>";
}

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