我定义了两个TextInput字段如下:
<TextInput
style = {styles.titleInput}
returnKeyType = {"next"}
autoFocus = {true}
placeholder = "Title" />
<TextInput
style = {styles.descriptionInput}
multiline = {true}
maxLength = {200}
placeholder = "Description" />
但在按下键盘上的“next”按钮后，我的react-native应用程序并没有跳转到第二个TextInput字段。我怎样才能做到呢?
谢谢!
当前回答
下面是如何为reactjs的电话代码输入实现这一点
import React, { useState, useRef } from 'react';
function Header(props) {
const [state , setState] = useState({
phone_number:"",
code_one:'',
code_two:'',
code_three:'',
code_four:'',
submitted:false,
})
const codeOneInput = useRef(null);
const codeTwoInput = useRef(null);
const codeThreeInput = useRef(null);
const codeFourInput = useRef(null);
const handleCodeChange = (e) => {
const {id , value} = e.target
if(value.length < 2){
setState(prevState => ({
...prevState,
[id] : value
}))
if(id=='code_one' && value.length >0){
codeTwoInput.current.focus();
}
if(id=='code_two' && value.length >0){
codeThreeInput.current.focus();
}
if(id=='code_three' && value.length >0){
codeFourInput.current.focus();
}
}
}
const sendCodeToServer = () => {
setState(prevState => ({
...prevState,
submitted : true,
}))
let codeEnteredByUser = state.code_one + state.code_two + state.code_three + state.code_four
axios.post(API_BASE_URL, {code:codeEnteredByUser})
.then(function (response) {
console.log(response)
})
}
return(
<>
<div className="are">
<div className="POP-INN-INPUT">
<input type="text" id="code_one" ref={codeOneInput} value={state.code_one} onChange={handleCodeChange} autoFocus/>
<input type="text" id="code_two" ref={codeTwoInput} value={state.code_two} onChange={handleCodeChange}/>
<input type="text" id="code_three" ref={codeThreeInput} value={state.code_three} onChange={handleCodeChange}/>
<input type="text" id="code_four" ref={codeFourInput} value={state.code_four} onChange={handleCodeChange}/>
</div>
<button disabled={state.submitted} onClick={sendCodeToServer}>
</div>
</>
)
}
export default
其他回答
有一种方法可以捕获TextInput中的制表符。这很俗气，但总比没有好。
定义一个onChangeText处理程序，比较新输入值和旧输入值，检查是否有\t。如果找到一个，推进字段如@boredgames所示
假设变量username包含用户名的值，setUsername在存储(组件状态，redux存储等)中分派一个动作来更改它，执行如下操作:
function tabGuard (newValue, oldValue, callback, nextCallback) {
if (newValue.indexOf('\t') >= 0 && oldValue.indexOf('\t') === -1) {
callback(oldValue)
nextCallback()
} else {
callback(newValue)
}
}
class LoginScene {
focusNextField = (nextField) => {
this.refs[nextField].focus()
}
focusOnPassword = () => {
this.focusNextField('password')
}
handleUsernameChange = (newValue) => {
const { username } = this.props // or from wherever
const { setUsername } = this.props.actions // or from wherever
tabGuard(newValue, username, setUsername, this.focusOnPassword)
}
render () {
const { username } = this.props
return (
<TextInput ref='username'
placeholder='Username'
autoCapitalize='none'
autoCorrect={false}
autoFocus
keyboardType='email-address'
onChangeText={handleUsernameChange}
blurOnSubmit={false}
onSubmitEditing={focusOnPassword}
value={username} />
)
}
}
我想分享我的解决方案使用功能组件…“这个”不需要!
React 16.12.0和React Native 0.61.5
这是我的组件的一个例子:
import React, { useRef } from 'react'
...
const MyFormComponent = () => {
const ref_input2 = useRef();
const ref_input3 = useRef();
return (
<>
<TextInput
placeholder="Input1"
autoFocus={true}
returnKeyType="next"
onSubmitEditing={() => ref_input2.current.focus()}
/>
<TextInput
placeholder="Input2"
returnKeyType="next"
onSubmitEditing={() => ref_input3.current.focus()}
ref={ref_input2}
/>
<TextInput
placeholder="Input3"
ref={ref_input3}
/>
</>
)
}
在你的组件中:
constructor(props) {
super(props);
this.focusNextField = this
.focusNextField
.bind(this);
// to store our input refs
this.inputs = {};
}
focusNextField(id) {
console.log("focus next input: " + id);
this
.inputs[id]
._root
.focus();
}
注意:我使用了._root，因为它是NativeBase' library ' Input中的TextInput的引用
在文本输入中，像这样
<TextInput
onSubmitEditing={() => {
this.focusNextField('two');
}}
returnKeyType="next"
blurOnSubmit={false}/>
<TextInput
ref={input => {
this.inputs['two'] = input;
}}/>
RN没有某种类型的Tabindex系统，这很令人恼火。
一个功能性组件，对于我的用例，我有一个字符串id数组用于输入，我遍历并显示每个文本输入。下面的代码将自动跳过所有这些，阻止键盘在字段之间消失/重新出现，并在结束时解散它，还在键盘上显示适当的“动作”按钮。
Typescript, Native Base。
const stringFieldIDs = [ 'q1', 'q2', 'q3' ]; export default () => { const stringFieldRefs = stringFieldIDs.map(() => useRef < any > ()); const basicStringField = (id: string, ind: number) => { const posInd = stringFieldIDs.indexOf(id); const isLast = posInd === stringFieldIDs.length - 1; return ( < Input blurOnSubmit = { isLast } ref = { stringFieldRefs[posInd] } returnKeyType = { isLast ? 'done' : 'next' } onSubmitEditing = { isLast ? undefined : () => stringFieldRefs[posInd + 1].current._root.focus() } /> ); }; return stringFieldIDs.map(basicStringField); };
使用react-native 0.45.1我还遇到了问题，试图在按下用户名TextInput的返回键后将焦点设置在密码TextInput上。
在尝试了这里的大多数顶级解决方案之后，我在github上找到了一个解决方案，满足了我的需求: https://github.com/shoutem/ui/issues/44#issuecomment-290724642
总结一下:
import React, { Component } from 'react';
import { TextInput as RNTextInput } from 'react-native';
export default class TextInput extends Component {
render() {
const { props } = this;
return (
<RNTextInput
{...props}
ref={(input) => props.inputRef && props.inputRef(input)}
/>
);
}
}
然后我这样使用它:
import React, {Component} from 'react';
import {
View,
} from 'react-native';
import TextInput from "../../components/TextInput";
class Login extends Component {
constructor(props) {
super(props);
this.passTextInput = null
}
render() {
return (
<View style={{flex:1}}>
<TextInput
style={{flex:1}}
placeholder="Username"
onSubmitEditing={(event) => {
this.passTextInput.focus()
}}
/>
<TextInput
style={{flex:1}}
placeholder="Password"
inputRef={(input) => {
this.passTextInput = input
}}
/>
</View>
)
}
}
