我有两个JavaScript数组：
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
我希望输出为：
var array3 = ["Vijendra","Singh","Shakya"];
输出数组应删除重复的单词。
如何在JavaScript中合并两个数组，以便从每个数组中只获得唯一的项目，其顺序与它们插入原始数组的顺序相同？
当前回答
新解决方案（使用Array.prototype.indexOf和Array.prototype.cocat）：
Array.prototype.uniqueMerge = function( a ) {
for ( var nonDuplicates = [], i = 0, l = a.length; i<l; ++i ) {
if ( this.indexOf( a[i] ) === -1 ) {
nonDuplicates.push( a[i] );
}
}
return this.concat( nonDuplicates )
};
用法：
>>> ['Vijendra', 'Singh'].uniqueMerge(['Singh', 'Shakya'])
["Vijendra", "Singh", "Shakya"]
Array.prototype.indexOf（用于internet explorer）：
Array.prototype.indexOf = Array.prototype.indexOf || function(elt)
{
var len = this.length >>> 0;
var from = Number(arguments[1]) || 0;
from = (from < 0) ? Math.ceil(from): Math.floor(from);
if (from < 0)from += len;
for (; from < len; from++)
{
if (from in this && this[from] === elt)return from;
}
return -1;
};
其他回答
使用reduce func查看的另一种方法：
function mergeDistinct(arResult, candidate){
if (-1 == arResult.indexOf(candidate)) {
arResult.push(candidate);
}
return arResult;
}
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
var arMerge = [];
arMerge = array1.reduce(mergeDistinct, arMerge);
arMerge = array2.reduce(mergeDistinct, arMerge);//["Vijendra","Singh","Shakya"];
带过滤器的最简单解决方案：
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
var mergedArrayWithoutDuplicates = array1.concat(
array2.filter(seccondArrayItem => !array1.includes(seccondArrayItem))
);
新解决方案（使用Array.prototype.indexOf和Array.prototype.cocat）：
Array.prototype.uniqueMerge = function( a ) {
for ( var nonDuplicates = [], i = 0, l = a.length; i<l; ++i ) {
if ( this.indexOf( a[i] ) === -1 ) {
nonDuplicates.push( a[i] );
}
}
return this.concat( nonDuplicates )
};
用法：
>>> ['Vijendra', 'Singh'].uniqueMerge(['Singh', 'Shakya'])
["Vijendra", "Singh", "Shakya"]
Array.prototype.indexOf（用于internet explorer）：
Array.prototype.indexOf = Array.prototype.indexOf || function(elt)
{
var len = this.length >>> 0;
var from = Number(arguments[1]) || 0;
from = (from < 0) ? Math.ceil(from): Math.floor(from);
if (from < 0)from += len;
for (; from < len; from++)
{
if (from in this && this[from] === elt)return from;
}
return -1;
};
这是我需要合并（或返回两个数组的并集）时使用的函数。
var union = function (a, b) {
for (var i = 0; i < b.length; i++)
if (a.indexOf(b[i]) === -1)
a.push(b[i]);
return a;
};
var a = [1, 2, 3, 'a', 'b', 'c'];
var b = [2, 3, 4, 'b', 'c', 'd'];
a = union(a, b);
//> [1, 2, 3, "a", "b", "c", 4, "d"]
var array1 = ["Vijendra", "Singh"];
var array2 = ["Singh", "Shakya"];
var array3 = union(array1, array2);
//> ["Vijendra", "Singh", "Shakya"]
最佳解决方案。。。
您可以直接在浏览器控制台中点击。。。
无重复项
a = [1, 2, 3];
b = [3, 2, 1, "prince"];
a.concat(b.filter(function(el) {
return a.indexOf(el) === -1;
}));
具有重复项
["prince", "asish", 5].concat(["ravi", 4])
如果你想要没有重复，你可以从这里尝试一个更好的解决方案-大喊代码。
[1, 2, 3].concat([3, 2, 1, "prince"].filter(function(el) {
return [1, 2, 3].indexOf(el) === -1;
}));
在Chrome浏览器控制台上试用
f12 > console
输出：
["prince", "asish", 5, "ravi", 4]
[1, 2, 3, "prince"]
