要创建一个带有公共方法的JavaScript类,我可以这样做:

function Restaurant() {}

Restaurant.prototype.buy_food = function(){
   // something here
}

Restaurant.prototype.use_restroom = function(){
   // something here
}

这样,我类的用户就可以:

var restaurant = new Restaurant();
restaurant.buy_food();
restaurant.use_restroom();

如何创建一个私有方法,可以由buy_food和use_restroom方法调用,但不能由类的用户外部调用?

换句话说,我希望我的方法实现能够做到:

Restaurant.prototype.use_restroom = function() {
   this.private_stuff();
}

但这是行不通的:

var r = new Restaurant();
r.private_stuff();

如何将private_stuff定义为私有方法,使两者都成立?

我读过Doug Crockford的文章几次,但它似乎不像“私有”方法可以被公共方法调用,而“特权”方法可以被外部调用。


当前回答

ES2021 / ES12 -私有方法

私有方法名以哈希前缀#开头,并且只能在定义它的类内部访问。

class Restaurant {

  // private method
  #private_stuff() {
    console.log("private stuff");
  }

  // public method
  buy_food() {
    this.#private_stuff();
  }

};

const restaurant = new Restaurant();
restaurant.buy_food(); // "private stuff";
restaurant.private_stuff(); // Uncaught TypeError: restaurant.private_stuff is not a function

其他回答

ES2021 / ES12 -私有方法

私有方法名以哈希前缀#开头,并且只能在定义它的类内部访问。

class Restaurant {

  // private method
  #private_stuff() {
    console.log("private stuff");
  }

  // public method
  buy_food() {
    this.#private_stuff();
  }

};

const restaurant = new Restaurant();
restaurant.buy_food(); // "private stuff";
restaurant.private_stuff(); // Uncaught TypeError: restaurant.private_stuff is not a function

别啰嗦了。这是Javascript。使用命名约定。

在es6类工作了多年之后,我最近开始了一个es5项目(使用requireJS,它看起来已经非常冗长了)。我已经反复研究了这里提到的所有策略,基本上都可以归结为使用命名约定:

Javascript doesn't have scope keywords like private. Other developers entering Javascript will know this upfront. Therefore, a simple naming convention is more than sufficient. A simple naming convention of prefixing with an underscore solves the problem of both private properties and private methods. Let's take advantage of the Prototype for speed reasons, but lets not get anymore verbose than that. Let's try to keep the es5 "class" looking as closely to what we might expect in other backend languages (and treat every file as a class, even if we don't need to return an instance). Let's demonstrate with a more realistic module situation (we'll use old es5 and old requireJs).

my-tooltip.js

    define([
        'tooltip'
    ],
    function(
        tooltip
    ){

        function MyTooltip() {
            // Later, if needed, we can remove the underscore on some
            // of these (make public) and allow clients of our class
            // to set them.
            this._selector = "#my-tooltip"
            this._template = 'Hello from inside my tooltip!';
            this._initTooltip();
        }

        MyTooltip.prototype = {
            constructor: MyTooltip,

            _initTooltip: function () {
                new tooltip.tooltip(this._selector, {
                    content: this._template,
                    closeOnClick: true,
                    closeButton: true
                });
            }
        }

        return {
            init: function init() {
               new MyTooltip();  // <-- Our constructor adds our tooltip to the DOM so not much we need to do after instantiation.
            }

            // You could instead return a new instantiation, 
            // if later you do more with this class.
            /* 
            create: function create() {
               return new MyTooltip();
            }
            */
        }
    });

你可以这样做,但缺点是它不能成为原型的一部分:

function Restaurant() {
    var myPrivateVar;

    var private_stuff = function() {  // Only visible inside Restaurant()
        myPrivateVar = "I can set this here!";
    }

    this.use_restroom = function() {  // use_restroom is visible to all
        private_stuff();
    }

    this.buy_food = function() {   // buy_food is visible to all
        private_stuff();
    }
}

你可以像这样模拟私有方法:

function Restaurant() {
}

Restaurant.prototype = (function() {
    var private_stuff = function() {
        // Private code here
    };

    return {

        constructor:Restaurant,

        use_restroom:function() {
            private_stuff();
        }

    };
})();

var r = new Restaurant();

// This will work:
r.use_restroom();

// This will cause an error:
r.private_stuff();

更多关于此技术的信息,请访问:http://webreflection.blogspot.com/2008/04/natural-javascript-private-methods.html

老问题,但这是一个相当简单的任务,可以用核心JS正确解决…没有ES6的Class抽象。事实上,据我所知,类抽象甚至不能解决这个问题。

我们既可以使用老的构造函数,也可以使用Object.create()更好地完成这项工作。让我们先从构造函数开始。这本质上是一个与georgebrock的答案相似的解决方案,georgebrock的答案受到了批评,因为所有由Restaurant构造函数创建的餐厅都将具有相同的私有方法。我会努力克服这个限制。

function restaurantFactory(name,menu){ function Restaurant(name){ this.name = name; } function prototypeFactory(menu){ // This is a private function function calculateBill(item){ return menu[item] || 0; } // This is the prototype to be return { constructor: Restaurant , askBill : function(...items){ var cost = items.reduce((total,item) => total + calculateBill(item) ,0) return "Thank you for dining at " + this.name + ". Total is: " + cost + "\n" } , callWaiter : function(){ return "I have just called the waiter at " + this.name + "\n"; } } } Restaurant.prototype = prototypeFactory(menu); return new Restaurant(name,menu); } var menu = { water: 1 , coke : 2 , beer : 3 , beef : 15 , rice : 2 }, name = "Silver Scooop", rest = restaurantFactory(name,menu); console.log(rest.callWaiter()); console.log(rest.askBill("beer", "beef"));

现在显然我们不能从外部访问菜单,但我们可以很容易地重命名餐厅的name属性。

这也可以用object .create()来完成,在这种情况下,我们跳过构造函数,简单地像var rest = object .create(prototypeFactory(menu))那样做,然后像rest.name = name那样将name属性添加到rest对象。