我有两个JavaScript数组:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
我希望输出为:
var array3 = ["Vijendra","Singh","Shakya"];
输出数组应删除重复的单词。
如何在JavaScript中合并两个数组,以便从每个数组中只获得唯一的项目,其顺序与它们插入原始数组的顺序相同?
我有两个JavaScript数组:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
我希望输出为:
var array3 = ["Vijendra","Singh","Shakya"];
输出数组应删除重复的单词。
如何在JavaScript中合并两个数组,以便从每个数组中只获得唯一的项目,其顺序与它们插入原始数组的顺序相同?
当前回答
您可以使用loadash unionWith-_.unionWith(〔arrays〕,〔comparator〕)
此方法类似于_.union,只是它接受被调用来比较数组元素的比较器。结果值从出现该值的第一个数组中选择。比较器由两个参数调用:(arrVal,othVal)。
var array1=[“Vijendra”,“Singh”];var array2=[“Singh”,“Shakya”];var array3=_.unionWith(array1,array2,_.isEqual);console.log(array3);<script src=“https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js“></script>
其他回答
const array3 = array1.filter(t=> !array2.includes(t)).concat(array2)
对于ES6,只有一行:
a = [1, 2, 3, 4]
b = [4, 5]
[...new Set(a.concat(b))] // [1, 2, 3, 4, 5]
可以使用新的“集”删除重复
[...new Set([...array1 ,...array2])]
作为LiraNuna的一部分的单线解决方案:
let array1 = ["Vijendra","Singh"];
let array2 = ["Singh", "Shakya"];
// Merges both arrays
let array3 = array1.concat(array2);
//REMOVE DUPLICATE
let removeDuplicate = [...new Set(array3)];
console.log(removeDuplicate);
ES6提供了一种单线解决方案,通过使用析构函数和集合来合并多个数组而不重复。
const array1 = ['a','b','c'];
const array2 = ['c','c','d','e'];
const array3 = [...new Set([...array1,...array2])];
console.log(array3); // ["a", "b", "c", "d", "e"]