我定义了两个TextInput字段如下:

<TextInput 
   style = {styles.titleInput}
   returnKeyType = {"next"}
   autoFocus = {true}
   placeholder = "Title" />
<TextInput
   style = {styles.descriptionInput}          
   multiline = {true}
   maxLength = {200}
   placeholder = "Description" />

但在按下键盘上的“next”按钮后,我的react-native应用程序并没有跳转到第二个TextInput字段。我怎样才能做到呢?

谢谢!


当前回答

结合@Eli Johnson的功能组件解决方案和@Rodrigo Tessarollo的CustomTextInput解决方案:

import React, { useRef } from 'react';
import { CustomTextInput } from 'path/to/CustomTextInput';
...


export const MyFormComponent = () => {

  const ref_to_input2 = useRef();

  return (
    <>
      <CustomTextInput
        placeholder="Input 1"
        autoFocus={true}
        returnKeyType="next"
        onSubmitEditing={() => ref_to_input2.current.focus()}
      />
      <CustomTextInput
        placeholder="Input 2"
        returnKeyType="done"
        refInner={ref_to_input2}
        onSubmitEditing={/* Do something! */}
      />
    </>
  )
}

在你的CustomTextInput组件中:

import { TextInput } from "react-native";
export const CustomTextInput = (props) => {
  <TextInput
        ref={props.refInner}
        {...props}
  />
}

其他回答

如果你的TextInput在另一个组件中,要让这个被接受的解决方案工作,你需要从ref“弹出”到父容器的引用。

// MyComponent
render() {
    <View>
        <TextInput ref={(r) => this.props.onRef(r)} { ...this.props }/>
    </View>
}

// MyView
render() {
    <MyComponent onSubmitEditing={(evt) => this.myField2.focus()}/>
    <MyComponent onRef={(r) => this.myField2 = r}/>
}

下面是如何为reactjs的电话代码输入实现这一点

import React, { useState, useRef } from 'react';

function Header(props) {

  const [state , setState] = useState({
        phone_number:"",
        code_one:'',
        code_two:'',
        code_three:'',
        code_four:'',
        submitted:false,

  })

   const codeOneInput = useRef(null);
   const codeTwoInput = useRef(null);
   const codeThreeInput = useRef(null);
   const codeFourInput = useRef(null);

   const handleCodeChange = (e) => {
        const {id , value} = e.target
        if(value.length < 2){
            setState(prevState => ({
                ...prevState,
                [id] : value
            }))
            if(id=='code_one' && value.length >0){
                codeTwoInput.current.focus();
            }
            if(id=='code_two'  && value.length >0){
                codeThreeInput.current.focus();
            }
            if(id=='code_three'  && value.length >0){
                codeFourInput.current.focus();
            }
        }
    }

    const sendCodeToServer = () => {

         setState(prevState => ({
                ...prevState,
                submitted : true,
          }))
  let codeEnteredByUser = state.code_one + state.code_two + state.code_three + state.code_four

        axios.post(API_BASE_URL, {code:codeEnteredByUser})
        .then(function (response) {
            console.log(response)
        })

   }

   return(
        <>

           <div className="are">
                 <div className="POP-INN-INPUT">
                                        <input type="text" id="code_one" ref={codeOneInput}    value={state.code_one}  onChange={handleCodeChange} autoFocus/>
                                        <input type="text" id="code_two"  ref={codeTwoInput}  value={state.code_two} onChange={handleCodeChange}/>
                                        <input type="text" id="code_three"  ref={codeThreeInput} value={state.code_three}  onChange={handleCodeChange}/>
                                        <input type="text" id="code_four" ref={codeFourInput}  value={state.code_four}  onChange={handleCodeChange}/>
                                    </div>

            <button disabled={state.submitted} onClick={sendCodeToServer}>
   
    </div>

       </>
    )
}
export default

使用react-native 0.45.1我还遇到了问题,试图在按下用户名TextInput的返回键后将焦点设置在密码TextInput上。

在尝试了这里的大多数顶级解决方案之后,我在github上找到了一个解决方案,满足了我的需求: https://github.com/shoutem/ui/issues/44#issuecomment-290724642

总结一下:

import React, { Component } from 'react';
import { TextInput as RNTextInput } from 'react-native';

export default class TextInput extends Component {
    render() {
        const { props } = this;

        return (
            <RNTextInput
                {...props}
                ref={(input) => props.inputRef && props.inputRef(input)}
            />
        );
    }
}

然后我这样使用它:

import React, {Component} from 'react';
import {
    View,
} from 'react-native';
import TextInput from "../../components/TextInput";

class Login extends Component {
    constructor(props) {
        super(props);
        this.passTextInput = null
    }

    render() {
        return (
            <View style={{flex:1}}>
                <TextInput
                    style={{flex:1}}
                    placeholder="Username"
                    onSubmitEditing={(event) => {
                        this.passTextInput.focus()
                    }}
                />

                <TextInput
                    style={{flex:1}}
                    placeholder="Password"
                    inputRef={(input) => {
                        this.passTextInput = input
                    }}
                />
            </View>
        )
    }
}
<TextInput 
    keyboardType="email-address"
    placeholder="Email"
    returnKeyType="next"
    ref="email"
    onSubmitEditing={() => this.focusTextInput(this.refs.password)}
    blurOnSubmit={false}
 />
<TextInput
    ref="password"
    placeholder="Password" 
    secureTextEntry={true} />

并添加方法onSubmitEditing={() => this.focusTextInput(this.ref .password)}如下所示:

private focusTextInput(node: any) {
    node.focus();
}

设置第二个TextInput焦点,当前一个TextInput的onSubmitEditing被触发时。

试试这个

为第二个TextInput添加一个引用 Ref ={(input) => {this。secondTextInput =输入;}} 绑定焦点函数到第一个TextInput的onSubmitEditing事件。 onSubmitEditing={() => {this.secondTextInput.focus();}} 记住将blurOnSubmit设置为false,以防止键盘闪烁。 blurOnSubmit ={假}

当一切都完成后,它应该看起来像这样。

<TextInput
    placeholder="FirstTextInput"
    returnKeyType="next"
    onSubmitEditing={() => { this.secondTextInput.focus(); }}
    blurOnSubmit={false}
/>

<TextInput
    ref={(input) => { this.secondTextInput = input; }}
    placeholder="secondTextInput"
/>