我怎么能看到当前的urlpatterns“反向”正在寻找?

我在一个视图中调用了逆向,我认为这个论证应该成立,但实际上并不成立。有什么办法能让我知道为什么我的图案没有?


当前回答

Django 1.8, Python 2.7+ 只需在Shell中运行这些命令。Python manage.py shell并执行以下代码。

from django.conf.urls import RegexURLPattern, RegexURLResolver
from django.core import urlresolvers
urls = urlresolvers.get_resolver(None)

def if_none(value):
    if value:
        return value
    return ''

def print_urls(urls, parent_pattern=None):
    for url in urls.url_patterns:
        if isinstance(url, RegexURLResolver):
            print_urls(url, if_none(parent_pattern) + url.regex.pattern)
        elif isinstance(url, RegexURLPattern):
            print(if_none(parent_pattern) + url.regex.pattern)

print_urls(urls)

其他回答

又一次改编自凯撒·卡纳萨的发电机魔法。这可以添加到你的应用程序的yourapp/management/commands/dumpurls.py目录中,这样它就可以作为management.py中的子命令来访问。

注意:我添加了一行,以确保它只过滤你的应用程序。如果需要其他url,则相应地更新或删除它。

作为management.py子命令

部署路径:yourapp/management/commands/dumpurls.py

from django.core.management.base import BaseCommand, CommandError
from django.conf import settings
from django.urls import URLPattern, URLResolver

def list_urls(lis, acc=None):

    if acc is None:
        acc = []
    if not lis:
        return
    l = lis[0]
    if isinstance(l, URLPattern):
        yield acc + [str(l.pattern),l.name]
    elif isinstance(l, URLResolver):
        yield from list_urls(l.url_patterns, acc + [str(l.pattern)])
    yield from list_urls(lis[1:], acc)

class Command(BaseCommand):
    help = 'List all URLs from the urlconf'

    def handle(self, *args, **options):

        urlconf = __import__(settings.ROOT_URLCONF, {}, {}, [''])

        records, glen, nlen = [], 0, 0

        for p in list_urls(urlconf.urlpatterns):
            record = [''.join(p[:2]), p[2]]

            # Update me, or add an argument
            if record[0].startswith('yourapp'):

                clen = len(record[0])
                if clen > glen: glen = clen

                clen = len(record[1])
                if clen > nlen: nlen = clen
                
                records.append(record)


        self.stdout.write('{:-<{width}}'.format('',width=glen+nlen))
        self.stdout.write('{:<{glen}}Name'.format('Path',glen=glen+4))
        self.stdout.write('{:-<{width}}'.format('',width=glen+nlen))
        for record in records:
            self.stdout.write('{path:<{glen}}{name}'.format(path=record[0],
                name=record[1],
                glen=glen+4))
        self.stdout.write('{:-<{width}}'.format('',width=glen+nlen))

样例输出

(env) django@dev:myproj~> ./manage.py dumpurls
-------------------------------------------------------------------------------------------------------
Path                                                                        Name
-------------------------------------------------------------------------------------------------------
yourapp/^api-key/$                                                          api-key-list
yourapp/^api-key\.(?P<format>[a-z0-9]+)/?$                                  api-key-list
yourapp/^attacks/$                                                          attack-list
yourapp/^attacks\.(?P<format>[a-z0-9]+)/?$                                  attack-list
yourapp/^attack-histories/$                                                 attackhistory-list
yourapp/^attack-histories\.(?P<format>[a-z0-9]+)/?$                         attackhistory-list
yourapp/^files/$                                                            file-list
yourapp/^files\.(?P<format>[a-z0-9]+)/?$                                    file-list
yourapp/^modules/$                                                          module-list
yourapp/^modules\.(?P<format>[a-z0-9]+)/?$                                  module-list
import subprocces

res = subprocess.run(
    'python manage.py show_urls',
    capture_output=True,
    shell=True,
)
url_list = [
    line.split('\t')[0]
    for line in res.stdout.decode().split('\n')
]

试试这个:

from django.urls import get_resolver
get_resolver().reverse_dict.keys()

或者如果你还在Django 1上。*:

from django.core.urlresolvers import get_resolver
get_resolver(None).reverse_dict.keys()

Django 1.8, Python 2.7+ 只需在Shell中运行这些命令。Python manage.py shell并执行以下代码。

from django.conf.urls import RegexURLPattern, RegexURLResolver
from django.core import urlresolvers
urls = urlresolvers.get_resolver(None)

def if_none(value):
    if value:
        return value
    return ''

def print_urls(urls, parent_pattern=None):
    for url in urls.url_patterns:
        if isinstance(url, RegexURLResolver):
            print_urls(url, if_none(parent_pattern) + url.regex.pattern)
        elif isinstance(url, RegexURLPattern):
            print(if_none(parent_pattern) + url.regex.pattern)

print_urls(urls)

有一个我使用的插件:https://github.com/django-extensions/django-extensions,它有一个show_urls命令可以帮助。