我试图使用片段与一个ViewPager使用FragmentPagerAdapter。 我想要实现的是替换一个片段,位于ViewPager的第一页,与另一个。

寻呼机由两个页面组成。第一个是FirstPagerFragment,第二个是SecondPagerFragment。点击第一页的一个按钮。我想用NextFragment替换FirstPagerFragment。

下面是我的代码。

public class FragmentPagerActivity extends FragmentActivity {

    static final int NUM_ITEMS = 2;

    MyAdapter mAdapter;
    ViewPager mPager;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.fragment_pager);

        mAdapter = new MyAdapter(getSupportFragmentManager());

        mPager = (ViewPager) findViewById(R.id.pager);
        mPager.setAdapter(mAdapter);

    }


    /**
     * Pager Adapter
     */
    public static class MyAdapter extends FragmentPagerAdapter {
        public MyAdapter(FragmentManager fm) {
            super(fm);
        }

        @Override
        public int getCount() {
            return NUM_ITEMS;
        }

        @Override
        public Fragment getItem(int position) {

            if(position == 0) {
                return FirstPageFragment.newInstance();
            } else {
                return SecondPageFragment.newInstance();
            }

        }
    }


    /**
     * Second Page FRAGMENT
     */
    public static class SecondPageFragment extends Fragment {

        public static SecondPageFragment newInstance() {
            SecondPageFragment f = new SecondPageFragment();
            return f;
        }

        @Override
        public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
            //Log.d("DEBUG", "onCreateView");
            return inflater.inflate(R.layout.second, container, false);

        }
    }

    /**
     * FIRST PAGE FRAGMENT
     */
    public static class FirstPageFragment extends Fragment {

        Button button;

        public static FirstPageFragment newInstance() {
            FirstPageFragment f = new FirstPageFragment();
            return f;
        }

        @Override
        public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
            //Log.d("DEBUG", "onCreateView");
            View root = inflater.inflate(R.layout.first, container, false);
            button = (Button) root.findViewById(R.id.button);
            button.setOnClickListener(new OnClickListener() {

                @Override
                public void onClick(View v) {
                    FragmentTransaction trans = getFragmentManager().beginTransaction();
                                    trans.replace(R.id.first_fragment_root_id, NextFragment.newInstance());
                    trans.setTransition(FragmentTransaction.TRANSIT_FRAGMENT_OPEN);
                    trans.addToBackStack(null);
                    trans.commit();

                }

            });

            return root;
        }

        /**
     * Next Page FRAGMENT in the First Page
     */
    public static class NextFragment extends Fragment {

        public static NextFragment newInstance() {
            NextFragment f = new NextFragment();
            return f;
        }

        @Override
        public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
            //Log.d("DEBUG", "onCreateView");
            return inflater.inflate(R.layout.next, container, false);

        }
    }
}

...这里是XML文件

fragment_pager.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
        android:orientation="vertical" android:padding="4dip"
        android:gravity="center_horizontal"
        android:layout_width="match_parent" android:layout_height="match_parent">

    <android.support.v4.view.ViewPager
            android:id="@+id/pager"
            android:layout_width="match_parent"
            android:layout_height="match_parent"
            android:layout_weight="1">
    </android.support.v4.view.ViewPager>

</LinearLayout>

first.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
  android:id="@+id/first_fragment_root_id"
  android:orientation="vertical"
  android:layout_width="match_parent"
  android:layout_height="match_parent">

  <Button android:id="@+id/button"
     android:layout_width="wrap_content" android:layout_height="wrap_content"
     android:text="to next"/>

</LinearLayout>

现在的问题是……我应该使用哪个ID

trans.replace(R.id.first_fragment_root_id, NextFragment.newInstance());

?

如果我用r。id。first_fragment_root_id,替换工作,但Hierarchy Viewer显示一个奇怪的行为,如下所示。

一开始的情况是

更换后的情况是

正如你所看到的,有一些错误,我希望在替换片段后找到与第一张图片中相同的状态。


当前回答

我也做了一个解决方案,那就是与Stacks合作。这是一种更模块化的方法,所以你不必在FragmentPagerAdapter中指定每个Fragment和Detail Fragment。它建立在ActionbarSherlock的示例之上,如果我是对的,它来自谷歌演示应用程序。

