我如何转换字符串既像'helloThere'或'helloThere'到'HelloThere'在JavaScript?
当前回答
输入 javaScript
输出 Java脚本
var text = 'javaScript';
text.replace(/([a-z])([A-Z][a-z])/g, "$1 $2").charAt(0).toUpperCase()+text.slice(1).replace(/([a-z])([A-Z][a-z])/g, "$1 $2");
其他回答
如果你处理的是大写骆驼的情况,这个片段可以帮助你,它还包含一些规格,所以你可以确保它适合你的情况。
export const fromCamelCaseToSentence = (word) =>
word
.replace(/([A-Z][a-z]+)/g, ' $1')
.replace(/([A-Z]{2,})/g, ' $1')
.replace(/\s{2,}/g, ' ')
.trim();
和规格:
describe('fromCamelCaseToSentence', () => {
test('does not fall with a single word', () => {
expect(fromCamelCaseToSentence('Approved')).toContain('Approved')
expect(fromCamelCaseToSentence('MDA')).toContain('MDA')
})
test('does not fall with an empty string', () => {
expect(fromCamelCaseToSentence('')).toContain('')
})
test('returns the separated by space words', () => {
expect(fromCamelCaseToSentence('NotApprovedStatus')).toContain('Not Approved Status')
expect(fromCamelCaseToSentence('GDBState')).toContain('GDB State')
expect(fromCamelCaseToSentence('StatusDGG')).toContain('Status DGG')
})
})
使用JS的String.prototype.replace()和String.prototype.toUpperCase()
const str = "thisIsATestString"; const res = str.replace (/ ^ [a - z] | [a - z] / g (c i) = >(我吗?": "") + c.toUpperCase()); console.log (res);// "This Is A Test String"
下面是使用正则表达式演示驼峰大小写字符串到句子字符串的链接。
输入
myCamelCaseSTRINGToSPLITDemo
输出
我的骆驼案例字符串分裂演示
这是一个将驼峰格式转换为句子文本的正则表达式
(?=[A-Z][a-z])|([A-Z]+)([A-Z][a-rt-z][a-z]\*)
用1美元2美元代替。
单击可查看正则表达式的转换
连续大写单词的最兼容的答案是:
常量文本 = 'theKD'; const result = text.replace(/([A-Z]{1,})/g, “$1”); const finalResult = result.charAt(0).toUpperCase() + result.slice(1); 控制台.log(最终结果);
它也与KD兼容,不会将其转换为KD。
我的分裂案例解决方案的行为方式,我想:
const splitCase = s => !s || s.indexOf(' ') >= 0 ? s :
(s.charAt(0).toUpperCase() + s.substring(1))
.split(/(?<=[a-z])(?=[A-Z])|(?<=[A-Z])(?=[A-Z][a-z])/g)
.map(x => x.replace(/([0-9]+)/g,'$1 '))
.join(' ')
输入
'a,abc,TheId,TheID,TheIDWord,TheID2Word,Leave me Alone!'
.split(',').map(splitCase)
.forEach(x => console.log(x))
输出
A
Abc
The Id
The ID
The ID Word
The ID2 Word
Leave me Alone!
由于上述函数需要在JS中使用Lookbehind,而目前Safari中还没有实现,因此我重写了实现,以不使用下面的RegEx:
const isUpper = c => c >= 'A' && c <= 'Z'
const isDigit = c => c >= '0' && c <= '9'
const upperOrDigit = c => isUpper(c) || isDigit(c)
function splitCase(s) {
let to = []
if (typeof s != 'string') return to
let lastSplit = 0
for (let i=0; i<s.length; i++) {
let c = s[i]
let prev = i>0 ? s[i-1] : null
let next = i+1 < s.length ? s[i+1] : null
if (upperOrDigit(c) && (!upperOrDigit(prev) || !upperOrDigit(next))) {
to.push(s.substring(lastSplit, i))
lastSplit = i
}
}
to.push(s.substring(lastSplit, s.length))
return to.filter(x => !!x)
}