我有两个JavaScript数组:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
我希望输出为:
var array3 = ["Vijendra","Singh","Shakya"];
输出数组应删除重复的单词。
如何在JavaScript中合并两个数组,以便从每个数组中只获得唯一的项目,其顺序与它们插入原始数组的顺序相同?
我有两个JavaScript数组:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
我希望输出为:
var array3 = ["Vijendra","Singh","Shakya"];
输出数组应删除重复的单词。
如何在JavaScript中合并两个数组,以便从每个数组中只获得唯一的项目,其顺序与它们插入原始数组的顺序相同?
当前回答
Array.prototype.union = function (other_array) {
/* you can include a test to check whether other_array really is an array */
other_array.forEach(function(v) { if(this.indexOf(v) === -1) {this.push(v);}}, this);
}
其他回答
可以使用新的“集”删除重复
[...new Set([...array1 ,...array2])]
只需使用Undercore.js的=>uniq即可实现:
array3 = _.uniq(array1.concat(array2))
console.log(array3)
它将印刷[“Vijendra”、“Singh”、“Shakya”]。
Use:
Array.prototype.merge = function (arr) {
var key;
for(key in arr)
this[key] = arr[key];
};
使用集合(ECMAScript 2015),将非常简单:
const array1=[“Vijendra”,“Singh”];const array2=[“Singh”,“Shakya”];console.log(Array.from(new Set(array1.concat(array2))));
之前写过同样的原因(适用于任意数量的数组):
/**
* Returns with the union of the given arrays.
*
* @param Any amount of arrays to be united.
* @returns {array} The union array.
*/
function uniteArrays()
{
var union = [];
for (var argumentIndex = 0; argumentIndex < arguments.length; argumentIndex++)
{
eachArgument = arguments[argumentIndex];
if (typeof eachArgument !== 'array')
{
eachArray = eachArgument;
for (var index = 0; index < eachArray.length; index++)
{
eachValue = eachArray[index];
if (arrayHasValue(union, eachValue) == false)
union.push(eachValue);
}
}
}
return union;
}
function arrayHasValue(array, value)
{ return array.indexOf(value) != -1; }