/**
 * This is a helper class that implements the management of tabs and all
 * details of connecting a ViewPager with associated TabHost.  It relies on a
 * trick.  Normally a tab host has a simple API for supplying a View or
 * Intent that each tab will show.  This is not sufficient for switching
 * between pages.  So instead we make the content part of the tab host
 * 0dp high (it is not shown) and the TabsAdapter supplies its own dummy
 * view to show as the tab content.  It listens to changes in tabs, and takes
 * care of switch to the correct paged in the ViewPager whenever the selected
 * tab changes.
 * 
 * Changed to support more Layers of fragments on each Tab.
 * by sebnapi (2012)
 * 
 */
public class TabsAdapter extends FragmentPagerAdapter
        implements TabHost.OnTabChangeListener, ViewPager.OnPageChangeListener {
    private final Context mContext;
    private final TabHost mTabHost;
    private final ViewPager mViewPager;

    private ArrayList<String> mTabTags = new ArrayList<String>();
    private HashMap<String, Stack<TabInfo>> mTabStackMap = new HashMap<String, Stack<TabInfo>>();

    static final class TabInfo {
        public final String tag;
        public final Class<?> clss;
        public Bundle args;

        TabInfo(String _tag, Class<?> _class, Bundle _args) {
            tag = _tag;
            clss = _class;
            args = _args;
        }
    }

    static class DummyTabFactory implements TabHost.TabContentFactory {
        private final Context mContext;

        public DummyTabFactory(Context context) {
            mContext = context;
        }

        @Override
        public View createTabContent(String tag) {
            View v = new View(mContext);
            v.setMinimumWidth(0);
            v.setMinimumHeight(0);
            return v;
        }
    }

    public interface SaveStateBundle{
        public Bundle onRemoveFragment(Bundle outState);
    }

    public TabsAdapter(FragmentActivity activity, TabHost tabHost, ViewPager pager) {
        super(activity.getSupportFragmentManager());
        mContext = activity;
        mTabHost = tabHost;
        mViewPager = pager;
        mTabHost.setOnTabChangedListener(this);
        mViewPager.setAdapter(this);
        mViewPager.setOnPageChangeListener(this);
    }

    /**
     * Add a Tab which will have Fragment Stack. Add Fragments on this Stack by using
     * addFragment(FragmentManager fm, String _tag, Class<?> _class, Bundle _args)
     * The Stack will hold always the default Fragment u add here.
     * 
     * DON'T ADD Tabs with same tag, it's not beeing checked and results in unexpected
     * beahvior.
     * 
     * @param tabSpec
     * @param clss
     * @param args
     */
    public void addTab(TabHost.TabSpec tabSpec, Class<?> clss, Bundle args){
        Stack<TabInfo> tabStack = new Stack<TabInfo>();

        tabSpec.setContent(new DummyTabFactory(mContext));
        mTabHost.addTab(tabSpec);
        String tag = tabSpec.getTag();
        TabInfo info = new TabInfo(tag, clss, args);

        mTabTags.add(tag);                  // to know the position of the tab tag 
        tabStack.add(info);
        mTabStackMap.put(tag, tabStack);
        notifyDataSetChanged();
    }

    /**
     * Will add the Fragment to Tab with the Tag _tag. Provide the Class of the Fragment
     * it will be instantiated by this object. Proivde _args for your Fragment.
     * 
     * @param fm
     * @param _tag
     * @param _class
     * @param _args
     */
    public void addFragment(FragmentManager fm, String _tag, Class<?> _class, Bundle _args){
        TabInfo info = new TabInfo(_tag, _class, _args);
        Stack<TabInfo> tabStack = mTabStackMap.get(_tag);   
        Fragment frag = fm.findFragmentByTag("android:switcher:" + mViewPager.getId() + ":" + mTabTags.indexOf(_tag));
        if(frag instanceof SaveStateBundle){
            Bundle b = new Bundle();
            ((SaveStateBundle) frag).onRemoveFragment(b);
            tabStack.peek().args = b;
        }
        tabStack.add(info);
        FragmentTransaction ft = fm.beginTransaction();
        ft.remove(frag).commit();
        notifyDataSetChanged();
    }

    /**
     * Will pop the Fragment added to the Tab with the Tag _tag
     * 
     * @param fm
     * @param _tag
     * @return
     */
    public boolean popFragment(FragmentManager fm, String _tag){
        Stack<TabInfo> tabStack = mTabStackMap.get(_tag);   
        if(tabStack.size()>1){
            tabStack.pop();
            Fragment frag = fm.findFragmentByTag("android:switcher:" + mViewPager.getId() + ":" + mTabTags.indexOf(_tag));
            FragmentTransaction ft = fm.beginTransaction();
            ft.remove(frag).commit();
            notifyDataSetChanged();
            return true;
        }
        return false;
    }

    public boolean back(FragmentManager fm) {
        int position = mViewPager.getCurrentItem();
        return popFragment(fm, mTabTags.get(position));
    }

