我怎么能看到当前的urlpatterns“反向”正在寻找?

我在一个视图中调用了逆向,我认为这个论证应该成立,但实际上并不成立。有什么办法能让我知道为什么我的图案没有?


当前回答

又一次改编自凯撒·卡纳萨的发电机魔法。这可以添加到你的应用程序的yourapp/management/commands/dumpurls.py目录中,这样它就可以作为management.py中的子命令来访问。

注意:我添加了一行,以确保它只过滤你的应用程序。如果需要其他url,则相应地更新或删除它。

作为management.py子命令

部署路径:yourapp/management/commands/dumpurls.py

from django.core.management.base import BaseCommand, CommandError
from django.conf import settings
from django.urls import URLPattern, URLResolver

def list_urls(lis, acc=None):

    if acc is None:
        acc = []
    if not lis:
        return
    l = lis[0]
    if isinstance(l, URLPattern):
        yield acc + [str(l.pattern),l.name]
    elif isinstance(l, URLResolver):
        yield from list_urls(l.url_patterns, acc + [str(l.pattern)])
    yield from list_urls(lis[1:], acc)

class Command(BaseCommand):
    help = 'List all URLs from the urlconf'

    def handle(self, *args, **options):

        urlconf = __import__(settings.ROOT_URLCONF, {}, {}, [''])

        records, glen, nlen = [], 0, 0

        for p in list_urls(urlconf.urlpatterns):
            record = [''.join(p[:2]), p[2]]

            # Update me, or add an argument
            if record[0].startswith('yourapp'):

                clen = len(record[0])
                if clen > glen: glen = clen

                clen = len(record[1])
                if clen > nlen: nlen = clen
                
                records.append(record)


        self.stdout.write('{:-<{width}}'.format('',width=glen+nlen))
        self.stdout.write('{:<{glen}}Name'.format('Path',glen=glen+4))
        self.stdout.write('{:-<{width}}'.format('',width=glen+nlen))
        for record in records:
            self.stdout.write('{path:<{glen}}{name}'.format(path=record[0],
                name=record[1],
                glen=glen+4))
        self.stdout.write('{:-<{width}}'.format('',width=glen+nlen))

样例输出

(env) django@dev:myproj~> ./manage.py dumpurls
-------------------------------------------------------------------------------------------------------
Path                                                                        Name
-------------------------------------------------------------------------------------------------------
yourapp/^api-key/$                                                          api-key-list
yourapp/^api-key\.(?P<format>[a-z0-9]+)/?$                                  api-key-list
yourapp/^attacks/$                                                          attack-list
yourapp/^attacks\.(?P<format>[a-z0-9]+)/?$                                  attack-list
yourapp/^attack-histories/$                                                 attackhistory-list
yourapp/^attack-histories\.(?P<format>[a-z0-9]+)/?$                         attackhistory-list
yourapp/^files/$                                                            file-list
yourapp/^files\.(?P<format>[a-z0-9]+)/?$                                    file-list
yourapp/^modules/$                                                          module-list
yourapp/^modules\.(?P<format>[a-z0-9]+)/?$                                  module-list

其他回答

只要输入一个你知道不存在的url,服务器就会返回一个错误消息,其中包含一个url模式列表。

例如,如果你在http://localhost:8000/something上运行一个网站

输入

http://localhost:8000/something/blahNonsense,您的服务器将返回url搜索列表并在浏览器中显示它

如果你正在使用DRF,你可以通过从router.get_urls()(在你的Django应用的urls.py文件中)打印特定路由器的urlpatterns来打印所有的URL模式。

打开你的apps urls.py,并在文件底部添加打印语句,这样整个文件看起来就像这样:

import pprint

from django.urls import include, path
from rest_framework import routers

from . import views

router = routers.DefaultRouter()
router.register(r"users", views.UserViewSet, basename="User")
router.register(r"auth", views.AuthenticationView, basename="Auth")
router.register(r"dummy", views.DummyViewSet, basename="Dummy")
router.register("surveys", views.SurveyViewSet, basename="survey")

urlpatterns = [
    path("", include(router.urls)),
]

pprint.pprint(router.get_urls())

然后,这些图案会像这样打印出来:

