预期的输入:
getDatesFromRange( '2010-10-01', '2010-10-05' );
预期的输出:
Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )
预期的输入:
getDatesFromRange( '2010-10-01', '2010-10-05' );
预期的输出:
Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )
当前回答
请注意,ViNce提供的答案不包括期间的结束日期。
如果你使用的是PHP 5.3+,你最好使用这样的函数:
/**
* Generate an array of string dates between 2 dates
*
* @param string $start Start date
* @param string $end End date
* @param string $format Output format (Default: Y-m-d)
*
* @return array
*/
function getDatesFromRange($start, $end, $format = 'Y-m-d') {
$array = array();
$interval = new DateInterval('P1D');
$realEnd = new DateTime($end);
$realEnd->add($interval);
$period = new DatePeriod(new DateTime($start), $interval, $realEnd);
foreach($period as $date) {
$array[] = $date->format($format);
}
return $array;
}
然后,你可以像预期的那样调用函数:
getDatesFromRange('2010-10-01', '2010-10-05');
运行演示
关于DatePeriod类的注意:您可以使用DatePeriod的第4个参数来排除开始日期(DatePeriod::EXCLUDE_START_DATE),但此时不能包括结束日期。
其他回答
function datesbetween ($date1,$date2)
{
$dates= array();
for ($i = $date1
; $i<= $date1
; $i=date_add($i, date_interval_create_from_date_string('1 days')) )
{
$dates[] = clone $i;
}
return $dates;
}
function GetDays($sStartDate, $sEndDate){
// Firstly, format the provided dates.
// This function works best with YYYY-MM-DD
// but other date formats will work thanks
// to strtotime().
$sStartDate = gmdate("Y-m-d", strtotime($sStartDate));
$sEndDate = gmdate("Y-m-d", strtotime($sEndDate));
// Start the variable off with the start date
$aDays[] = $sStartDate;
// Set a 'temp' variable, sCurrentDate, with
// the start date - before beginning the loop
$sCurrentDate = $sStartDate;
// While the current date is less than the end date
while($sCurrentDate < $sEndDate){
// Add a day to the current date
$sCurrentDate = gmdate("Y-m-d", strtotime("+1 day", strtotime($sCurrentDate)));
// Add this new day to the aDays array
$aDays[] = $sCurrentDate;
}
// Once the loop has finished, return the
// array of days.
return $aDays;
}
使用像
GetDays('2007-01-01', '2007-01-31');
这是另一个解决方案。请核对一下。
$first = '10/30/2017'; //starting date
$last= '10/11/2017'; //ending date
$first_time_arr=explode('/',$first);
$last_time_arr=explode('/',$last);
//create timestamp of starting date
$start_timestamp=mktime(0,0,0, $first_time_arr[0], $first_time_arr[1],$first_time_arr[2]);
//create timestamp of ending date
$end_timestamp=mktime(0,0,0, $last_time_arr[0], $last_time_arr[1],$last_time_arr[2]);
$date_arr=array();
for($i=$start_timestamp;$i<=$end_timestamp;$i=$i+86400){
$date_arr[]=date("Y-m-d",$i); //this will save all dates in array
}
使用DateTime对象的PHP 5.2解决方案。但是startDate必须在endDate之前。
function createRange($startDate, $endDate) {
$tmpDate = new DateTime($startDate);
$tmpEndDate = new DateTime($endDate);
$outArray = array();
do {
$outArray[] = $tmpDate->format('Y-m-d');
} while ($tmpDate->modify('+1 day') <= $tmpEndDate);
return $outArray;
}
使用:
$dates = createRange('2010-10-01', '2010-10-05');
$日期包含:
Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )
这很简短,而且应该在PHP4+中工作。
function getDatesFromRange($start, $end){
$dates = array($start);
while(end($dates) < $end){
$dates[] = date('Y-m-d', strtotime(end($dates).' +1 day'));
}
return $dates;
}