这对于普通哈希来说很简单
{:a => "a", :b => "b"}
这就意味着
"a=a&b=b"
但是你怎么处理更复杂的东西，比如
{:a => "a", :b => ["c", "d", "e"]}
这应该转化为
"a=a&b[0]=c&b[1]=d&b[2]=e"
或者更糟的是，(该怎么做)像这样的事情:
{:a => "a", :b => [{:c => "c", :d => "d"}, {:e => "e", :f => "f"}]
非常感谢你的帮助!
当前回答
如果你只需要支持简单的ASCII键/值查询字符串，这里有一个简短而甜蜜的语句:
hash = {"foo" => "bar", "fooz" => 123}
# => {"foo"=>"bar", "fooz"=>123}
query_string = hash.to_a.map { |x| "#{x[0]}=#{x[1]}" }.join("&")
# => "foo=bar&fooz=123"
其他回答
2.6.3 :001 > hash = {:a => "a", :b => ["c", "d", "e"]}
=> {:a=>"a", :b=>["c", "d", "e"]}
2.6.3 :002 > hash.to_a.map { |x| "#{x[0]}=#{x[1].class == Array ? x[1].join(",") : x[1]}"
}.join("&")
=> "a=a&b=c,d,e"
{:a=>"a", :b=>"b", :c=>"c"}.map{ |x,v| "#{x}=#{v}" }.reduce{|x,v| "#{x}&#{v}" }
"a=a&b=b&c=c"
还有另一种方法。对于简单的查询。
如果你只需要支持简单的ASCII键/值查询字符串，这里有一个简短而甜蜜的语句:
hash = {"foo" => "bar", "fooz" => 123}
# => {"foo"=>"bar", "fooz"=>123}
query_string = hash.to_a.map { |x| "#{x[0]}=#{x[1]}" }.join("&")
# => "foo=bar&fooz=123"
require 'uri'
class Hash
def to_query_hash(key)
reduce({}) do |h, (k, v)|
new_key = key.nil? ? k : "#{key}[#{k}]"
v = Hash[v.each_with_index.to_a.map(&:reverse)] if v.is_a?(Array)
if v.is_a?(Hash)
h.merge!(v.to_query_hash(new_key))
else
h[new_key] = v
end
h
end
end
def to_query(key = nil)
URI.encode_www_form(to_query_hash(key))
end
end
2.4.2 :019 > {:a => "a", :b => "b"}.to_query_hash(nil)
=> {:a=>"a", :b=>"b"}
2.4.2 :020 > {:a => "a", :b => "b"}.to_query
=> "a=a&b=b"
2.4.2 :021 > {:a => "a", :b => ["c", "d", "e"]}.to_query_hash(nil)
=> {:a=>"a", "b[0]"=>"c", "b[1]"=>"d", "b[2]"=>"e"}
2.4.2 :022 > {:a => "a", :b => ["c", "d", "e"]}.to_query
=> "a=a&b%5B0%5D=c&b%5B1%5D=d&b%5B2%5D=e"
class Hash
def to_params
params = ''
stack = []
each do |k, v|
if v.is_a?(Hash)
stack << [k,v]
elsif v.is_a?(Array)
stack << [k,Hash.from_array(v)]
else
params << "#{k}=#{v}&"
end
end
stack.each do |parent, hash|
hash.each do |k, v|
if v.is_a?(Hash)
stack << ["#{parent}[#{k}]", v]
else
params << "#{parent}[#{k}]=#{v}&"
end
end
end
params.chop!
params
end
def self.from_array(array = [])
h = Hash.new
array.size.times do |t|
h[t] = array[t]
end
h
end
end
