如何在以下列表中搜索包含字符串“abc”的项目?
xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
以下检查“abc”是否在列表中,但未检测到“abc-123”和“abc-456”:
if 'abc' in xs:
如何在以下列表中搜索包含字符串“abc”的项目?
xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
以下检查“abc”是否在列表中,但未检测到“abc-123”和“abc-456”:
if 'abc' in xs:
当前回答
要检查列表中任何字符串中是否存在“abc”,请执行以下操作:
xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
if any("abc" in s for s in xs):
...
要获取包含“abc”的所有项目:
matching = [s for s in xs if "abc" in s]
其他回答
for item in my_list:
if item.find("abc") != -1:
print item
mylist=['abc','def','ghi','abc']
pattern=re.compile(r'abc')
pattern.findall(mylist)
x = 'aaa'
L = ['aaa-12', 'bbbaaa', 'cccaa']
res = [y for y in L if x in y]
将nan添加到列表中,以下内容适用于我:
some_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456',np.nan]
any([i for i in [x for x in some_list if str(x) != 'nan'] if "abc" in i])
我是Python新手。我得到了下面的代码,使其易于理解:
my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
for item in my_list:
if 'abc' in item:
print(item)