我需要从一个相当大的SQL Server表(即300,000+行)中删除重复的行。
当然,由于RowID标识字段的存在,这些行不会完全重复。
MyTable
RowID int not null identity(1,1) primary key,
Col1 varchar(20) not null,
Col2 varchar(2048) not null,
Col3 tinyint not null
我该怎么做呢?
我需要从一个相当大的SQL Server表(即300,000+行)中删除重复的行。
当然,由于RowID标识字段的存在,这些行不会完全重复。
MyTable
RowID int not null identity(1,1) primary key,
Col1 varchar(20) not null,
Col2 varchar(2048) not null,
Col3 tinyint not null
我该怎么做呢?
当前回答
获取重复的行:
SELECT
name, email, COUNT(*)
FROM
users
GROUP BY
name, email
HAVING COUNT(*) > 1
删除重复的行。
DELETE users
WHERE rowid NOT IN
(SELECT MIN(rowid)
FROM users
GROUP BY name, email);
其他回答
DELETE
FROM MyTable
WHERE NOT EXISTS (
SELECT min(RowID)
FROM Mytable
WHERE (SELECT RowID
FROM Mytable
GROUP BY Col1, Col2, Col3
))
);
我更喜欢CTE从sql server表中删除重复的行
强烈推荐阅读本文::http://codaffection.com/sql-server-article/delete-duplicate-rows-in-sql-server/
保持原创性
WITH CTE AS
(
SELECT *,ROW_NUMBER() OVER (PARTITION BY col1,col2,col3 ORDER BY col1,col2,col3) AS RN
FROM MyTable
)
DELETE FROM CTE WHERE RN<>1
不保留原创
WITH CTE AS
(SELECT *,R=RANK() OVER (ORDER BY col1,col2,col3)
FROM MyTable)
DELETE CTE
WHERE R IN (SELECT R FROM CTE GROUP BY R HAVING COUNT(*)>1)
我想这会很有帮助。这里,ROW_NUMBER() OVER(分区由res1。Title ORDER BY res1.Id)作为num来区分重复的行。
delete FROM
(SELECT res1.*,ROW_NUMBER() OVER(PARTITION BY res1.Title ORDER BY res1.Id)as num
FROM
(select * from [dbo].[tbl_countries])as res1
)as res2
WHERE res2.num > 1
在微软支持网站上有一篇关于删除重复文件的好文章。这是相当保守的——他们让你在不同的步骤中做所有的事情——但它应该适用于大的表格。
在过去,我使用了自连接来实现这一点,尽管它可能会用一个HAVING子句来美化:
DELETE dupes
FROM MyTable dupes, MyTable fullTable
WHERE dupes.dupField = fullTable.dupField
AND dupes.secondDupField = fullTable.secondDupField
AND dupes.uniqueField > fullTable.uniqueField
如果重复行的所有列都是相同的,那么下面的查询可以用来删除重复的记录。
SELECT DISTINCT * INTO #TemNewTable FROM #OriginalTable
TRUNCATE TABLE #OriginalTable
INSERT INTO #OriginalTable SELECT * FROM #TemNewTable
DROP TABLE #TemNewTable