我有两个JavaScript数组:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
我希望输出为:
var array3 = ["Vijendra","Singh","Shakya"];
输出数组应删除重复的单词。
如何在JavaScript中合并两个数组,以便从每个数组中只获得唯一的项目,其顺序与它们插入原始数组的顺序相同?
我有两个JavaScript数组:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
我希望输出为:
var array3 = ["Vijendra","Singh","Shakya"];
输出数组应删除重复的单词。
如何在JavaScript中合并两个数组,以便从每个数组中只获得唯一的项目,其顺序与它们插入原始数组的顺序相同?
当前回答
Array.prototype.union = function (other_array) {
/* you can include a test to check whether other_array really is an array */
other_array.forEach(function(v) { if(this.indexOf(v) === -1) {this.push(v);}}, this);
}
其他回答
Array.prototype.merge = function(/* variable number of arrays */){
for(var i = 0; i < arguments.length; i++){
var array = arguments[i];
for(var j = 0; j < array.length; j++){
if(this.indexOf(array[j]) === -1) {
this.push(array[j]);
}
}
}
return this;
};
一个更好的数组合并函数。
如果您合并对象数组,请考虑使用lodash UnionBy函数,它允许您设置自定义谓词比较对象:
import { unionBy } from 'lodash';
const a = [{a: 1, b: 2}];
const b = [{a: 1, b: 3}];
const c = [{a: 2, b: 4}];
const result = UnionBy(a,b,c, x => x.a);
结果是:〔{a:1;b:2},{a:2;b:4}〕
结果中使用了来自数组的第一个传递匹配
之前写过同样的原因(适用于任意数量的数组):
/**
* Returns with the union of the given arrays.
*
* @param Any amount of arrays to be united.
* @returns {array} The union array.
*/
function uniteArrays()
{
var union = [];
for (var argumentIndex = 0; argumentIndex < arguments.length; argumentIndex++)
{
eachArgument = arguments[argumentIndex];
if (typeof eachArgument !== 'array')
{
eachArray = eachArgument;
for (var index = 0; index < eachArray.length; index++)
{
eachValue = eachArray[index];
if (arrayHasValue(union, eachValue) == false)
union.push(eachValue);
}
}
}
return union;
}
function arrayHasValue(array, value)
{ return array.indexOf(value) != -1; }
为什么不使用对象?看起来你在尝试建立一套模型。然而,这并不能维持秩序。
var set1 = {"Vijendra":true, "Singh":true}
var set2 = {"Singh":true, "Shakya":true}
// Merge second object into first
function merge(set1, set2){
for (var key in set2){
if (set2.hasOwnProperty(key))
set1[key] = set2[key]
}
return set1
}
merge(set1, set2)
// Create set from array
function setify(array){
var result = {}
for (var item in array){
if (array.hasOwnProperty(item))
result[array[item]] = true
}
return result
}
作为LiraNuna的一部分的单线解决方案:
let array1 = ["Vijendra","Singh"];
let array2 = ["Singh", "Shakya"];
// Merges both arrays
let array3 = array1.concat(array2);
//REMOVE DUPLICATE
let removeDuplicate = [...new Set(array3)];
console.log(removeDuplicate);