我要做一个柱状图,其中最大的柱状图离y轴最近,最短的柱状图离y轴最远。这有点像我的表格
Name Position
1 James Goalkeeper
2 Frank Goalkeeper
3 Jean Defense
4 Steve Defense
5 John Defense
6 Tim Striker
所以我试图建立一个条形图,根据位置显示球员的数量
p <- ggplot(theTable, aes(x = Position)) + geom_bar(binwidth = 1)
但是图表显示的是门将栏,然后是防守栏,最后是前锋栏。我希望图表的顺序是,防守条最靠近y轴,守门员条,最后是前锋条。
谢谢
另一种方法是使用重新排序来排列因子的级别。根据计数的升序(n)或降序(-n)。非常类似于使用forcats包中的fct_reorder:
降序排列
df %>%
count(Position) %>%
ggplot(aes(x = reorder(Position, -n), y = n)) +
geom_bar(stat = 'identity') +
xlab("Position")
升序排序
df % > %
数(位置)% > %
ggplot(aes(x = reorder(Position, n), y = n)) +
Geom_bar (stat = 'identity') +
xlab(“位置”)
数据帧:
df <- structure(list(Position = structure(c(3L, 3L, 1L, 1L, 1L, 2L), .Label = c("防御",
"前锋","Zoalkeeper"), class = "factor"), Name =结构(c(2L,
1 l, 3 l 5 l 4 l, 6 l), .Label = c(“弗兰克”,“詹姆斯”,“琼”,“约翰”,
"Steve", "Tim"), class = "factor")), class = "data.frame", row.names = c(NA,
6 l))
你只需要指定Position列为一个有序因子,其中级别是按它们的计数排序的:
theTable <- transform( theTable,
Position = ordered(Position, levels = names( sort(-table(Position)))))
(请注意,表(Position)产生了Position列的频率计数。)
然后,您的ggplot函数将以计数递减的顺序显示条形图。
我不知道在geom_bar中是否有一个选项可以在不显式地创建有序因子的情况下做到这一点。
library(ggplot2)
library(magrittr)
dd <- tibble::tribble(
~Name, ~Position,
"James", "Goalkeeper",
"Frank", "Goalkeeper",
"Jean", "Defense",
"John", "Defense",
"Steve", "Defense",
"Tim", "Striker"
)
dd %>% ggplot(aes(x = forcats::fct_infreq(Position))) + geom_bar()
于2022-08-30使用reprex v2.0.2创建
除了forcats::fct_infreq之外,由
@HolgerBrandl,有forcats::fct_rev,它颠倒了因子的顺序。
theTable <- data.frame(
Position=
c("Zoalkeeper", "Zoalkeeper", "Defense",
"Defense", "Defense", "Striker"),
Name=c("James", "Frank","Jean",
"Steve","John", "Tim"))
p1 <- ggplot(theTable, aes(x = Position)) + geom_bar()
p2 <- ggplot(theTable, aes(x = fct_infreq(Position))) + geom_bar()
p3 <- ggplot(theTable, aes(x = fct_rev(fct_infreq(Position)))) + geom_bar()
gridExtra::grid.arrange(p1, p2, p3, nrow=3)