根据@givanse的回答，以下是你可以用类来做的:

class Swipe {
    constructor(element) {
        this.xDown = null;
        this.yDown = null;
        this.element = typeof(element) === 'string' ? document.querySelector(element) : element;

        this.element.addEventListener('touchstart', function(evt) {
            this.xDown = evt.touches[0].clientX;
            this.yDown = evt.touches[0].clientY;
        }.bind(this), false);

    }

    onLeft(callback) {
        this.onLeft = callback;

        return this;
    }

    onRight(callback) {
        this.onRight = callback;

        return this;
    }

    onUp(callback) {
        this.onUp = callback;

        return this;
    }

    onDown(callback) {
        this.onDown = callback;

        return this;
    }

    handleTouchMove(evt) {
        if ( ! this.xDown || ! this.yDown ) {
            return;
        }

        var xUp = evt.touches[0].clientX;
        var yUp = evt.touches[0].clientY;

        this.xDiff = this.xDown - xUp;
        this.yDiff = this.yDown - yUp;

        if ( Math.abs( this.xDiff ) > Math.abs( this.yDiff ) ) { // Most significant.
            if ( this.xDiff > 0 ) {
                this.onLeft();
            } else {
                this.onRight();
            }
        } else {
            if ( this.yDiff > 0 ) {
                this.onUp();
            } else {
                this.onDown();
            }
        }

        // Reset values.
        this.xDown = null;
        this.yDown = null;
    }

    run() {
        this.element.addEventListener('touchmove', function(evt) {
            this.handleTouchMove(evt).bind(this);
        }.bind(this), false);
    }
}

你可以这样使用它:

// Use class to get element by string.
var swiper = new Swipe('#my-element');
swiper.onLeft(function() { alert('You swiped left.') });
swiper.run();

// Get the element yourself.
var swiper = new Swipe(document.getElementById('#my-element'));
swiper.onLeft(function() { alert('You swiped left.') });
swiper.run();

// One-liner.
(new Swipe('#my-element')).onLeft(function() { alert('You swiped left.') }).run();

我之前使用的方法是，您必须检测mousedown事件，记录其x,y位置(任何相关的位置)，然后检测mouseup事件，并减去两个值。

简单的JS代码示例:

document.addEventListener('touchstart', handleTouchStart, false);        
document.addEventListener('touchmove', handleTouchMove, false);

var xDown = null;                                                        
var yDown = null;

function getTouches(evt) {
  return evt.touches ||             // browser API
         evt.originalEvent.touches; // jQuery
}                                                     
                                                                         
function handleTouchStart(evt) {
    const firstTouch = getTouches(evt)[0];                                      
    xDown = firstTouch.clientX;                                      
    yDown = firstTouch.clientY;                                      
};                                                
                                                                         
function handleTouchMove(evt) {
    if ( ! xDown || ! yDown ) {
        return;
    }

    var xUp = evt.touches[0].clientX;                                    
    var yUp = evt.touches[0].clientY;

    var xDiff = xDown - xUp;
    var yDiff = yDown - yUp;
                                                                         
    if ( Math.abs( xDiff ) > Math.abs( yDiff ) ) {/*most significant*/
        if ( xDiff > 0 ) {
            /* right swipe */ 
        } else {
            /* left swipe */
        }                       
    } else {
        if ( yDiff > 0 ) {
            /* down swipe */ 
        } else { 
            /* up swipe */
        }                                                                 
    }
    /* reset values */
    xDown = null;
    yDown = null;                                             
};

Android测试。

我也合并了一些答案，主要是第一个和第二个与类，下面是我的版本:

export default class Swipe {
    constructor(options) {
        this.xDown = null;
        this.yDown = null;

        this.options = options;

        this.handleTouchStart = this.handleTouchStart.bind(this);
        this.handleTouchMove = this.handleTouchMove.bind(this);

        document.addEventListener('touchstart', this.handleTouchStart, false);
        document.addEventListener('touchmove', this.handleTouchMove, false);

    }

    onLeft() {
        this.options.onLeft();
    }

    onRight() {
        this.options.onRight();
    }

    onUp() {
        this.options.onUp();
    }

    onDown() {
        this.options.onDown();
    }

    static getTouches(evt) {
        return evt.touches      // browser API

    }

    handleTouchStart(evt) {
        const firstTouch = Swipe.getTouches(evt)[0];
        this.xDown = firstTouch.clientX;
        this.yDown = firstTouch.clientY;
    }

    handleTouchMove(evt) {
        if ( ! this.xDown || ! this.yDown ) {
            return;
        }

        let xUp = evt.touches[0].clientX;
        let yUp = evt.touches[0].clientY;

        let xDiff = this.xDown - xUp;
        let yDiff = this.yDown - yUp;


        if ( Math.abs( xDiff ) > Math.abs( yDiff ) ) {/*most significant*/
            if ( xDiff > 0 && this.options.onLeft) {
                /* left swipe */
                this.onLeft();
            } else if (this.options.onRight) {
                /* right swipe */
                this.onRight();
            }
        } else {
            if ( yDiff > 0 && this.options.onUp) {
                /* up swipe */
                this.onUp();
            } else if (this.options.onDown){
                /* down swipe */
                this.onDown();
            }
        }

        /* reset values */
        this.xDown = null;
        this.yDown = null;
    }
}

之后可以这样使用:

let swiper = new Swipe({
                    onLeft() {
                        console.log('You swiped left.');
                    }
});

当你只想调用“onLeft”方法时，它有助于避免控制台错误。

我重新包装了TouchWipe作为一个简短的jquery插件:detectSwipe

我发现@givanse的答案是最可靠和最兼容的多个移动浏览器，用于注册滑动操作。

但是，他的代码需要做一些更改，才能在使用jQuery的现代移动浏览器中工作。

事件。如果使用jQuery并且结果为undefined, touches将不存在，应该由event. originalevent . touches_替换。没有jQuery，事件。触摸应该可以正常工作。

所以解就是，

document.addEventListener('touchstart', handleTouchStart, false);        
document.addEventListener('touchmove', handleTouchMove, false);

var xDown = null;                                                        
var yDown = null;                                                        

function handleTouchStart(evt) {                                         
    xDown = evt.originalEvent.touches[0].clientX;                                      
    yDown = evt.originalEvent.touches[0].clientY;                                      
};                                                

function handleTouchMove(evt) {
    if ( ! xDown || ! yDown ) {
        return;
    }

    var xUp = evt.originalEvent.touches[0].clientX;                                    
    var yUp = evt.originalEvent.touches[0].clientY;

    var xDiff = xDown - xUp;
    var yDiff = yDown - yUp;

    if ( Math.abs( xDiff ) > Math.abs( yDiff ) ) {/*most significant*/
        if ( xDiff > 0 ) {
            /* left swipe */ 
        } else {
            /* right swipe */
        }                       
    } else {
        if ( yDiff > 0 ) {
            /* up swipe */ 
        } else { 
            /* down swipe */
        }                                                                 
    }
    /* reset values */
    xDown = null;
    yDown = null;                                             
};

测试:

Android: Chrome, UC浏览器 iOS: Safari, Chrome, UC浏览器