如何使用python3搜索和替换文件中的文本?

这是我的代码:

import os
import sys
import fileinput

print ("Text to search for:")
textToSearch = input( "> " )

print ("Text to replace it with:")
textToReplace = input( "> " )

print ("File to perform Search-Replace on:")
fileToSearch  = input( "> " )
#fileToSearch = 'D:\dummy1.txt'

tempFile = open( fileToSearch, 'r+' )

for line in fileinput.input( fileToSearch ):
    if textToSearch in line :
        print('Match Found')
    else:
        print('Match Not Found!!')
    tempFile.write( line.replace( textToSearch, textToReplace ) )
tempFile.close()


input( '\n\n Press Enter to exit...' )

输入文件:

hi this is abcd hi this is abcd
This is dummy text file.
This is how search and replace works abcd

当我在上面的输入文件中搜索并将“ram”替换为“abcd”时,它就像一个咒语。但当我反过来做,即替换'abcd'由'ram',一些垃圾字符被留在最后。

将'abcd'替换为'ram'

hi this is ram hi this is ram
This is dummy text file.
This is how search and replace works rambcd

当前回答

Fileinput已经支持就地编辑。在这种情况下,它将stdout重定向到文件:

#!/usr/bin/env python3
import fileinput

with fileinput.FileInput(filename, inplace=True, backup='.bak') as file:
    for line in file:
        print(line.replace(text_to_search, replacement_text), end='')

其他回答

Besides the answers already mentioned, here is an explanation of why you have some random characters at the end: You are opening the file in r+ mode, not w mode. The key difference is that w mode clears the contents of the file as soon as you open it, whereas r+ doesn't. This means that if your file content is "123456789" and you write "www" to it, you get "www456789". It overwrites the characters with the new input, but leaves any remaining input untouched. You can clear a section of the file contents by using truncate(<startPosition>), but you are probably best off saving the updated file content to a string first, then doing truncate(0) and writing it all at once. Or you can use my library :D

你可以在python中使用sed、awk或grep(有一些限制)。这里有一个非常简单的例子。它在文件中把香蕉变成香蕉牙膏。你可以编辑和使用它。(我测试过了…注意:如果你在Windows下测试,你应该先安装sed命令并设置路径)

import os 
file="a.txt"
oldtext="Banana"
newtext=" BananaToothpaste"
os.system('sed -i "s/{}/{}/g" {}'.format(oldtext,newtext,file))
#print(f'sed -i "s/{oldtext}/{newtext}/g" {file}')
print('This command was applied:  sed -i "s/{}/{}/g" {}'.format(oldtext,newtext,file))

如果你想直接在文件上看到结果,应用:"type" for windows/ "cat" for linux:

####FOR WINDOWS:
os.popen("type " + file).read()
####FOR LINUX:
os.popen("cat " + file).read()

以读模式打开文件。以字符串格式读取文件。替换文本。关闭文件。再次以写模式打开文件。最后,将替换后的文本写入相同的文件。

try:
    with open("file_name", "r+") as text_file:
        texts = text_file.read()
        texts = texts.replace("to_replace", "replace_string")
    with open(file_name, "w") as text_file:
        text_file.write(texts)
except FileNotFoundError as f:
    print("Could not find the file you are trying to read.")

你可以这样做替换

f1 = open('file1.txt', 'r')
f2 = open('file2.txt', 'w')
for line in f1:
    f2.write(line.replace('old_text', 'new_text'))
f1.close()
f2.close()

我稍微修改了Jayram Singh的帖子,以替换每一个'!'字符转换为一个数字,我想在每个实例中增加这个数字。我想这对那些想要修改每行出现不止一次的字符并且想要迭代的人可能会有帮助。希望这能帮助到别人。PS-我在编码方面很新,所以如果我的帖子在任何方面都不合适,我很抱歉,但这对我来说是有效的。

f1 = open('file1.txt', 'r')
f2 = open('file2.txt', 'w')
n = 1  

# if word=='!'replace w/ [n] & increment n; else append same word to     
# file2

for line in f1:
    for word in line:
        if word == '!':
            f2.write(word.replace('!', f'[{n}]'))
            n += 1
        else:
            f2.write(word)
f1.close()
f2.close()