只要输入一个你知道不存在的url，服务器就会返回一个错误消息，其中包含一个url模式列表。

例如，如果你在http://localhost:8000/something上运行一个网站

输入

http://localhost:8000/something/blahNonsense，您的服务器将返回url搜索列表并在浏览器中显示它

Django >= 2.0解决方案

我测试了这篇文章中的其他答案，它们要么不能与Django 2一起工作。X，不完整或太复杂。因此，以下是我的看法:

from django.conf import settings
from django.urls import URLPattern, URLResolver

urlconf = __import__(settings.ROOT_URLCONF, {}, {}, [''])

def list_urls(lis, acc=None):
    if acc is None:
        acc = []
    if not lis:
        return
    l = lis[0]
    if isinstance(l, URLPattern):
        yield acc + [str(l.pattern)]
    elif isinstance(l, URLResolver):
        yield from list_urls(l.url_patterns, acc + [str(l.pattern)])
    yield from list_urls(lis[1:], acc)

for p in list_urls(urlconf.urlpatterns):
    print(''.join(p))

该代码打印所有url，不像其他解决方案，它将打印完整的路径，而不仅仅是最后一个节点。例如:

admin/
admin/login/
admin/logout/
admin/password_change/
admin/password_change/done/
admin/jsi18n/
admin/r/<int:content_type_id>/<path:object_id>/
admin/auth/group/
admin/auth/group/add/
admin/auth/group/autocomplete/
admin/auth/group/<path:object_id>/history/
admin/auth/group/<path:object_id>/delete/
admin/auth/group/<path:object_id>/change/
admin/auth/group/<path:object_id>/
admin/auth/user/<id>/password/
admin/auth/user/
... etc, etc

在Django 3.0中，这很简单:

from django.urls import get_resolver
print(get_resolver().url_patterns)

指纹: < urltern " >， < urltern '/测试"[另一个名称]>

Django 1.11, Python 2.7.6

cd to_your_django_project Python manage.py shell

然后粘贴以下代码。

from django.conf.urls import RegexURLPattern, RegexURLResolver
from django.core import urlresolvers
urls = urlresolvers.get_resolver()

def if_none(value):
    if value:
        return value
    return ''

def print_urls(urls, parent_pattern=None):
    for url in urls.url_patterns:
        if isinstance(url, RegexURLResolver):
            print_urls(url, if_none(parent_pattern) + url.regex.pattern)
        elif isinstance(url, RegexURLPattern):
            print(if_none(parent_pattern) + url.regex.pattern)

print_urls(urls)

样例输出:

^django-admin/^$
^django-admin/^login/$
^django-admin/^logout/$
^django-admin/^password_change/$
^django-admin/^password_change/done/$
^django-admin/^jsi18n/$
^django-admin/^r/(?P<content_type_id>\d+)/(?P<object_id>.+)/$
^django-admin/^wagtailimages/image/^$
^django-admin/^wagtailimages/image/^add/$
^django-admin/^wagtailimages/image/^(.+)/history/$
^django-admin/^wagtailimages/image/^(.+)/delete/$
^django-admin/^wagtailimages/image/^(.+)/change/$
^django-admin/^wagtailimages/image/^(.+)/$
...

这里有一个快速而肮脏的黑客，只需获得你需要的信息，而不需要修改任何设置。

$ pip install django-extensions
$ python manage.py shell -c 'from django.core.management import call_command; from django_extensions.management.commands.show_urls import Command; call_command(Command())'

这是小猪在逃避@robert的回答。虽然是正确的，但我不想让django扩展成为依赖项，哪怕只是一秒钟。

import subprocces

res = subprocess.run(
    'python manage.py show_urls',
    capture_output=True,
    shell=True,
)
url_list = [
    line.split('\t')[0]
    for line in res.stdout.decode().split('\n')
]