如果要获取多个子字符串的数据列表

你可以这样改

some_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
# select element where "abc" or "ghi" is included
find_1 = "abc"
find_2 = "ghi"
result = [element for element in some_list if find_1 in element or find_2 in element] 
# Output ['abc-123', 'ghi-789', 'abc-456']

问题：给出abc的信息

a = ['abc-123', 'def-456', 'ghi-789', 'abc-456']


aa = [ string for string in a if  "abc" in string]
print(aa)


Output =>  ['abc-123', 'abc-456']

如果您只需要知道“abc”是否在其中一项中，这是最短的方法：

if 'abc' in str(my_list):

注意：这假设“abc”是字母数字文本。如果“abc”可能只是一个特殊字符（即[]”，），请不要使用它。

将nan添加到列表中，以下内容适用于我：

some_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456',np.nan]
any([i for i in [x for x in some_list if str(x) != 'nan'] if "abc" in i])

mylist=['abc','def','ghi','abc']

pattern=re.compile(r'abc') 

pattern.findall(mylist)

x = 'aaa'
L = ['aaa-12', 'bbbaaa', 'cccaa']
res = [y for y in L if x in y]