    @Override
    public int getCount() {
        return mTabStackMap.size();
    }

    @Override
    public int getItemPosition(Object object) {
        ArrayList<Class<?>> positionNoneHack = new ArrayList<Class<?>>();
        for(Stack<TabInfo> tabStack: mTabStackMap.values()){
            positionNoneHack.add(tabStack.peek().clss);
        }   // if the object class lies on top of our stacks, we return default
        if(positionNoneHack.contains(object.getClass())){
            return POSITION_UNCHANGED;
        }
        return POSITION_NONE;
    }

    @Override
    public Fragment getItem(int position) {
        Stack<TabInfo> tabStack = mTabStackMap.get(mTabTags.get(position));
        TabInfo info = tabStack.peek();
        return Fragment.instantiate(mContext, info.clss.getName(), info.args);
    }

    @Override
    public void onTabChanged(String tabId) {
        int position = mTabHost.getCurrentTab();
        mViewPager.setCurrentItem(position);
    }

    @Override
    public void onPageScrolled(int position, float positionOffset, int positionOffsetPixels) {
    }

    @Override
    public void onPageSelected(int position) {
        // Unfortunately when TabHost changes the current tab, it kindly
        // also takes care of putting focus on it when not in touch mode.
        // The jerk.
        // This hack tries to prevent this from pulling focus out of our
        // ViewPager.
        TabWidget widget = mTabHost.getTabWidget();
        int oldFocusability = widget.getDescendantFocusability();
        widget.setDescendantFocusability(ViewGroup.FOCUS_BLOCK_DESCENDANTS);
        mTabHost.setCurrentTab(position);
        widget.setDescendantFocusability(oldFocusability);
    }

    @Override
    public void onPageScrollStateChanged(int state) {
    }

}

在MainActivity中添加后退按钮功能:

@Override
public void onBackPressed() {
  if (!mTabsAdapter.back(getSupportFragmentManager())) {
    super.onBackPressed();
  }
}

如果你想保存碎片状态,当它被删除。让你的Fragment实现接口SaveStateBundle在函数中返回一个带有你保存状态的bundle。通过this.getArguments()获得实例化后的bundle。

你可以这样实例化一个标签:

mTabsAdapter.addTab(mTabHost.newTabSpec("firstTabTag").setIndicator("First Tab Title"),
                FirstFragmentActivity.FirstFragmentFragment.class, null);

工作类似,如果你想添加一个片段在标签堆栈的顶部。 重要:我认为,如果你想在两个tab上有两个相同类的实例,这是行不通的。 我在一起很快就解决了这个问题,所以我只能分享它,没有提供任何经验。

其他回答

我已经创建了一个ViewPager 3个元素和2个子元素的索引2和3和这里我想做的。

我已经在StackOverFlow之前的问题和答案的帮助下实现了这一点,这里是链接。

ViewPagerChildFragments

我做了一些类似于wize的事情,但在我的回答中,你可以随时在两个片段之间更改。在改变屏幕方向之类的时候,我遇到了一些问题。这是PagerAdapter的样子:

    public class MyAdapter extends FragmentPagerAdapter
{
    static final int NUM_ITEMS = 2;
    private final FragmentManager mFragmentManager;
    private Fragment mFragmentAtPos0;
     private Map<Integer, String> mFragmentTags;
     private boolean isNextFragment=false;

    public MyAdapter(FragmentManager fm)
    {
        super(fm);
        mFragmentManager = fm;
         mFragmentTags = new HashMap<Integer, String>();
    }

    @Override
    public Fragment getItem(int position)
    {
        if (position == 0)
        {


            if (isPager) {
                mFragmentAtPos0 = new FirstPageFragment();
            } else {
                mFragmentAtPos0 = new NextFragment();
            }
            return mFragmentAtPos0;
        }
        else
            return SecondPageFragment.newInstance();
    }

    @Override
    public int getCount()
    {
        return NUM_ITEMS;
    }


 @Override
    public Object instantiateItem(ViewGroup container, int position) {
        Object obj = super.instantiateItem(container, position);
        if (obj instanceof Fragment) {
            // record the fragment tag here.
            Fragment f = (Fragment) obj;
            String tag = f.getTag();
            mFragmentTags.put(position, tag);
        }
        return obj;
    }


    public void onChange(boolean isNextFragment) {

        if (mFragmentAtPos0 == null)
            mFragmentAtPos0 = getFragment(0);
        if (mFragmentAtPos0 != null)
            mFragmentManager.beginTransaction().remove(mFragmentAtPos0).commit();


        if (!isNextFragment) {
            mFragmentAtFlashcards = new FirstPageFragment();
        } else {
            mFragmentAtFlashcards = new NextFragment();
        }

        notifyDataSetChanged();


