我想用H:MM:SS这样的模式以秒为单位格式化持续时间。java中当前的实用程序设计用于格式化时间,而不是持续时间。


当前回答

如果你不想拖进库,使用Formatter或相关的快捷方式就足够简单了。给定整数秒数s:

  String.format("%d:%02d:%02d", s / 3600, (s % 3600) / 60, (s % 60));

其他回答

这可能有点俗气,但如果你决心使用Java 8的Java .time来实现这一点,这是一个很好的解决方案:

import java.time.Duration;
import java.time.LocalDateTime;
import java.time.format.DateTimeFormatter;
import java.time.format.DateTimeFormatterBuilder;
import java.time.temporal.ChronoField;
import java.time.temporal.Temporal;
import java.time.temporal.TemporalAccessor;
import java.time.temporal.TemporalField;
import java.time.temporal.UnsupportedTemporalTypeException;

public class TemporalDuration implements TemporalAccessor {
    private static final Temporal BASE_TEMPORAL = LocalDateTime.of(0, 1, 1, 0, 0);

    private final Duration duration;
    private final Temporal temporal;

    public TemporalDuration(Duration duration) {
        this.duration = duration;
        this.temporal = duration.addTo(BASE_TEMPORAL);
    }

    @Override
    public boolean isSupported(TemporalField field) {
        if(!temporal.isSupported(field)) return false;
        long value = temporal.getLong(field)-BASE_TEMPORAL.getLong(field);
        return value!=0L;
    }

    @Override
    public long getLong(TemporalField field) {
        if(!isSupported(field)) throw new UnsupportedTemporalTypeException(new StringBuilder().append(field.toString()).toString());
        return temporal.getLong(field)-BASE_TEMPORAL.getLong(field);
    }

    public Duration getDuration() {
        return duration;
    }

    @Override
    public String toString() {
        return dtf.format(this);
    }

    private static final DateTimeFormatter dtf = new DateTimeFormatterBuilder()
            .optionalStart()//second
            .optionalStart()//minute
            .optionalStart()//hour
            .optionalStart()//day
            .optionalStart()//month
            .optionalStart()//year
            .appendValue(ChronoField.YEAR).appendLiteral(" Years ").optionalEnd()
            .appendValue(ChronoField.MONTH_OF_YEAR).appendLiteral(" Months ").optionalEnd()
            .appendValue(ChronoField.DAY_OF_MONTH).appendLiteral(" Days ").optionalEnd()
            .appendValue(ChronoField.HOUR_OF_DAY).appendLiteral(" Hours ").optionalEnd()
            .appendValue(ChronoField.MINUTE_OF_HOUR).appendLiteral(" Minutes ").optionalEnd()
            .appendValue(ChronoField.SECOND_OF_MINUTE).appendLiteral(" Seconds").optionalEnd()
            .toFormatter();

}

下面是在Kotlin中将java.time.Duration转换为一个漂亮的字符串的一行代码:

duration.run {
   "%d:%02d:%02d.%03d".format(toHours(), toMinutesPart(), toSecondsPart(), toMillisPart())
}

示例输出: 120:56:03.004

long duration = 4 * 60 * 60 * 1000;
SimpleDateFormat sdf = new SimpleDateFormat("HH:mm:ss.SSS", Locale.getDefault());
log.info("Duration: " + sdf.format(new Date(duration - TimeZone.getDefault().getRawOffset())));

使用这个func

private static String strDuration(long duration) {
    int ms, s, m, h, d;
    double dec;
    double time = duration * 1.0;

    time = (time / 1000.0);
    dec = time % 1;
    time = time - dec;
    ms = (int)(dec * 1000);

    time = (time / 60.0);
    dec = time % 1;
    time = time - dec;
    s = (int)(dec * 60);

    time = (time / 60.0);
    dec = time % 1;
    time = time - dec;
    m = (int)(dec * 60);

    time = (time / 24.0);
    dec = time % 1;
    time = time - dec;
    h = (int)(dec * 24);
    
    d = (int)time;
    
    return (String.format("%d d - %02d:%02d:%02d.%03d", d, h, m, s, ms));
}

我的库Time4J提供了一个基于模式的解决方案(类似于Apache DurationFormatUtils,但更灵活):

Duration<ClockUnit> duration =
    Duration.of(-573421, ClockUnit.SECONDS) // input in seconds only
    .with(Duration.STD_CLOCK_PERIOD); // performs normalization to h:mm:ss-structure
String fs = Duration.formatter(ClockUnit.class, "+##h:mm:ss").format(duration);
System.out.println(fs); // output => -159:17:01

这段代码演示了处理小时溢出和符号处理的功能,请参见基于模式的持续时间格式化程序的API。