我定义了两个TextInput字段如下:
<TextInput
style = {styles.titleInput}
returnKeyType = {"next"}
autoFocus = {true}
placeholder = "Title" />
<TextInput
style = {styles.descriptionInput}
multiline = {true}
maxLength = {200}
placeholder = "Description" />
但在按下键盘上的“next”按钮后，我的react-native应用程序并没有跳转到第二个TextInput字段。我怎样才能做到呢?
谢谢!
当前回答
在React Native的GitHub问题上尝试这个解决方案。
https://github.com/facebook/react-native/pull/2149#issuecomment-129262565
你需要为TextInput组件使用ref道具。 然后你需要创建一个函数，该函数在onSubmitEditing道具上被调用，将焦点移动到第二个TextInput引用上。
var InputScreen = React.createClass({
_focusNextField(nextField) {
this.refs[nextField].focus()
},
render: function() {
return (
<View style={styles.container}>
<TextInput
ref='1'
style={styles.input}
placeholder='Normal'
returnKeyType='next'
blurOnSubmit={false}
onSubmitEditing={() => this._focusNextField('2')}
/>
<TextInput
ref='2'
style={styles.input}
keyboardType='email-address'
placeholder='Email Address'
returnKeyType='next'
blurOnSubmit={false}
onSubmitEditing={() => this._focusNextField('3')}
/>
<TextInput
ref='3'
style={styles.input}
keyboardType='url'
placeholder='URL'
returnKeyType='next'
blurOnSubmit={false}
onSubmitEditing={() => this._focusNextField('4')}
/>
<TextInput
ref='4'
style={styles.input}
keyboardType='numeric'
placeholder='Numeric'
blurOnSubmit={false}
onSubmitEditing={() => this._focusNextField('5')}
/>
<TextInput
ref='5'
style={styles.input}
keyboardType='numbers-and-punctuation'
placeholder='Numbers & Punctuation'
returnKeyType='done'
/>
</View>
);
}
});
其他回答
在你的组件中:
constructor(props) {
super(props);
this.focusNextField = this
.focusNextField
.bind(this);
// to store our input refs
this.inputs = {};
}
focusNextField(id) {
console.log("focus next input: " + id);
this
.inputs[id]
._root
.focus();
}
注意:我使用了._root，因为它是NativeBase' library ' Input中的TextInput的引用
在文本输入中，像这样
<TextInput
onSubmitEditing={() => {
this.focusNextField('two');
}}
returnKeyType="next"
blurOnSubmit={false}/>
<TextInput
ref={input => {
this.inputs['two'] = input;
}}/>
如果您恰好像我一样使用tcomb-form-native，您也可以这样做。这里有一个技巧:不是直接设置TextInput的道具，而是通过选项来实现。您可以将表单的字段引用为:
this.refs.form.getComponent('password').refs.input.focus()
所以最终的产品看起来是这样的:
var t = require('tcomb-form-native');
var Form = t.form.Form;
var MyForm = t.struct({
field1: t.String,
field2: t.String,
});
var MyComponent = React.createClass({
_getFormOptions () {
return {
fields: {
field1: {
returnKeyType: 'next',
onSubmitEditing: () => {this.refs.form.getComponent('field2').refs.input.focus()},
},
},
};
},
render () {
var formOptions = this._getFormOptions();
return (
<View style={styles.container}>
<Form ref="form" type={MyForm} options={formOptions}/>
</View>
);
},
});
(感谢remcoanker在这里发布的想法:https://github.com/gcanti/tcomb-form-native/issues/96)
RN没有某种类型的Tabindex系统，这很令人恼火。
一个功能性组件，对于我的用例，我有一个字符串id数组用于输入，我遍历并显示每个文本输入。下面的代码将自动跳过所有这些，阻止键盘在字段之间消失/重新出现，并在结束时解散它，还在键盘上显示适当的“动作”按钮。
Typescript, Native Base。
const stringFieldIDs = [ 'q1', 'q2', 'q3' ]; export default () => { const stringFieldRefs = stringFieldIDs.map(() => useRef < any > ()); const basicStringField = (id: string, ind: number) => { const posInd = stringFieldIDs.indexOf(id); const isLast = posInd === stringFieldIDs.length - 1; return ( < Input blurOnSubmit = { isLast } ref = { stringFieldRefs[posInd] } returnKeyType = { isLast ? 'done' : 'next' } onSubmitEditing = { isLast ? undefined : () => stringFieldRefs[posInd + 1].current._root.focus() } /> ); }; return stringFieldIDs.map(basicStringField); };
有一种方法可以捕获TextInput中的制表符。这很俗气，但总比没有好。
定义一个onChangeText处理程序，比较新输入值和旧输入值，检查是否有\t。如果找到一个，推进字段如@boredgames所示
假设变量username包含用户名的值，setUsername在存储(组件状态，redux存储等)中分派一个动作来更改它，执行如下操作:
function tabGuard (newValue, oldValue, callback, nextCallback) {
if (newValue.indexOf('\t') >= 0 && oldValue.indexOf('\t') === -1) {
callback(oldValue)
nextCallback()
} else {
callback(newValue)
}
}
class LoginScene {
focusNextField = (nextField) => {
this.refs[nextField].focus()
}
focusOnPassword = () => {
this.focusNextField('password')
}
handleUsernameChange = (newValue) => {
const { username } = this.props // or from wherever
const { setUsername } = this.props.actions // or from wherever
tabGuard(newValue, username, setUsername, this.focusOnPassword)
}
render () {
const { username } = this.props
return (
<TextInput ref='username'
placeholder='Username'
autoCapitalize='none'
autoCorrect={false}
autoFocus
keyboardType='email-address'
onChangeText={handleUsernameChange}
blurOnSubmit={false}
onSubmitEditing={focusOnPassword}
value={username} />
)
}
}
使用react-native 0.45.1我还遇到了问题，试图在按下用户名TextInput的返回键后将焦点设置在密码TextInput上。
在尝试了这里的大多数顶级解决方案之后，我在github上找到了一个解决方案，满足了我的需求: https://github.com/shoutem/ui/issues/44#issuecomment-290724642
总结一下:
import React, { Component } from 'react';
import { TextInput as RNTextInput } from 'react-native';
export default class TextInput extends Component {
render() {
const { props } = this;
return (
<RNTextInput
{...props}
ref={(input) => props.inputRef && props.inputRef(input)}
/>
);
}
}
然后我这样使用它:
import React, {Component} from 'react';
import {
View,
} from 'react-native';
import TextInput from "../../components/TextInput";
class Login extends Component {
constructor(props) {
super(props);
this.passTextInput = null
}
render() {
return (
<View style={{flex:1}}>
<TextInput
style={{flex:1}}
placeholder="Username"
onSubmitEditing={(event) => {
this.passTextInput.focus()
}}
/>
<TextInput
style={{flex:1}}
placeholder="Password"
inputRef={(input) => {
this.passTextInput = input
}}
/>
</View>
)
}
}
