我用这个

@"^([\w\.\-]+)@([\w\-]+)((\.(\w){2,3})+)$"

Regexp来验证电子邮件

([\w\.\-]+) -用于第一级域名(许多字母和数字,也有点和连字符) ([\w\-]+) -用于二级域 ((\.(\w){2,3})+) -这是用于其他级别域(从3到无穷),其中包括一个点和2或3个字面量

这个正则表达式有什么问题?

编辑:它与“something@someth.ing”电子邮件不匹配


当前回答

没有完美的正则表达式,但我认为,基于对RFC5322的研究,这个正则表达式相当强大。用c#字符串插值,我认为也很容易理解。

const string atext = @"a-zA-Z\d!#\$%&'\*\+-/=\?\^_`\{\|\}~";
var localPart = $"[{atext}]+(\\.[{atext}]+)*";
var domain = $"[{atext}]+(\\.[{atext}]+)*";
Assert.That(() => EmailRegex = new Regex($"^{localPart}@{domain}$", Compiled), 
Throws.Nothing);

用NUnit 2.x检查。

其他回答

这并不满足rfc 5321和5322的所有要求,但它适用于以下定义。

@"^([0-9a-zA-Z]([\+\-_\.][0-9a-zA-Z]+)*)+"@(([0-9a-zA-Z][-\w]*[0-9a-zA-Z]*\.)+[a-zA-Z0-9]{2,17})$";

下面是代码

const String pattern =
   @"^([0-9a-zA-Z]" + //Start with a digit or alphabetical
   @"([\+\-_\.][0-9a-zA-Z]+)*" + // No continuous or ending +-_. chars in email
   @")+" +
   @"@(([0-9a-zA-Z][-\w]*[0-9a-zA-Z]*\.)+[a-zA-Z0-9]{2,17})$";

var validEmails = new[] {
        "ma@hostname.com",
        "ma@hostname.comcom",
        "MA@hostname.coMCom",
        "m.a@hostname.co",
        "m_a1a@hostname.com",
        "ma-a@hostname.com",
        "ma-a@hostname.com.edu",
        "ma-a.aa@hostname.com.edu",
        "ma.h.saraf.onemore@hostname.com.edu",
        "ma12@hostname.com",
        "12@hostname.com",
};
var invalidEmails = new[] {
        "Abc.example.com",     // No `@`
        "A@b@c@example.com",   // multiple `@`
        "ma...ma@jjf.co",      // continuous multiple dots in name
        "ma@jjf.c",            // only 1 char in extension
        "ma@jjf..com",         // continuous multiple dots in domain
        "ma@@jjf.com",         // continuous multiple `@`
        "@majjf.com",          // nothing before `@`
        "ma.@jjf.com",         // nothing after `.`
        "ma_@jjf.com",         // nothing after `_`
        "ma_@jjf",             // no domain extension 
        "ma_@jjf.",            // nothing after `_` and .
        "ma@jjf.",             // nothing after `.`
    };

foreach (var str in validEmails)
{
    Console.WriteLine("{0} - {1} ", str, Regex.IsMatch(str, pattern));
}
foreach (var str in invalidEmails)
{
    Console.WriteLine("{0} - {1} ", str, Regex.IsMatch(str, pattern));
}

这段代码将有助于在c#.Net中使用正则表达式验证电子邮件id。它很容易使用

if (!System.Text.RegularExpressions.Regex.IsMatch("<Email String Here>", @"^([\w\.\-]+)@([\w\-]+)((\.(\w){2,3})+)$"))
        {
            MessageBox.show("Incorrect Email Id.");
        }

如果它不起作用,请告诉我:)

public static bool isValidEmail(this string email)
{

    string[] mail = email.Split(new string[] { "@" }, StringSplitOptions.None);

    if (mail.Length != 2)
        return false;

    //check part before ...@

    if (mail[0].Length < 1)
        return false;

    System.Text.RegularExpressions.Regex regex = new System.Text.RegularExpressions.Regex(@"^[a-zA-Z0-9_\-\.]+$");
    if (!regex.IsMatch(mail[0]))
        return false;

    //check part after @...

    string[] domain = mail[1].Split(new string[] { "." }, StringSplitOptions.None);

    if (domain.Length < 2)
        return false;

    regex = new System.Text.RegularExpressions.Regex(@"^[a-zA-Z0-9_\-]+$");

    foreach (string d in domain)
    {
        if (!regex.IsMatch(d))
            return false;
    }

    //get TLD
    if (domain[domain.Length - 1].Length < 2)
        return false;

    return true;

}

以下是我从这里收集信息和微软文档后的解决方案:

/// <summary>
/// * TLD support from 2 to 5 chars (modify the values as you want)
/// * Supports: abc@gmail.com.us
/// * Non-sensitive case 
/// * Stops operation if takes longer than 250ms and throw a detailed exception
/// </summary>
/// <param name="email"></param>
/// <returns>valid: true | invalid: false </returns>
/// <exception cref="ArgumentException"></exception>

private bool validateEmailPattern(string email) {
    try {
        return Regex.IsMatch(email,
            @"^([\w\.\-]+)@([\w\-]+)((\.(\w){2,5})+)$",
            RegexOptions.None, TimeSpan.FromMilliseconds(250));
    } catch (RegexMatchTimeoutException) {
        // throw an exception explaining the task was failed 
        _ = email ?? throw new ArgumentException("email, Timeout/failed regexr processing.", nameof(email));
    }
}

我在MSDN上找到了一个很好的文档。

如何:验证字符串是否在有效的电子邮件格式 http://msdn.microsoft.com/en-us/library/01escwtf.aspx (请注意,这段代码还支持在Internet域名中使用非ascii字符。)

有两个实现,用于。net 2.0/3.0和用于。net 3.5及更高版本。 2.0/3.0版本为:

bool IsValidEmail(string strIn)
{
    // Return true if strIn is in valid e-mail format.
    return Regex.IsMatch(strIn, @"^([\w-\.]+)@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.)|(([\w-]+\.)+))([a-zA-Z]{2,4}|[0-9]{1,3})(\]?)$"); 
}

我对这个方法的测试给出:

Invalid: @majjf.com
Invalid: A@b@c@example.com
Invalid: Abc.example.com
Valid: j..s@proseware.com
Valid: j.@server1.proseware.com
Invalid: js*@proseware.com
Invalid: js@proseware..com
Valid: ma...ma@jjf.co
Valid: ma.@jjf.com
Invalid: ma@@jjf.com
Invalid: ma@jjf.
Invalid: ma@jjf..com
Invalid: ma@jjf.c
Invalid: ma_@jjf
Invalid: ma_@jjf.
Valid: ma_@jjf.com
Invalid: -------
Valid: 12@hostname.com
Valid: d.j@server1.proseware.com
Valid: david.jones@proseware.com
Valid: j.s@server1.proseware.com
Invalid: j@proseware.com9
Valid: j_9@[129.126.118.1]
Valid: jones@ms1.proseware.com
Invalid: js#internal@proseware.com
Invalid: js@proseware.com9
Invalid: js@proseware.com9
Valid: m.a@hostname.co
Valid: m_a1a@hostname.com
Valid: ma.h.saraf.onemore@hostname.com.edu
Valid: ma@hostname.com
Invalid: ma@hostname.comcom
Invalid: MA@hostname.coMCom
Valid: ma12@hostname.com
Valid: ma-a.aa@hostname.com.edu
Valid: ma-a@hostname.com
Valid: ma-a@hostname.com.edu
Valid: ma-a@1hostname.com
Valid: ma.a@1hostname.com
Valid: ma@1hostname.com