预期的输入:

getDatesFromRange( '2010-10-01', '2010-10-05' );

预期的输出:

Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )

当前回答

function createDateRangeArray($strDateFrom,$strDateTo)
{
    // takes two dates formatted as YYYY-MM-DD and creates an
    // inclusive array of the dates between the from and to dates.

    // could test validity of dates here but I'm already doing
    // that in the main script

    $aryRange = [];

    $iDateFrom = mktime(1, 0, 0, substr($strDateFrom, 5, 2), substr($strDateFrom, 8, 2), substr($strDateFrom, 0, 4));
    $iDateTo = mktime(1, 0, 0, substr($strDateTo, 5, 2), substr($strDateTo, 8, 2), substr($strDateTo, 0, 4));

    if ($iDateTo >= $iDateFrom) {
        array_push($aryRange, date('Y-m-d', $iDateFrom)); // first entry
        while ($iDateFrom<$iDateTo) {
            $iDateFrom += 86400; // add 24 hours
            array_push($aryRange, date('Y-m-d', $iDateFrom));
        }
    }
    return $aryRange;
}

来源:http://boonedocks.net/mike/archives/137-Creating-a-Date-Range-Array-with-PHP.html

其他回答

  function GetDays($sStartDate, $sEndDate){  
      // Firstly, format the provided dates.  
      // This function works best with YYYY-MM-DD  
      // but other date formats will work thanks  
      // to strtotime().  
      $sStartDate = gmdate("Y-m-d", strtotime($sStartDate));  
      $sEndDate = gmdate("Y-m-d", strtotime($sEndDate));  

      // Start the variable off with the start date  
     $aDays[] = $sStartDate;  

     // Set a 'temp' variable, sCurrentDate, with  
     // the start date - before beginning the loop  
     $sCurrentDate = $sStartDate;  

     // While the current date is less than the end date  
     while($sCurrentDate < $sEndDate){  
       // Add a day to the current date  
       $sCurrentDate = gmdate("Y-m-d", strtotime("+1 day", strtotime($sCurrentDate)));  

       // Add this new day to the aDays array  
       $aDays[] = $sCurrentDate;  
     }  

     // Once the loop has finished, return the  
     // array of days.  
     return $aDays;  
   }  

使用像

GetDays('2007-01-01', '2007-01-31'); 

简单却有魅力:

    $period = new DatePeriod(new DateTime('2015-01-01'), new DateInterval('P1D'), new DateTime('2015-01-15 +1 day'));
    foreach ($period as $date) {
        $dates[] = $date->format("Y-m-d");
    }

    //ONLY SHOWING
    echo '<pre>';
    var_dump($dates);
    echo '</pre>';
    exit();

这是另一个解决方案。请核对一下。

$first = '10/30/2017'; //starting date
$last= '10/11/2017';   //ending date
$first_time_arr=explode('/',$first); 
$last_time_arr=explode('/',$last);
//create timestamp of starting date
$start_timestamp=mktime(0,0,0, $first_time_arr[0], $first_time_arr[1],$first_time_arr[2]);
//create timestamp of ending date
$end_timestamp=mktime(0,0,0, $last_time_arr[0], $last_time_arr[1],$last_time_arr[2]);
$date_arr=array();
for($i=$start_timestamp;$i<=$end_timestamp;$i=$i+86400){
    $date_arr[]=date("Y-m-d",$i); //this will save all dates in array
}

我认为这是最简短的答案

按照您的喜好编辑代码

for ($x=strtotime('2015-12-01');$x<=strtotime('2015-12-30');$x+=86400)
echo date('Y-m-d',$x);
public static function countDays($date1,$date2)
{
    $date1 = strtotime($date1); // or your date as well
    $date2 = strtotime($date2);
    $datediff = $date1 - $date2;
    return floor($datediff/(60*60*24));
}

public static function dateRange($date1,$date2)
{
    $count = static::countDays($date1,$date2) + 1;
    $dates = array();
    for($i=0;$i<$count;$i++)
    {
        $dates[] = date("Y-m-d",strtotime($date2.'+'.$i.' days'));
    }
    return $dates;
}