如何在以下列表中搜索包含字符串“abc”的项目?
xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
以下检查“abc”是否在列表中,但未检测到“abc-123”和“abc-456”:
if 'abc' in xs:
如何在以下列表中搜索包含字符串“abc”的项目?
xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
以下检查“abc”是否在列表中,但未检测到“abc-123”和“abc-456”:
if 'abc' in xs:
当前回答
我需要与以下匹配项对应的列表索引:
lst=['abc-123', 'def-456', 'ghi-789', 'abc-456']
[n for n, x in enumerate(lst) if 'abc' in x]
输出
[0, 3]
其他回答
x = 'aaa'
L = ['aaa-12', 'bbbaaa', 'cccaa']
res = [y for y in L if x in y]
def find_dog(new_ls):
splt = new_ls.split()
if 'dog' in splt:
print("True")
else:
print('False')
find_dog("Is there a dog here?")
我需要与以下匹配项对应的列表索引:
lst=['abc-123', 'def-456', 'ghi-789', 'abc-456']
[n for n, x in enumerate(lst) if 'abc' in x]
输出
[0, 3]
如果要获取多个子字符串的数据列表
你可以这样改
some_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
# select element where "abc" or "ghi" is included
find_1 = "abc"
find_2 = "ghi"
result = [element for element in some_list if find_1 in element or find_2 in element]
# Output ['abc-123', 'ghi-789', 'abc-456']
要检查列表中任何字符串中是否存在“abc”,请执行以下操作:
xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
if any("abc" in s for s in xs):
...
要获取包含“abc”的所有项目:
matching = [s for s in xs if "abc" in s]