    }


    @Override
    public int getItemPosition(Object object)
    {
        if (object instanceof FirstPageFragment && mFragmentAtPos0 instanceof NextFragment)
            return POSITION_NONE;
         if (object instanceof NextFragment && mFragmentAtPos0 instanceof FirstPageFragment)
            return POSITION_NONE;
        return POSITION_UNCHANGED;
    }


    public Fragment getFragment(int position) {
        String tag = mFragmentTags.get(position);
        if (tag == null)
            return null;
        return mFragmentManager.findFragmentByTag(tag);
    }
}

我在适配器容器活动中实现的侦听器,用于在附加片段时将其放到片段中,这是活动:

    public class PagerContainerActivity extends AppCompatActivity implements ChangeFragmentListener {

//...

  @Override
    public void onChange(boolean isNextFragment) {
        if (pagerAdapter != null)
            pagerAdapter.onChange(isNextFragment);


    }

//...
}

然后在片段中放置侦听器,当附加调用它:

public class FirstPageFragment extends Fragment{


private ChangeFragmentListener changeFragmentListener;


//...
 @Override
    public void onAttach(Activity activity) {
        super.onAttach(activity);
        changeFragmentListener = ((PagerContainerActivity) activity);
    }

    @Override
    public void onDetach() {
        super.onDetach();
        changeFragmentListener = null;
    }
//...
//in the on click to change the fragment
changeFragmentListener.onChange(true);
//...
}

最后是听众:

public interface changeFragmentListener {

    void onChange(boolean isNextFragment);

}

Here's my relatively simple solution to this problem. The keys to this solution are to use FragmentStatePagerAdapter instead of FragmentPagerAdapter as the former will remove unused fragments for you while the later still retains their instances. The second is the use of POSITION_NONE in getItem(). I've used a simple List to keep track of my fragments. My requirement was to replace the entire list of fragments at once with a new list, but the below could be easily modified to replace individual fragments:

public class MyFragmentAdapter extends FragmentStatePagerAdapter {
    private List<Fragment> fragmentList = new ArrayList<Fragment>();
    private List<String> tabTitleList = new ArrayList<String>();

    public MyFragmentAdapter(FragmentManager fm) {
        super(fm);
    }

    public void addFragments(List<Fragment> fragments, List<String> titles) {
        fragmentList.clear();
        tabTitleList.clear();
        fragmentList.addAll(fragments);
        tabTitleList.addAll(titles);
        notifyDataSetChanged();
    }

    @Override
    public int getItemPosition(Object object) {
        if (fragmentList.contains(object)) {
            return POSITION_UNCHANGED;
        }
        return POSITION_NONE;
    }

    @Override
    public Fragment getItem(int item) {
        if (item >= fragmentList.size()) {
            return null;
        }
        return fragmentList.get(item);
    }

    @Override
    public int getCount() {
        return fragmentList.size();
    }

    @Override
    public CharSequence getPageTitle(int position) {
        return tabTitleList.get(position);
    }
}

还有另一种解决方案,不需要修改ViewPager和FragmentStatePagerAdapter的源代码,它与作者使用的FragmentPagerAdapter基类一起工作。

我想先回答作者的问题,他应该使用哪个ID;它是容器的ID,也就是视图分页器本身的ID。但是,正如您自己可能注意到的那样,在代码中使用该ID不会发生任何事情。我将解释为什么:

首先,要使ViewPager重新填充页面,需要调用驻留在适配器基类中的notifyDataSetChanged()。

其次,ViewPager使用getItemPosition()抽象方法来检查哪些页面应该销毁,哪些页面应该保留。这个函数的默认实现总是返回POSITION_UNCHANGED,这将导致ViewPager保留所有当前页面,从而不会附加新页面。因此,为了使片段替换工作,getItemPosition()需要在适配器中被重写,并且在使用旧的、要隐藏的片段作为参数调用时必须返回POSITION_NONE。

这也意味着你的适配器总是需要知道哪个片段应该显示在位置0,FirstPageFragment还是NextFragment。一种方法是在创建FirstPageFragment时提供一个侦听器,当切换片段时将调用该侦听器。我认为这是一件好事,让你的片段适配器处理所有的片段切换和调用ViewPager和FragmentManager。

第三,FragmentPagerAdapter通过从位置派生的名称来缓存使用的片段,因此,如果在位置0有一个片段,即使类是新的,它也不会被替换。有两种解决方案,但最简单的是使用FragmentTransaction的remove()函数,该函数也将删除其标记。

