我有以下代码:

info = new System.Diagnostics.ProcessStartInfo("TheProgram.exe", String.Join(" ", args));
info.CreateNoWindow = true;
info.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
info.RedirectStandardOutput = true;
info.UseShellExecute = false;
System.Diagnostics.Process p = System.Diagnostics.Process.Start(info);
p.WaitForExit();
Console.WriteLine(p.StandardOutput.ReadToEnd()); //need the StandardOutput contents

我知道我正在启动的进程的输出大约有7MB长。在Windows控制台中运行它可以正常工作。不幸的是,从编程的角度来看,它会无限期地挂在WaitForExit上。还要注意,对于较小的输出(比如3KB),这段代码不会挂起。

ProcessStartInfo中的内部StandardOutput是否可能不能缓冲7MB?如果是,我该怎么办?如果不是,我做错了什么?


当前回答

流程的文档。StandardOutput说在你等待之前读取,否则你会死锁,代码片段复制如下:

 // Start the child process.
 Process p = new Process();
 // Redirect the output stream of the child process.
 p.StartInfo.UseShellExecute = false;
 p.StartInfo.RedirectStandardOutput = true;
 p.StartInfo.FileName = "Write500Lines.exe";
 p.Start();
 // Do not wait for the child process to exit before
 // reading to the end of its redirected stream.
 // p.WaitForExit();
 // Read the output stream first and then wait.
 string output = p.StandardOutput.ReadToEnd();
 p.WaitForExit();

其他回答

上面的答案没有一个能起作用。

Rob解决方案挂起,“Mark Byers”解决方案获得已处理异常。(我尝试了其他答案的“解决方案”)。

所以我决定提出另一个解决方案:

public void GetProcessOutputWithTimeout(Process process, int timeoutSec, CancellationToken token, out string output, out int exitCode)
{
    string outputLocal = "";  int localExitCode = -1;
    var task = System.Threading.Tasks.Task.Factory.StartNew(() =>
    {
        outputLocal = process.StandardOutput.ReadToEnd();
        process.WaitForExit();
        localExitCode = process.ExitCode;
    }, token);

    if (task.Wait(timeoutSec, token))
    {
        output = outputLocal;
        exitCode = localExitCode;
    }
    else
    {
        exitCode = -1;
        output = "";
    }
}

using (var process = new Process())
{
    process.StartInfo = ...;
    process.Start();
    string outputUnicode; int exitCode;
    GetProcessOutputWithTimeout(process, PROCESS_TIMEOUT, out outputUnicode, out exitCode);
}

这段代码经过调试,工作完美。

我是这样解决的:

            Process proc = new Process();
            proc.StartInfo.FileName = batchFile;
            proc.StartInfo.UseShellExecute = false;
            proc.StartInfo.CreateNoWindow = true;
            proc.StartInfo.RedirectStandardError = true;
            proc.StartInfo.RedirectStandardInput = true;
            proc.StartInfo.RedirectStandardOutput = true;
            proc.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;      
            proc.Start();
            StreamWriter streamWriter = proc.StandardInput;
            StreamReader outputReader = proc.StandardOutput;
            StreamReader errorReader = proc.StandardError;
            while (!outputReader.EndOfStream)
            {
                string text = outputReader.ReadLine();                    
                streamWriter.WriteLine(text);
            }

            while (!errorReader.EndOfStream)
            {                   
                string text = errorReader.ReadLine();
                streamWriter.WriteLine(text);
            }

            streamWriter.Close();
            proc.WaitForExit();

我重定向输入,输出和错误,并处理从输出和错误流读取。 此解决方案适用于SDK 7- 8.1,适用于Windows 7和Windows 8

未处理的ObjectDisposedException问题发生在进程超时时。在这种情况下,条件的其他部分:

if (process.WaitForExit(timeout) 
    && outputWaitHandle.WaitOne(timeout) 
    && errorWaitHandle.WaitOne(timeout))

不执行。我用以下方法解决了这个问题:

using (AutoResetEvent outputWaitHandle = new AutoResetEvent(false))
using (AutoResetEvent errorWaitHandle = new AutoResetEvent(false))
{
    using (Process process = new Process())
    {
        // preparing ProcessStartInfo

        try
        {
            process.OutputDataReceived += (sender, e) =>
                {
                    if (e.Data == null)
                    {
                        outputWaitHandle.Set();
                    }
                    else
                    {
                        outputBuilder.AppendLine(e.Data);
                    }
                };
            process.ErrorDataReceived += (sender, e) =>
                {
                    if (e.Data == null)
                    {
                        errorWaitHandle.Set();
                    }
                    else
                    {
                        errorBuilder.AppendLine(e.Data);
                    }
                };

            process.Start();

            process.BeginOutputReadLine();
            process.BeginErrorReadLine();

            if (process.WaitForExit(timeout))
            {
                exitCode = process.ExitCode;
            }
            else
            {
                // timed out
            }

            output = outputBuilder.ToString();
        }
        finally
        {
            outputWaitHandle.WaitOne(timeout);
            errorWaitHandle.WaitOne(timeout);
        }
    }
}

我认为使用async,可以有一个更优雅的解决方案,即使同时使用standardOutput和standardError也不会出现死锁:

using (Process process = new Process())
{
    process.StartInfo.FileName = filename;
    process.StartInfo.Arguments = arguments;
    process.StartInfo.UseShellExecute = false;
    process.StartInfo.RedirectStandardOutput = true;
    process.StartInfo.RedirectStandardError = true;

    process.Start();

    var tStandardOutput = process.StandardOutput.ReadToEndAsync();
    var tStandardError = process.StandardError.ReadToEndAsync();

    if (process.WaitForExit(timeout))
    {
        string output = await tStandardOutput;
        string errors = await tStandardError;

        // Process completed. Check process.ExitCode here.
    }
    else
    {
        // Timed out.
    }
}

这是基于Mark Byers的回答。 如果你不在异步方法中,你可以使用string output = tStandardOutput.result;而不是等待

我试图通过考虑Mark Byers, Rob, stevejay的回答,创建一个类来解决你使用异步流读取的问题。这样做,我意识到有一个与异步流程输出流读取相关的错误。

我在微软报告了这个漏洞:https://connect.microsoft.com/VisualStudio/feedback/details/3119134

简介:

You can't do that: process.BeginOutputReadLine(); process.Start(); You will receive System.InvalidOperationException : StandardOut has not been redirected or the process hasn't started yet. ============================================================================================================================ Then you have to start asynchronous output read after the process is started: process.Start(); process.BeginOutputReadLine(); Doing so, make a race condition because the output stream can receive data before you set it to asynchronous:

process.Start(); 
// Here the operating system could give the cpu to another thread.  
// For example, the newly created thread (Process) and it could start writing to the output
// immediately before next line would execute. 
// That create a race condition.
process.BeginOutputReadLine();

============================================================================================================================ Then some people could say that you just have to read the stream before you set it to asynchronous. But the same problem occurs. There will be a race condition between the synchronous read and set the stream into asynchronous mode. ============================================================================================================================ There is no way to acheive safe asynchronous read of an output stream of a process in the actual way "Process" and "ProcessStartInfo" has been designed.

对于您的情况,您最好使用其他用户建议的异步读取。但是您应该意识到,由于竞态条件,您可能会错过一些信息。