你可以创建一个动态导入来收集项目中每个应用程序的所有URL模式，简单的方法如下:

def get_url_patterns():
    import importlib
    from django.apps import apps

    list_of_all_url_patterns = list()
    for name, app in apps.app_configs.items():
        # you have a directory structure where you should be able to build the correct path
        # my example shows that apps.[app_name].urls is where to look
        mod_to_import = f'apps.{name}.urls'
        try:
            urls = getattr(importlib.import_module(mod_to_import), "urlpatterns")
            list_of_all_url_patterns.extend(urls)
        except ImportError as ex:
            # is an app without urls
            pass

    return list_of_all_url_patterns

List_of_all_url_patterns = get_url_patterns()

我最近使用类似的方法创建了一个模板标记来显示活动导航链接。

django 2.0的极简解决方案

例如，如果你正在寻找installed_apps的第一个应用程序上的url，你可以像这样访问它:

from django.urls import get_resolver
from pprint import pprint

pprint(
    get_resolver().url_patterns[0].url_patterns
)

如果你正在使用DRF，你可以通过从router.get_urls()(在你的Django应用的urls.py文件中)打印特定路由器的urlpatterns来打印所有的URL模式。

打开你的apps urls.py，并在文件底部添加打印语句，这样整个文件看起来就像这样:

import pprint

from django.urls import include, path
from rest_framework import routers

from . import views

router = routers.DefaultRouter()
router.register(r"users", views.UserViewSet, basename="User")
router.register(r"auth", views.AuthenticationView, basename="Auth")
router.register(r"dummy", views.DummyViewSet, basename="Dummy")
router.register("surveys", views.SurveyViewSet, basename="survey")

urlpatterns = [
    path("", include(router.urls)),
]

pprint.pprint(router.get_urls())

然后，这些图案会像这样打印出来:

[<URLPattern '^users/$' [name='User-list']>,
 <URLPattern '^users\.(?P<format>[a-z0-9]+)/?$' [name='User-list']>,
 <URLPattern '^users/admins/$' [name='User-admins']>,
 <URLPattern '^users/admins\.(?P<format>[a-z0-9]+)/?$' [name='User-admins']>,
 <URLPattern '^users/current/$' [name='User-current']>,
 <URLPattern '^users/current\.(?P<format>[a-z0-9]+)/?$' [name='User-current']>,
 <URLPattern '^users/(?P<pk>[^/.]+)/$' [name='User-detail']>,
 <URLPattern '^users/(?P<pk>[^/.]+)\.(?P<format>[a-z0-9]+)/?$' [name='User-detail']>,
 <URLPattern '^auth/login/$' [name='Auth-login']>,
...
]

from django.urls.resolvers import RegexPattern,RoutePattern
from your_main_app import urls

def get_urls():
    url_list = []
    for url in urls.urlpatterns:
        url_list.append(url.pattern._regex) if isinstance(url.pattern, RegexPattern) else url_list.append(url.pattern._route)

    return url_list

这里your_main_app是放置settings.py文件的应用程序名称

Django >= 2.0列表解决方案

领养自@CesarCanassa

from django.conf import settings
from django.urls import URLPattern, URLResolver

URLCONF = __import__(settings.ROOT_URLCONF, {}, {}, [''])

def list_urls(patterns, path=None):
    """ recursive """
    if not path:
        path = []
    result = []
    for pattern in patterns:
        if isinstance(pattern, URLPattern):
            result.append(''.join(path) + str(pattern.pattern))
        elif isinstance(pattern, URLResolver):
            result += list_urls(pattern.url_patterns, path + [str(pattern.pattern)])
    return result

如果你想要一个项目中所有url的列表，首先你需要安装django-extensions

您可以使用命令简单地安装。

pip install django-extensions

有关包goto django-extensions的更多信息

之后，在settings.py文件中的INSTALLED_APPS中添加django_extensions，如下所示:

INSTALLED_APPS = (
...
'django_extensions',
...
)

urls . py的例子:

from django.urls import path, include
from . import views
from . import health_views

urlpatterns = [
    path('get_url_info', views.get_url_func),
    path('health', health_views.service_health_check),
    path('service-session/status', views.service_session_status)
]

然后，在终端上运行任意命令

python manage.py show_urls

or

./manage.py show_urls

基于config urls.py的输出示例:

/get_url_info             django_app.views.get_url_func
/health                   django_app.health_views.service_health_check
/service-session/status   django_app.views.service_session_status

有关更多信息，您可以查看文档。