场景:用户点击视图控制器上的按钮。视图控制器是导航堆栈中最顶层的(很明显)。tap调用在另一个类上调用的实用程序类方法。这里发生了不好的事情我想在控件返回到视图控制器之前在那里显示一个警告。
+ (void)myUtilityMethod {
// do stuff
// something bad happened, display an alert.
}
这是可能的UIAlertView(但可能不太合适)。
在这种情况下，你如何在myUtilityMethod中呈现UIAlertController ?
当前回答
你可以使用两种方法:
-使用UIAlertView或'UIActionSheet'代替(不推荐，因为它在iOS 8中已弃用，但现在可以使用了)
-记得上次显示的视图控制器。举个例子。
@interface UIViewController (TopController)
+ (UIViewController *)topViewController;
@end
// implementation
#import "UIViewController+TopController.h"
#import <objc/runtime.h>
static __weak UIViewController *_topViewController = nil;
@implementation UIViewController (TopController)
+ (UIViewController *)topViewController {
UIViewController *vc = _topViewController;
while (vc.parentViewController) {
vc = vc.parentViewController;
}
return vc;
}
+ (void)load {
[super load];
[self swizzleSelector:@selector(viewDidAppear:) withSelector:@selector(myViewDidAppear:)];
[self swizzleSelector:@selector(viewWillDisappear:) withSelector:@selector(myViewWillDisappear:)];
}
- (void)myViewDidAppear:(BOOL)animated {
if (_topViewController == nil) {
_topViewController = self;
}
[self myViewDidAppear:animated];
}
- (void)myViewWillDisappear:(BOOL)animated {
if (_topViewController == self) {
_topViewController = nil;
}
[self myViewWillDisappear:animated];
}
+ (void)swizzleSelector:(SEL)sel1 withSelector:(SEL)sel2
{
Class class = [self class];
Method originalMethod = class_getInstanceMethod(class, sel1);
Method swizzledMethod = class_getInstanceMethod(class, sel2);
BOOL didAddMethod = class_addMethod(class,
sel1,
method_getImplementation(swizzledMethod),
method_getTypeEncoding(swizzledMethod));
if (didAddMethod) {
class_replaceMethod(class,
sel2,
method_getImplementation(originalMethod),
method_getTypeEncoding(originalMethod));
} else {
method_exchangeImplementations(originalMethod, swizzledMethod);
}
}
@end
用法:
[[UIViewController topViewController] presentViewController:alertController ...];
其他回答
斯威夫特5
在显示消息后隐藏窗口是很重要的。
func showErrorMessage(_ message: String) {
let alertWindow = UIWindow(frame: UIScreen.main.bounds)
alertWindow.rootViewController = UIViewController()
let alertController = UIAlertController(title: "Error", message: message, preferredStyle: UIAlertController.Style.alert)
alertController.addAction(UIAlertAction(title: "Close", style: UIAlertAction.Style.cancel, handler: { _ in
alertWindow.isHidden = true
}))
alertWindow.windowLevel = UIWindow.Level.alert + 1;
alertWindow.makeKeyAndVisible()
alertWindow.rootViewController?.present(alertController, animated: true, completion: nil)
}
下面的解决方案没有发挥作用，尽管它在所有版本中看起来都很有前途。这个解决方案正在生成WARNING。
警告:试图显示不在窗口层次结构中的视图!
https://stackoverflow.com/a/34487871/2369867 = > 这在当时看起来很有希望。但在Swift 3中没有。 所以我在Swift 3中回答这个问题，这不是模板示例。
一旦粘贴到任何函数中，这是相当完整的功能代码。
快速Swift 3自包含代码
let alertController = UIAlertController(title: "<your title>", message: "<your message>", preferredStyle: UIAlertControllerStyle.alert)
alertController.addAction(UIAlertAction(title: "Close", style: UIAlertActionStyle.cancel, handler: nil))
let alertWindow = UIWindow(frame: UIScreen.main.bounds)
alertWindow.rootViewController = UIViewController()
alertWindow.windowLevel = UIWindowLevelAlert + 1;
alertWindow.makeKeyAndVisible()
alertWindow.rootViewController?.present(alertController, animated: true, completion: nil)
这是在Swift 3中测试和工作的代码。
似乎有效:
static UIViewController *viewControllerForView(UIView *view) {
UIResponder *responder = view;
do {
responder = [responder nextResponder];
}
while (responder && ![responder isKindOfClass:[UIViewController class]]);
return (UIViewController *)responder;
}
-(void)showActionSheet {
UIAlertController *alertController = [UIAlertController alertControllerWithTitle:nil message:nil preferredStyle:UIAlertControllerStyleActionSheet];
[alertController addAction:[UIAlertAction actionWithTitle:@"Cancel" style:UIAlertActionStyleCancel handler:nil]];
[alertController addAction:[UIAlertAction actionWithTitle:@"Do it" style:UIAlertActionStyleDefault handler:nil]];
[viewControllerForView(self) presentViewController:alertController animated:YES completion:nil];
}
对于iOS 13，基于mythicalcoder和bobbyrehm的回答:
在iOS 13中，如果你正在创建自己的窗口来显示警报，你需要保持对该窗口的强引用，否则你的警报将不会显示，因为当它的引用退出作用域时，窗口将立即被释放。
此外，在警报解除后，您需要再次将引用设置为nil，以便删除窗口，继续允许用户在它下面的主窗口上进行交互。
你可以创建一个UIViewController子类来封装窗口内存管理逻辑:
class WindowAlertPresentationController: UIViewController {
// MARK: - Properties
private lazy var window: UIWindow? = UIWindow(frame: UIScreen.main.bounds)
private let alert: UIAlertController
// MARK: - Initialization
init(alert: UIAlertController) {
self.alert = alert
super.init(nibName: nil, bundle: nil)
}
required init?(coder aDecoder: NSCoder) {
fatalError("This initializer is not supported")
}
// MARK: - Presentation
func present(animated: Bool, completion: (() -> Void)?) {
window?.rootViewController = self
window?.windowLevel = UIWindow.Level.alert + 1
window?.makeKeyAndVisible()
present(alert, animated: animated, completion: completion)
}
// MARK: - Overrides
override func dismiss(animated flag: Bool, completion: (() -> Void)? = nil) {
super.dismiss(animated: flag) {
self.window = nil
completion?()
}
}
}
你可以这样使用它，或者如果你想在你的UIAlertController上使用一个方便的方法，你可以把它扔到一个扩展中:
extension UIAlertController {
func presentInOwnWindow(animated: Bool, completion: (() -> Void)?) {
let windowAlertPresentationController = WindowAlertPresentationController(alert: self)
windowAlertPresentationController.present(animated: animated, completion: completion)
}
}
在Objective-C中显示警报的简单方法:
[[[[UIApplication sharedApplication] keyWindow] rootViewController] presentViewController:alertController animated:YES completion:nil];
alertController是你的UIAlertController对象。
注意:你还需要确保你的助手类扩展了UIViewController
