如何在以下列表中搜索包含字符串“abc”的项目?
xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
以下检查“abc”是否在列表中,但未检测到“abc-123”和“abc-456”:
if 'abc' in xs:
如何在以下列表中搜索包含字符串“abc”的项目?
xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
以下检查“abc”是否在列表中,但未检测到“abc-123”和“abc-456”:
if 'abc' in xs:
当前回答
def find_dog(new_ls):
splt = new_ls.split()
if 'dog' in splt:
print("True")
else:
print('False')
find_dog("Is there a dog here?")
其他回答
def find_dog(new_ls):
splt = new_ls.split()
if 'dog' in splt:
print("True")
else:
print('False')
find_dog("Is there a dog here?")
我是Python新手。我得到了下面的代码,使其易于理解:
my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
for item in my_list:
if 'abc' in item:
print(item)
要检查列表中任何字符串中是否存在“abc”,请执行以下操作:
xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
if any("abc" in s for s in xs):
...
要获取包含“abc”的所有项目:
matching = [s for s in xs if "abc" in s]
x = 'aaa'
L = ['aaa-12', 'bbbaaa', 'cccaa']
res = [y for y in L if x in y]
for item in my_list:
if item.find("abc") != -1:
print item