[<URLPattern '^users/$' [name='User-list']>,
 <URLPattern '^users\.(?P<format>[a-z0-9]+)/?$' [name='User-list']>,
 <URLPattern '^users/admins/$' [name='User-admins']>,
 <URLPattern '^users/admins\.(?P<format>[a-z0-9]+)/?$' [name='User-admins']>,
 <URLPattern '^users/current/$' [name='User-current']>,
 <URLPattern '^users/current\.(?P<format>[a-z0-9]+)/?$' [name='User-current']>,
 <URLPattern '^users/(?P<pk>[^/.]+)/$' [name='User-detail']>,
 <URLPattern '^users/(?P<pk>[^/.]+)\.(?P<format>[a-z0-9]+)/?$' [name='User-detail']>,
 <URLPattern '^auth/login/$' [name='Auth-login']>,
...
]

又一次改编自凯撒·卡纳萨的发电机魔法。这可以添加到你的应用程序的yourapp/management/commands/dumpurls.py目录中,这样它就可以作为management.py中的子命令来访问。

注意:我添加了一行,以确保它只过滤你的应用程序。如果需要其他url,则相应地更新或删除它。

作为management.py子命令

部署路径:yourapp/management/commands/dumpurls.py

from django.core.management.base import BaseCommand, CommandError
from django.conf import settings
from django.urls import URLPattern, URLResolver

def list_urls(lis, acc=None):

    if acc is None:
        acc = []
    if not lis:
        return
    l = lis[0]
    if isinstance(l, URLPattern):
        yield acc + [str(l.pattern),l.name]
    elif isinstance(l, URLResolver):
        yield from list_urls(l.url_patterns, acc + [str(l.pattern)])
    yield from list_urls(lis[1:], acc)

class Command(BaseCommand):
    help = 'List all URLs from the urlconf'

    def handle(self, *args, **options):

        urlconf = __import__(settings.ROOT_URLCONF, {}, {}, [''])

        records, glen, nlen = [], 0, 0

        for p in list_urls(urlconf.urlpatterns):
            record = [''.join(p[:2]), p[2]]

            # Update me, or add an argument
            if record[0].startswith('yourapp'):

                clen = len(record[0])
                if clen > glen: glen = clen

                clen = len(record[1])
                if clen > nlen: nlen = clen
                
                records.append(record)


        self.stdout.write('{:-<{width}}'.format('',width=glen+nlen))
        self.stdout.write('{:<{glen}}Name'.format('Path',glen=glen+4))
        self.stdout.write('{:-<{width}}'.format('',width=glen+nlen))
        for record in records:
            self.stdout.write('{path:<{glen}}{name}'.format(path=record[0],
                name=record[1],
                glen=glen+4))
        self.stdout.write('{:-<{width}}'.format('',width=glen+nlen))

样例输出

(env) django@dev:myproj~> ./manage.py dumpurls
-------------------------------------------------------------------------------------------------------
Path                                                                        Name
-------------------------------------------------------------------------------------------------------
yourapp/^api-key/$                                                          api-key-list
yourapp/^api-key\.(?P<format>[a-z0-9]+)/?$                                  api-key-list
yourapp/^attacks/$                                                          attack-list
yourapp/^attacks\.(?P<format>[a-z0-9]+)/?$                                  attack-list
yourapp/^attack-histories/$                                                 attackhistory-list
yourapp/^attack-histories\.(?P<format>[a-z0-9]+)/?$                         attackhistory-list
yourapp/^files/$                                                            file-list
yourapp/^files\.(?P<format>[a-z0-9]+)/?$                                    file-list
yourapp/^modules/$                                                          module-list
yourapp/^modules\.(?P<format>[a-z0-9]+)/?$                                  module-list

Django 1.8, Python 2.7+ 只需在Shell中运行这些命令。Python manage.py shell并执行以下代码。

from django.conf.urls import RegexURLPattern, RegexURLResolver
from django.core import urlresolvers
urls = urlresolvers.get_resolver(None)

def if_none(value):
    if value:
        return value
    return ''

def print_urls(urls, parent_pattern=None):
    for url in urls.url_patterns:
        if isinstance(url, RegexURLResolver):
            print_urls(url, if_none(parent_pattern) + url.regex.pattern)
        elif isinstance(url, RegexURLPattern):
            print(if_none(parent_pattern) + url.regex.pattern)

print_urls(urls)

django 2.0的极简解决方案

例如,如果你正在寻找installed_apps的第一个应用程序上的url,你可以像这样访问它:

from django.urls import get_resolver
from pprint import pprint

pprint(
    get_resolver().url_patterns[0].url_patterns
)