我想提取一个字符串中包含的所有数字。正则表达式和isdigit()方法哪个更适合这个目的?

例子:

line = "hello 12 hi 89"

结果:

[12, 89]

当前回答

# extract numbers from garbage string:
s = '12//n,_@#$%3.14kjlw0xdadfackvj1.6e-19&*ghn334'
newstr = ''.join((ch if ch in '0123456789.-e' else ' ') for ch in s)
listOfNumbers = [float(i) for i in newstr.split()]
print(listOfNumbers)
[12.0, 3.14, 0.0, 1.6e-19, 334.0]

其他回答

str1 = "There are 2 apples for 4 persons"

# printing original string 
print("The original string : " + str1) # The original string : There are 2 apples for 4 persons

# using List comprehension + isdigit() +split()
# getting numbers from string 
res = [int(i) for i in str1.split() if i.isdigit()]

print("The numbers list is : " + str(res)) # The numbers list is : [2, 4]

此答案还包含数字在字符串中为浮点数的情况

def get_first_nbr_from_str(input_str):
    '''
    :param input_str: strings that contains digit and words
    :return: the number extracted from the input_str
    demo:
    'ab324.23.123xyz': 324.23
    '.5abc44': 0.5
    '''
    if not input_str and not isinstance(input_str, str):
        return 0
    out_number = ''
    for ele in input_str:
        if (ele == '.' and '.' not in out_number) or ele.isdigit():
            out_number += ele
        elif out_number:
            break
    return float(out_number)

我一直在寻找一个解决方案来去除字符串的面具,特别是从巴西的电话号码,这篇文章没有回答,但启发了我。这是我的解决方案:

>>> phone_number = '+55(11)8715-9877'
>>> ''.join([n for n in phone_number if n.isdigit()])
'551187159877'

使用下面的正则表达式是一种方法

lines = "hello 12 hi 89"
import re
output = []
#repl_str = re.compile('\d+.?\d*')
repl_str = re.compile('^\d+$')
#t = r'\d+.?\d*'
line = lines.split()
for word in line:
        match = re.search(repl_str, word)
        if match:
            output.append(float(match.group()))
print (output)

和findall Re.findall (r'\d+', "hello 12 hi 89")

['12', '89']

re.findall(r'\b\d+\b', "hello 12 hi 89 33F AC 777")

['12', '89', '777']

@jmnas,我喜欢你的答案,但它没有找到浮动。我正在编写一个脚本来解析前往CNC铣床的代码,需要找到可以是整数或浮点数的X和Y维度,所以我将您的代码改编为以下内容。这就找到了int, float值为正和负。仍然没有找到十六进制格式的值,但你可以添加“x”和“A”通过“F”到num_char元组,我认为它会解析像“0x23AC”这样的东西。

s = 'hello X42 I\'m a Y-32.35 string Z30'
xy = ("X", "Y")
num_char = (".", "+", "-")

l = []

tokens = s.split()
for token in tokens:

    if token.startswith(xy):
        num = ""
        for char in token:
            # print(char)
            if char.isdigit() or (char in num_char):
                num = num + char

        try:
            l.append(float(num))
        except ValueError:
            pass

print(l)