如果要获取多个子字符串的数据列表

你可以这样改

some_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
# select element where "abc" or "ghi" is included
find_1 = "abc"
find_2 = "ghi"
result = [element for element in some_list if find_1 in element or find_2 in element] 
# Output ['abc-123', 'ghi-789', 'abc-456']

我需要与以下匹配项对应的列表索引：

lst=['abc-123', 'def-456', 'ghi-789', 'abc-456']

[n for n, x in enumerate(lst) if 'abc' in x]

输出

[0, 3]

使用Pythons字符串类的__contains__（）方法。：

a = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
for i in a:
    if i.__contains__("abc") :
        print(i, " is containing")

要检查列表中任何字符串中是否存在“abc”，请执行以下操作：

xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']

if any("abc" in s for s in xs):
    ...

要获取包含“abc”的所有项目：

matching = [s for s in xs if "abc" in s]

使用筛选器获取具有“abc”的所有元素：

>>> xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
>>> list(filter(lambda x: 'abc' in x, xs))
['abc-123', 'abc-456']

还可以使用列表理解：

>>> [x for x in xs if 'abc' in x]

我是Python新手。我得到了下面的代码，使其易于理解：

my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
for item in my_list:
    if 'abc' in item:
       print(item)