我有一个熊猫数据框架,我想把它分为3个单独的集。我知道使用sklearn中的train_test_split。交叉验证,可以将数据分为两组(训练和测试)。然而,我无法找到将数据分成三组的任何解决方案。最好是有原始数据的下标。
我知道一个解决办法是使用train_test_split两次,并以某种方式调整索引。但是是否有一种更标准/内置的方法将数据分成3组而不是2组?
我有一个熊猫数据框架,我想把它分为3个单独的集。我知道使用sklearn中的train_test_split。交叉验证,可以将数据分为两组(训练和测试)。然而,我无法找到将数据分成三组的任何解决方案。最好是有原始数据的下标。
我知道一个解决办法是使用train_test_split两次,并以某种方式调整索引。但是是否有一种更标准/内置的方法将数据分成3组而不是2组?
当前回答
回答任意数量的子集:
def _separate_dataset(patches, label_patches, percentage, shuffle: bool = True):
"""
:param patches: data patches
:param label_patches: label patches
:param percentage: list of percentages for each value, example [0.9, 0.02, 0.08] to get 90% train, 2% val and 8% test.
:param shuffle: Shuffle dataset before split.
:return: tuple of two lists of size = len(percentage), one with data x and other with labels y.
"""
x_test = patches
y_test = label_patches
percentage = list(percentage) # need it to be mutable
assert sum(percentage) == 1., f"percentage must add to 1, but it adds to sum{percentage} = {sum(percentage)}"
x = []
y = []
for i, per in enumerate(percentage[:-1]):
x_train, x_test, y_train, y_test = train_test_split(x_test, y_test, test_size=1-per, shuffle=shuffle)
percentage[i+1:] = [value / (1-percentage[i]) for value in percentage[i+1:]]
x.append(x_train)
y.append(y_train)
x.append(x_test)
y.append(y_test)
return x, y
这适用于任何比例。在本例中,您应该执行percentage = [train_percentage, val_percentage, test_percentage]。
其他回答
将数据集分割为训练集和测试集,如在其他答案中一样,使用
from sklearn.model_selection import train_test_split
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.2, random_state=42)
然后,如果您适合您的模型,您可以添加validation_split作为参数。这样就不需要提前创建验证集。例如:
from tensorflow.keras import Model
model = Model(input_layer, out)
[...]
history = model.fit(x=X_train, y=y_train, [...], validation_split = 0.3)
验证集旨在作为训练集训练期间的代表运行测试集,完全来自训练集,无论是通过k-fold交叉验证(推荐)还是通过validation_split;然后,您不需要单独创建一个验证集,仍然可以将数据集分为您所要求的三个集。
Numpy解决方案。我们将首先洗牌整个数据集(df。Sample (frac=1, random_state=42)),然后将我们的数据集分成以下部分:
60% -列车集, 20% -验证集, 20% -测试装置
In [305]: train, validate, test = \
np.split(df.sample(frac=1, random_state=42),
[int(.6*len(df)), int(.8*len(df))])
In [306]: train
Out[306]:
A B C D E
0 0.046919 0.792216 0.206294 0.440346 0.038960
2 0.301010 0.625697 0.604724 0.936968 0.870064
1 0.642237 0.690403 0.813658 0.525379 0.396053
9 0.488484 0.389640 0.599637 0.122919 0.106505
8 0.842717 0.793315 0.554084 0.100361 0.367465
7 0.185214 0.603661 0.217677 0.281780 0.938540
In [307]: validate
Out[307]:
A B C D E
5 0.806176 0.008896 0.362878 0.058903 0.026328
6 0.145777 0.485765 0.589272 0.806329 0.703479
In [308]: test
Out[308]:
A B C D E
4 0.521640 0.332210 0.370177 0.859169 0.401087
3 0.333348 0.964011 0.083498 0.670386 0.169619
[int(.6*len(df)), int(.8*len(df))] -是numpy.split()的indices_or_sections数组。
下面是一个np.split()使用的小演示-让我们把20个元素的数组分成以下部分:80%,10%,10%:
In [45]: a = np.arange(1, 21)
In [46]: a
Out[46]: array([ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20])
In [47]: np.split(a, [int(.8 * len(a)), int(.9 * len(a))])
Out[47]:
[array([ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16]),
array([17, 18]),
array([19, 20])]
使用train_test_split非常方便,不需要在划分到几个集后执行重新索引,也不需要编写一些额外的代码。上面的最佳答案没有提到使用train_test_split分隔两次而不改变分区大小将不会给出最初预期的分区:
x_train, x_remain = train_test_split(x, test_size=(val_size + test_size))
那么x_remain中的验证集和测试集的部分就会发生变化,可以算作
new_test_size = np.around(test_size / (val_size + test_size), 2)
# To preserve (new_test_size + new_val_size) = 1.0
new_val_size = 1.0 - new_test_size
x_val, x_test = train_test_split(x_remain, test_size=new_test_size)
在这种情况下,将保存所有初始分区。
注意:
函数被编写来处理随机集创建的播种。你不应该依赖集分割,它不会随机化集合。
import numpy as np
import pandas as pd
def train_validate_test_split(df, train_percent=.6, validate_percent=.2, seed=None):
np.random.seed(seed)
perm = np.random.permutation(df.index)
m = len(df.index)
train_end = int(train_percent * m)
validate_end = int(validate_percent * m) + train_end
train = df.iloc[perm[:train_end]]
validate = df.iloc[perm[train_end:validate_end]]
test = df.iloc[perm[validate_end:]]
return train, validate, test
示范
np.random.seed([3,1415])
df = pd.DataFrame(np.random.rand(10, 5), columns=list('ABCDE'))
df
train, validate, test = train_validate_test_split(df)
train
validate
test
def train_val_test_split(X, y, train_size, val_size, test_size):
X_train_val, X_test, y_train_val, y_test = train_test_split(X, y, test_size = test_size)
relative_train_size = train_size / (val_size + train_size)
X_train, X_val, y_train, y_val = train_test_split(X_train_val, y_train_val,
train_size = relative_train_size, test_size = 1-relative_train_size)
return X_train, X_val, X_test, y_train, y_val, y_test
在这里,我们使用sklearn的train_test_split将数据分割2次