我怎么能看到当前的urlpatterns“反向”正在寻找?
我在一个视图中调用了逆向,我认为这个论证应该成立,但实际上并不成立。有什么办法能让我知道为什么我的图案没有?
我怎么能看到当前的urlpatterns“反向”正在寻找?
我在一个视图中调用了逆向,我认为这个论证应该成立,但实际上并不成立。有什么办法能让我知道为什么我的图案没有?
当前回答
Django >= 2.0列表解决方案
领养自@CesarCanassa
from django.conf import settings
from django.urls import URLPattern, URLResolver
URLCONF = __import__(settings.ROOT_URLCONF, {}, {}, [''])
def list_urls(patterns, path=None):
""" recursive """
if not path:
path = []
result = []
for pattern in patterns:
if isinstance(pattern, URLPattern):
result.append(''.join(path) + str(pattern.pattern))
elif isinstance(pattern, URLResolver):
result += list_urls(pattern.url_patterns, path + [str(pattern.pattern)])
return result
其他回答
这里有一个快速而肮脏的黑客,只需获得你需要的信息,而不需要修改任何设置。
$ pip install django-extensions
$ python manage.py shell -c 'from django.core.management import call_command; from django_extensions.management.commands.show_urls import Command; call_command(Command())'
这是小猪在逃避@robert的回答。虽然是正确的,但我不想让django扩展成为依赖项,哪怕只是一秒钟。
试试这个:
from django.urls import get_resolver
get_resolver().reverse_dict.keys()
或者如果你还在Django 1上。*:
from django.core.urlresolvers import get_resolver
get_resolver(None).reverse_dict.keys()
又一次改编自凯撒·卡纳萨的发电机魔法。这可以添加到你的应用程序的yourapp/management/commands/dumpurls.py目录中,这样它就可以作为management.py中的子命令来访问。
注意:我添加了一行,以确保它只过滤你的应用程序。如果需要其他url,则相应地更新或删除它。
作为management.py子命令
部署路径:yourapp/management/commands/dumpurls.py
from django.core.management.base import BaseCommand, CommandError
from django.conf import settings
from django.urls import URLPattern, URLResolver
def list_urls(lis, acc=None):
if acc is None:
acc = []
if not lis:
return
l = lis[0]
if isinstance(l, URLPattern):
yield acc + [str(l.pattern),l.name]
elif isinstance(l, URLResolver):
yield from list_urls(l.url_patterns, acc + [str(l.pattern)])
yield from list_urls(lis[1:], acc)
class Command(BaseCommand):
help = 'List all URLs from the urlconf'
def handle(self, *args, **options):
urlconf = __import__(settings.ROOT_URLCONF, {}, {}, [''])
records, glen, nlen = [], 0, 0
for p in list_urls(urlconf.urlpatterns):
record = [''.join(p[:2]), p[2]]
# Update me, or add an argument
if record[0].startswith('yourapp'):
clen = len(record[0])
if clen > glen: glen = clen
clen = len(record[1])
if clen > nlen: nlen = clen
records.append(record)
self.stdout.write('{:-<{width}}'.format('',width=glen+nlen))
self.stdout.write('{:<{glen}}Name'.format('Path',glen=glen+4))
self.stdout.write('{:-<{width}}'.format('',width=glen+nlen))
for record in records:
self.stdout.write('{path:<{glen}}{name}'.format(path=record[0],
name=record[1],
glen=glen+4))
self.stdout.write('{:-<{width}}'.format('',width=glen+nlen))
样例输出
(env) django@dev:myproj~> ./manage.py dumpurls
-------------------------------------------------------------------------------------------------------
Path Name
-------------------------------------------------------------------------------------------------------
yourapp/^api-key/$ api-key-list
yourapp/^api-key\.(?P<format>[a-z0-9]+)/?$ api-key-list
yourapp/^attacks/$ attack-list
yourapp/^attacks\.(?P<format>[a-z0-9]+)/?$ attack-list
yourapp/^attack-histories/$ attackhistory-list
yourapp/^attack-histories\.(?P<format>[a-z0-9]+)/?$ attackhistory-list
yourapp/^files/$ file-list
yourapp/^files\.(?P<format>[a-z0-9]+)/?$ file-list
yourapp/^modules/$ module-list
yourapp/^modules\.(?P<format>[a-z0-9]+)/?$ module-list
只要输入一个你知道不存在的url,服务器就会返回一个错误消息,其中包含一个url模式列表。
例如,如果你在http://localhost:8000/something上运行一个网站
输入
http://localhost:8000/something/blahNonsense,您的服务器将返回url搜索列表并在浏览器中显示它
from django.urls.resolvers import RegexPattern,RoutePattern
from your_main_app import urls
def get_urls():
url_list = []
for url in urls.urlpatterns:
url_list.append(url.pattern._regex) if isinstance(url.pattern, RegexPattern) else url_list.append(url.pattern._route)
return url_list
这里your_main_app是放置settings.py文件的应用程序名称