预期的输入:

getDatesFromRange( '2010-10-01', '2010-10-05' );

预期的输出:

Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )

当前回答

简单却有魅力:

    $period = new DatePeriod(new DateTime('2015-01-01'), new DateInterval('P1D'), new DateTime('2015-01-15 +1 day'));
    foreach ($period as $date) {
        $dates[] = $date->format("Y-m-d");
    }

    //ONLY SHOWING
    echo '<pre>';
    var_dump($dates);
    echo '</pre>';
    exit();

其他回答

使用DateTime对象的PHP 5.2解决方案。但是startDate必须在endDate之前。

function createRange($startDate, $endDate) {
    $tmpDate = new DateTime($startDate);
    $tmpEndDate = new DateTime($endDate);

    $outArray = array();
    do {
        $outArray[] = $tmpDate->format('Y-m-d');
    } while ($tmpDate->modify('+1 day') <= $tmpEndDate);

    return $outArray;
}

使用:

$dates = createRange('2010-10-01', '2010-10-05');

$日期包含:

Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )       
<?
print_r(getDatesFromRange( '2010-10-01', '2010-10-05' ));

function getDatesFromRange($startDate, $endDate)
{
    $return = array($startDate);
    $start = $startDate;
    $i=1;
    if (strtotime($startDate) < strtotime($endDate))
    {
       while (strtotime($start) < strtotime($endDate))
        {
            $start = date('Y-m-d', strtotime($startDate.'+'.$i.' days'));
            $return[] = $start;
            $i++;
        }
    }

    return $return;
}

有很多方法可以做到这一点,但最后这都取决于您使用的PHP版本。以下是所有解决方案的总结:

获取PHP版本:

echo phpinfo();

PHP 5。+。

$period = new DatePeriod(
     new DateTime('2010-10-01'),
     new DateInterval('P1D'),
     new DateTime('2010-10-05')
);

PHP 4 +

/**
 * creating between two date
 * @param string since
 * @param string until
 * @param string step
 * @param string date format
 * @return array
 * @author Ali OYGUR <alioygur@gmail.com>
 */
function dateRange($first, $last, $step = '+1 day', $format = 'd/m/Y' ) { 

    $dates = array();
    $current = strtotime($first);
    $last = strtotime($last);

    while( $current <= $last ) { 

        $dates[] = date($format, $current);
        $current = strtotime($step, $current);
    }

    return $dates;
}

PHP < 4

你应该升级:)

$arr = range(strtotime("2013-12-01"),strtotime("2013-12-31"), "86400");
array_walk_recursive($arr, function(&$element) { $element = date("Y-m-d", $element); });
print_r ($arr);
function datesbetween ($date1,$date2)
{
    $dates= array();
    for ($i = $date1
       ; $i<= $date1
       ; $i=date_add($i, date_interval_create_from_date_string('1 days')) ) 
    {            
       $dates[] = clone $i;
    }
    return $dates;
}