如何检测用户用JavaScript在网页上向某个方向滑动手指?
我想知道是否有一种解决方案可以同时适用于iPhone和Android手机上的网站。
如何检测用户用JavaScript在网页上向某个方向滑动手指?
我想知道是否有一种解决方案可以同时适用于iPhone和Android手机上的网站。
当前回答
如果有人试图在Android上使用jQuery Mobile,并且有JQM滑动检测的问题
(我在Xperia Z1, Galaxy S3, Nexus 4和一些Wiko手机上也有一些)这可能很有用:
//Fix swipe gesture on android
if(android){ //Your own device detection here
$.event.special.swipe.verticalDistanceThreshold = 500
$.event.special.swipe.horizontalDistanceThreshold = 10
}
在android上的滑动不会被检测到,除非它是一个非常长、精确和快速的滑动。
这两条线可以正常工作
其他回答
我之前使用的方法是,您必须检测mousedown事件,记录其x,y位置(任何相关的位置),然后检测mouseup事件,并减去两个值。
根据@givanse的回答,以下是你可以用类来做的:
class Swipe {
constructor(element) {
this.xDown = null;
this.yDown = null;
this.element = typeof(element) === 'string' ? document.querySelector(element) : element;
this.element.addEventListener('touchstart', function(evt) {
this.xDown = evt.touches[0].clientX;
this.yDown = evt.touches[0].clientY;
}.bind(this), false);
}
onLeft(callback) {
this.onLeft = callback;
return this;
}
onRight(callback) {
this.onRight = callback;
return this;
}
onUp(callback) {
this.onUp = callback;
return this;
}
onDown(callback) {
this.onDown = callback;
return this;
}
handleTouchMove(evt) {
if ( ! this.xDown || ! this.yDown ) {
return;
}
var xUp = evt.touches[0].clientX;
var yUp = evt.touches[0].clientY;
this.xDiff = this.xDown - xUp;
this.yDiff = this.yDown - yUp;
if ( Math.abs( this.xDiff ) > Math.abs( this.yDiff ) ) { // Most significant.
if ( this.xDiff > 0 ) {
this.onLeft();
} else {
this.onRight();
}
} else {
if ( this.yDiff > 0 ) {
this.onUp();
} else {
this.onDown();
}
}
// Reset values.
this.xDown = null;
this.yDown = null;
}
run() {
this.element.addEventListener('touchmove', function(evt) {
this.handleTouchMove(evt).bind(this);
}.bind(this), false);
}
}
你可以这样使用它:
// Use class to get element by string.
var swiper = new Swipe('#my-element');
swiper.onLeft(function() { alert('You swiped left.') });
swiper.run();
// Get the element yourself.
var swiper = new Swipe(document.getElementById('#my-element'));
swiper.onLeft(function() { alert('You swiped left.') });
swiper.run();
// One-liner.
(new Swipe('#my-element')).onLeft(function() { alert('You swiped left.') }).run();
在这里的建议之上,我将跟踪手指号码,因为如果你同时用两个手指触摸,它将获得X位置,而不会导致一个奇怪的行为,而且,你可能想要设置一个“距离”最小值,这样用户在通过你的网站或应用程序触摸时就不会错误地触发滑动。
//Swipe
let touchstartX = 0
let touchendX = 0
let fingerCount = 0
const checkDirection = () => {
const distance = 50 //Minimum distance for the swipe to work
//left
if (touchendX < touchstartX && (touchstartX - touchendX) > distance ){
//Do something cool
}
//right
if (touchendX > touchstartX && (touchendX - touchstartX) > distance){
//Do something cooler
}
document.addEventListener('touchstart', e => {
fingerCount = e.touches.length
touchstartX = e.changedTouches[0].clientX
})
document.addEventListener('touchend', e => {
touchendX = e.changedTouches[0].clientX
if(fingerCount === 1){
checkDirection()
}
})
我必须为旋转木马编写一个简单的脚本,以检测向左或向右的滑动。
我使用指针事件代替触摸事件。
我希望这对个人有用,我欢迎任何改进我的代码的见解;我觉得很不好意思加入这个线程与显著优秀的JS开发人员。
function getSwipeX({elementId}) {
this.e = document.getElementsByClassName(elementId)[0];
this.initialPosition = 0;
this.lastPosition = 0;
this.threshold = 200;
this.diffInPosition = null;
this.diffVsThreshold = null;
this.gestureState = 0;
this.getTouchStart = (event) => {
event.preventDefault();
if (window.PointerEvent) {
this.e.setPointerCapture(event.pointerId);
}
return this.initalTouchPos = this.getGesturePoint(event);
}
this.getTouchMove = (event) => {
event.preventDefault();
return this.lastPosition = this.getGesturePoint(event);
}
this.getTouchEnd = (event) => {
event.preventDefault();
if (window.PointerEvent) {
this.e.releasePointerCapture(event.pointerId);
}
this.doSomething();
this.initialPosition = 0;
}
this.getGesturePoint = (event) => {
this.point = event.pageX
return this.point;
}
this.whatGestureDirection = (event) => {
this.diffInPosition = this.initalTouchPos - this.lastPosition;
this.diffVsThreshold = Math.abs(this.diffInPosition) > this.threshold;
(Math.sign(this.diffInPosition) > 0) ? this.gestureState = 'L' : (Math.sign(this.diffInPosition) < 0) ? this.gestureState = 'R' : this.gestureState = 'N';
return [this.diffInPosition, this.diffVsThreshold, this.gestureState];
}
this.doSomething = (event) => {
let [gestureDelta,gestureThreshold,gestureDirection] = this.whatGestureDirection();
// USE THIS TO DEBUG
console.log(gestureDelta,gestureThreshold,gestureDirection);
if (gestureThreshold) {
(gestureDirection == 'L') ? // LEFT ACTION : // RIGHT ACTION
}
}
if (window.PointerEvent) {
this.e.addEventListener('pointerdown', this.getTouchStart, true);
this.e.addEventListener('pointermove', this.getTouchMove, true);
this.e.addEventListener('pointerup', this.getTouchEnd, true);
this.e.addEventListener('pointercancel', this.getTouchEnd, true);
}
}
可以使用new调用该函数。
window.addEventListener('load', () => {
let test = new getSwipeX({
elementId: 'your_div_here'
});
})
简单的JS代码示例:
document.addEventListener('touchstart', handleTouchStart, false);
document.addEventListener('touchmove', handleTouchMove, false);
var xDown = null;
var yDown = null;
function getTouches(evt) {
return evt.touches || // browser API
evt.originalEvent.touches; // jQuery
}
function handleTouchStart(evt) {
const firstTouch = getTouches(evt)[0];
xDown = firstTouch.clientX;
yDown = firstTouch.clientY;
};
function handleTouchMove(evt) {
if ( ! xDown || ! yDown ) {
return;
}
var xUp = evt.touches[0].clientX;
var yUp = evt.touches[0].clientY;
var xDiff = xDown - xUp;
var yDiff = yDown - yUp;
if ( Math.abs( xDiff ) > Math.abs( yDiff ) ) {/*most significant*/
if ( xDiff > 0 ) {
/* right swipe */
} else {
/* left swipe */
}
} else {
if ( yDiff > 0 ) {
/* down swipe */
} else {
/* up swipe */
}
}
/* reset values */
xDown = null;
yDown = null;
};
Android测试。