这是大量的文本,这里是代码,应该在你的情况下工作:

public class MyAdapter extends FragmentPagerAdapter
{
    static final int NUM_ITEMS = 2;
    private final FragmentManager mFragmentManager;
    private Fragment mFragmentAtPos0;

    public MyAdapter(FragmentManager fm)
    {
        super(fm);
        mFragmentManager = fm;
    }

    @Override
    public Fragment getItem(int position)
    {
        if (position == 0)
        {
            if (mFragmentAtPos0 == null)
            {
                mFragmentAtPos0 = FirstPageFragment.newInstance(new FirstPageFragmentListener()
                {
                    public void onSwitchToNextFragment()
                    {
                        mFragmentManager.beginTransaction().remove(mFragmentAtPos0).commit();
                        mFragmentAtPos0 = NextFragment.newInstance();
                        notifyDataSetChanged();
                    }
                });
            }
            return mFragmentAtPos0;
        }
        else
            return SecondPageFragment.newInstance();
    }

    @Override
    public int getCount()
    {
        return NUM_ITEMS;
    }

    @Override
    public int getItemPosition(Object object)
    {
        if (object instanceof FirstPageFragment && mFragmentAtPos0 instanceof NextFragment)
            return POSITION_NONE;
        return POSITION_UNCHANGED;
    }
}

public interface FirstPageFragmentListener
{
    void onSwitchToNextFragment();
}

我按照@wize和@mdelolmo的答案,我得到了解决方案。由于吨。但是,我稍微调整了这些解决方案,以提高内存消耗。

我观察到的问题:

它们保存被替换的Fragment实例。在我的情况下,它是一个持有MapView的片段,我认为它的成本很高。所以,我维护FragmentPagerPositionChanged (POSITION_NONE或POSITION_UNCHANGED)而不是Fragment本身。

这是我的实现。

  public static class DemoCollectionPagerAdapter extends FragmentStatePagerAdapter {

    private SwitchFragListener mSwitchFragListener;
    private Switch mToggle;
    private int pagerAdapterPosChanged = POSITION_UNCHANGED;
    private static final int TOGGLE_ENABLE_POS = 2;


    public DemoCollectionPagerAdapter(FragmentManager fm, Switch toggle) {
        super(fm);
        mToggle = toggle;

        mSwitchFragListener = new SwitchFragListener();
        mToggle.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
            @Override
            public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
                mSwitchFragListener.onSwitchToNextFragment();
            }
        });
    }

    @Override
    public Fragment getItem(int i) {
        switch (i)
        {
            case TOGGLE_ENABLE_POS:
                if(mToggle.isChecked())
                {
                    return TabReplaceFragment.getInstance();
                }else
                {
                    return DemoTab2Fragment.getInstance(i);
                }

            default:
                return DemoTabFragment.getInstance(i);
        }
    }

    @Override
    public int getCount() {
        return 5;
    }

    @Override
    public CharSequence getPageTitle(int position) {
        return "Tab " + (position + 1);
    }

    @Override
    public int getItemPosition(Object object) {

        //  This check make sures getItem() is called only for the required Fragment
        if (object instanceof TabReplaceFragment
                ||  object instanceof DemoTab2Fragment)
            return pagerAdapterPosChanged;

        return POSITION_UNCHANGED;
    }

    /**
     * Switch fragments Interface implementation
     */
    private final class SwitchFragListener implements
            SwitchFragInterface {

        SwitchFragListener() {}

        public void onSwitchToNextFragment() {

            pagerAdapterPosChanged = POSITION_NONE;
            notifyDataSetChanged();
        }
    }

    /**
     * Interface to switch frags
     */
    private interface SwitchFragInterface{
        void onSwitchToNextFragment();
    }
}

演示链接在这里..https://youtu.be/l_62uhKkLyM

出于演示目的,在位置2处使用了两个片段TabReplaceFragment和DemoTab2Fragment。在所有其他情况下,我使用DemoTabFragment实例。

解释:

我将Switch从Activity传递到DemoCollectionPagerAdapter。基于这个开关的状态,我们将显示正确的片段。当开关检查被更改时,我调用SwitchFragListener的onSwitchToNextFragment方法,其中我将pagerAdapterPosChanged变量的值更改为POSITION_NONE。查看更多关于POSITION_NONE的信息。这将使getItem无效,我有逻辑实例化正确的片段在那里。抱歉,如果解释得有点乱的话。

再次感谢@wize和@mdelolmo的原创想法。

希望这对你有帮助。:)

如果这个实现有任何缺陷,请告诉我。那将对我的项目大有帮助。