如何在以下列表中搜索包含字符串“abc”的项目?

xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']

以下检查“abc”是否在列表中,但未检测到“abc-123”和“abc-456”:

if 'abc' in xs:

当前回答

要检查列表中任何字符串中是否存在“abc”,请执行以下操作:

xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']

if any("abc" in s for s in xs):
    ...

要获取包含“abc”的所有项目:

matching = [s for s in xs if "abc" in s]

其他回答

for item in my_list:
    if item.find("abc") != -1:
        print item
mylist=['abc','def','ghi','abc']

pattern=re.compile(r'abc') 

pattern.findall(mylist)
x = 'aaa'
L = ['aaa-12', 'bbbaaa', 'cccaa']
res = [y for y in L if x in y]

将nan添加到列表中,以下内容适用于我:

some_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456',np.nan]
any([i for i in [x for x in some_list if str(x) != 'nan'] if "abc" in i])

我是Python新手。我得到了下面的代码,使其易于理解:

my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
for item in my_list:
    if 'abc' in item:
       print(item)