这帮助了我，当我试图深度复制Dictionary < string, string >

Dictionary<string, string> dict2 = new Dictionary<string, string>(dict);

祝你好运

对我来说最好的方法是:

Dictionary<int, int> copy= new Dictionary<int, int>(yourListOrDictionary);

在这种情况下，你有一个"object"的字典，object可以是(double, int，…或ComplexClass):

Dictionary<string, object> dictSrc { get; set; }

public class ComplexClass : ICloneable
{
    
    private Point3D ...;
    private Vector3D ....;
    [...]

    public object Clone()
    {
        ComplexClass clone = new ComplexClass();
        clone = (ComplexClass)this.MemberwiseClone();
        return clone;
    }

}


dictSrc["toto"] = new ComplexClass()
dictSrc["tata"] = 12.3
...

dictDest = dictSrc.ToDictionary(entry => entry.Key,
                                entry => ((entry.Value is ICloneable) ? (entry.Value as ICloneable).Clone() : entry.Value) );

好的，.NET 2.0的答案是:

如果不需要克隆值，可以使用构造函数重载to Dictionary，该构造函数接受一个现有的Dictionary。(也可以将比较器指定为现有字典的比较器。)

如果你确实需要克隆值，你可以使用这样的方法:

public static Dictionary<TKey, TValue> CloneDictionaryCloningValues<TKey, TValue>
   (Dictionary<TKey, TValue> original) where TValue : ICloneable
{
    Dictionary<TKey, TValue> ret = new Dictionary<TKey, TValue>(original.Count,
                                                            original.Comparer);
    foreach (KeyValuePair<TKey, TValue> entry in original)
    {
        ret.Add(entry.Key, (TValue) entry.Value.Clone());
    }
    return ret;
}

当然，这也依赖于TValue.Clone()是一个适当的深度克隆。

这帮助了我，当我试图深度复制Dictionary < string, string >

Dictionary<string, string> dict2 = new Dictionary<string, string>(dict);

祝你好运

Dictionary<string, int> dictionary = new Dictionary<string, int>();

Dictionary<string, int> copy = new Dictionary<string, int>(dictionary);