我定义了两个TextInput字段如下:

<TextInput 
   style = {styles.titleInput}
   returnKeyType = {"next"}
   autoFocus = {true}
   placeholder = "Title" />
<TextInput
   style = {styles.descriptionInput}          
   multiline = {true}
   maxLength = {200}
   placeholder = "Description" />

但在按下键盘上的“next”按钮后,我的react-native应用程序并没有跳转到第二个TextInput字段。我怎样才能做到呢?

谢谢!


当前回答

我想分享我的解决方案使用功能组件…“这个”不需要!

React 16.12.0和React Native 0.61.5

这是我的组件的一个例子:

import React, { useRef } from 'react'
...


const MyFormComponent = () => {

  const ref_input2 = useRef();
  const ref_input3 = useRef();

  return (
    <>
      <TextInput
        placeholder="Input1"
        autoFocus={true}
        returnKeyType="next"
        onSubmitEditing={() => ref_input2.current.focus()}
      />
      <TextInput
        placeholder="Input2"
        returnKeyType="next"
        onSubmitEditing={() => ref_input3.current.focus()}
        ref={ref_input2}
      />
      <TextInput
        placeholder="Input3"
        ref={ref_input3}
      />
    </>
  )
}

其他回答

使用回调引用而不是遗留的字符串引用:

<TextInput
    style = {styles.titleInput}
    returnKeyType = {"next"}
    autoFocus = {true}
    placeholder = "Title"
    onSubmitEditing={() => {this.nextInput.focus()}}
/>
<TextInput
    style = {styles.descriptionInput}  
    multiline = {true}
    maxLength = {200}
    placeholder = "Description"
    ref={nextInput => this.nextInput = nextInput}
/>

有一种方法可以捕获TextInput中的制表符。这很俗气,但总比没有好。

定义一个onChangeText处理程序,比较新输入值和旧输入值,检查是否有\t。如果找到一个,推进字段如@boredgames所示

假设变量username包含用户名的值,setUsername在存储(组件状态,redux存储等)中分派一个动作来更改它,执行如下操作:

function tabGuard (newValue, oldValue, callback, nextCallback) {
  if (newValue.indexOf('\t') >= 0 && oldValue.indexOf('\t') === -1) {
    callback(oldValue)
    nextCallback()
  } else {
    callback(newValue)
  }
}

class LoginScene {
  focusNextField = (nextField) => {
    this.refs[nextField].focus()
  }

  focusOnPassword = () => {
    this.focusNextField('password')
  }

  handleUsernameChange = (newValue) => {
    const { username } = this.props            // or from wherever
    const { setUsername } = this.props.actions // or from wherever

    tabGuard(newValue, username, setUsername, this.focusOnPassword)
  }

  render () {
    const { username } = this.props

    return (
      <TextInput ref='username'
                 placeholder='Username'
                 autoCapitalize='none'
                 autoCorrect={false}
                 autoFocus
                 keyboardType='email-address'
                 onChangeText={handleUsernameChange}
                 blurOnSubmit={false}
                 onSubmitEditing={focusOnPassword}
                 value={username} />
    )
  }
}

我就是这样做到的。下面的例子使用了React 16.3中引入的React. createref () API。

class Test extends React.Component {
  constructor(props) {
    super(props);
    this.secondTextInputRef = React.createRef();
  }

  render() {
    return(
        <View>
            <TextInput
                placeholder = "FirstTextInput"
                returnKeyType="next"
                onSubmitEditing={() => { this.secondTextInputRef.current.focus(); }}
            />
            <TextInput
                ref={this.secondTextInputRef}
                placeholder = "secondTextInput"
            />
        </View>
    );
  }
}

我想这对你有帮助。

从React Native 0.36开始,不再支持在文本输入节点上调用focus()(在其他几个答案中建议)。相反,你可以使用React Native中的TextInputState模块。我创建了以下帮助模块,使这更容易:

// TextInputManager
//
// Provides helper functions for managing the focus state of text
// inputs. This is a hack! You are supposed to be able to call
// "focus()" directly on TextInput nodes, but that doesn't seem
// to be working as of ReactNative 0.36
//
import { findNodeHandle } from 'react-native'
import TextInputState from 'react-native/lib/TextInputState'


export function focusTextInput(node) {
  try {
    TextInputState.focusTextInput(findNodeHandle(node))
  } catch(e) {
    console.log("Couldn't focus text input: ", e.message)
  }
}

然后,您可以在TextInput的任何“ref”上调用focusTextInput函数。例如:

...
<TextInput onSubmit={() => focusTextInput(this.refs.inputB)} />
<TextInput ref="inputB" />
...

在React Native的GitHub问题上尝试这个解决方案。

https://github.com/facebook/react-native/pull/2149#issuecomment-129262565

你需要为TextInput组件使用ref道具。 然后你需要创建一个函数,该函数在onSubmitEditing道具上被调用,将焦点移动到第二个TextInput引用上。

var InputScreen = React.createClass({
    _focusNextField(nextField) {
        this.refs[nextField].focus()
    },

    render: function() {
        return (
            <View style={styles.container}>
                <TextInput
                    ref='1'
                    style={styles.input}
                    placeholder='Normal'
                    returnKeyType='next'
                    blurOnSubmit={false}
                    onSubmitEditing={() => this._focusNextField('2')}
                />
                <TextInput
                    ref='2'
                    style={styles.input}
                    keyboardType='email-address'
                    placeholder='Email Address'
                    returnKeyType='next'
                    blurOnSubmit={false}
                    onSubmitEditing={() => this._focusNextField('3')}
                />
                <TextInput
                    ref='3'
                    style={styles.input}
                    keyboardType='url'
                    placeholder='URL'
                    returnKeyType='next'
                    blurOnSubmit={false}
                    onSubmitEditing={() => this._focusNextField('4')}
                />
                <TextInput
                    ref='4'
                    style={styles.input}
                    keyboardType='numeric'
                    placeholder='Numeric'
                    blurOnSubmit={false}
                    onSubmitEditing={() => this._focusNextField('5')}
                />
                <TextInput
                    ref='5'
                    style={styles.input}
                    keyboardType='numbers-and-punctuation'
                    placeholder='Numbers & Punctuation'
                    returnKeyType='done'
                />
            </View>
        );
    }
});