预期的输入:
getDatesFromRange( '2010-10-01', '2010-10-05' );
预期的输出:
Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )
预期的输入:
getDatesFromRange( '2010-10-01', '2010-10-05' );
预期的输出:
Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )
当前回答
function datesbetween ($date1,$date2)
{
$dates= array();
for ($i = $date1
; $i<= $date1
; $i=date_add($i, date_interval_create_from_date_string('1 days')) )
{
$dates[] = clone $i;
}
return $dates;
}
其他回答
使用DateTime对象的PHP 5.2解决方案。但是startDate必须在endDate之前。
function createRange($startDate, $endDate) {
$tmpDate = new DateTime($startDate);
$tmpEndDate = new DateTime($endDate);
$outArray = array();
do {
$outArray[] = $tmpDate->format('Y-m-d');
} while ($tmpDate->modify('+1 day') <= $tmpEndDate);
return $outArray;
}
使用:
$dates = createRange('2010-10-01', '2010-10-05');
$日期包含:
Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )
这是非常灵活的。
/**
* Creating date collection between two dates
*
* <code>
* <?php
* # Example 1
* date_range("2014-01-01", "2014-01-20", "+1 day", "m/d/Y");
*
* # Example 2. you can use even time
* date_range("01:00:00", "23:00:00", "+1 hour", "H:i:s");
* </code>
*
* @author Ali OYGUR <alioygur@gmail.com>
* @param string since any date, time or datetime format
* @param string until any date, time or datetime format
* @param string step
* @param string date of output format
* @return array
*/
function date_range($first, $last, $step = '+1 day', $output_format = 'd/m/Y' ) {
$dates = array();
$current = strtotime($first);
$last = strtotime($last);
while( $current <= $last ) {
$dates[] = date($output_format, $current);
$current = strtotime($step, $current);
}
return $dates;
}
为了让穆斯塔法的回答更完整,这绝对是最简单和最有效的方法:
function getDatesFromRange($start_date, $end_date, $date_format = 'Y-m-d')
{
$dates_array = array();
for ($x = strtotime($start_date); $x <= strtotime($end_date); $x += 86400) {
array_push($dates_array, date($date_format, $x));
}
return $dates_array;
}
// see the dates in the array
print_r( getDatesFromRange('2017-02-09', '2017-02-19') );
如果在调用函数时添加第三个参数,您甚至可以更改默认的输出日期格式,否则它将使用默认格式,即设置为'Y-m-d'。
我希望它能帮助你:)
简单却有魅力:
$period = new DatePeriod(new DateTime('2015-01-01'), new DateInterval('P1D'), new DateTime('2015-01-15 +1 day'));
foreach ($period as $date) {
$dates[] = $date->format("Y-m-d");
}
//ONLY SHOWING
echo '<pre>';
var_dump($dates);
echo '</pre>';
exit();
我认为这是最简短的答案
按照您的喜好编辑代码
for ($x=strtotime('2015-12-01');$x<=strtotime('2015-12-30');$x+=86400)
echo date('Y-m-d',$x);