我已经创建了一个ViewPager 3个元素和2个子元素的索引2和3和这里我想做的。

我已经在StackOverFlow之前的问题和答案的帮助下实现了这一点，这里是链接。

ViewPagerChildFragments

Here's my relatively simple solution to this problem. The keys to this solution are to use FragmentStatePagerAdapter instead of FragmentPagerAdapter as the former will remove unused fragments for you while the later still retains their instances. The second is the use of POSITION_NONE in getItem(). I've used a simple List to keep track of my fragments. My requirement was to replace the entire list of fragments at once with a new list, but the below could be easily modified to replace individual fragments:

public class MyFragmentAdapter extends FragmentStatePagerAdapter {
    private List<Fragment> fragmentList = new ArrayList<Fragment>();
    private List<String> tabTitleList = new ArrayList<String>();

    public MyFragmentAdapter(FragmentManager fm) {
        super(fm);
    }

    public void addFragments(List<Fragment> fragments, List<String> titles) {
        fragmentList.clear();
        tabTitleList.clear();
        fragmentList.addAll(fragments);
        tabTitleList.addAll(titles);
        notifyDataSetChanged();
    }

    @Override
    public int getItemPosition(Object object) {
        if (fragmentList.contains(object)) {
            return POSITION_UNCHANGED;
        }
        return POSITION_NONE;
    }

    @Override
    public Fragment getItem(int item) {
        if (item >= fragmentList.size()) {
            return null;
        }
        return fragmentList.get(item);
    }

    @Override
    public int getCount() {
        return fragmentList.size();
    }

    @Override
    public CharSequence getPageTitle(int position) {
        return tabTitleList.get(position);
    }
}

在你的onCreateView方法中，容器实际上是一个ViewPager实例。

所以，只是打电话

ViewPager vpViewPager = (ViewPager) container;
vpViewPager.setCurrentItem(1);

将改变当前片段在你的ViewPager。

经过研究，我找到了短代码的解决方案。 首先，在fragment上创建一个公共实例，如果fragment没有在方向改变上重新创建，则在onSaveInstanceState上删除你的fragment。

 @Override
public void onSaveInstanceState(Bundle outState) {
    if (null != mCalFragment) {
        FragmentTransaction bt = getChildFragmentManager().beginTransaction();
        bt.remove(mFragment);
        bt.commit();
    }
    super.onSaveInstanceState(outState);
}

要替换ViewPager中的片段，你可以将ViewPager、PagerAdapter和FragmentStatePagerAdapter类的源代码移动到你的项目中，并添加以下代码。

分为:viewpage:

public void notifyItemChanged(Object oldItem, Object newItem) {
    if (mItems != null) {
            for (ItemInfo itemInfo : mItems) {
                        if (itemInfo.object.equals(oldItem)) {
                                itemInfo.object = newItem;
                        }
                    }
       }
       invalidate();
    }

FragmentStatePagerAdapter:

public void replaceFragmetns(ViewPager container, Fragment oldFragment, Fragment newFragment) {
       startUpdate(container);

       // remove old fragment

       if (mCurTransaction == null) {
            mCurTransaction = mFragmentManager.beginTransaction();
        }
       int position = getFragmentPosition(oldFragment);
        while (mSavedState.size() <= position) {
            mSavedState.add(null);
        }
        mSavedState.set(position, null);
        mFragments.set(position, null);

        mCurTransaction.remove(oldFragment);

        // add new fragment

        while (mFragments.size() <= position) {
            mFragments.add(null);
        }
        mFragments.set(position, newFragment);
        mCurTransaction.add(container.getId(), newFragment);

       finishUpdate(container);

       // ensure getItem returns newFragemtn after calling handleGetItemInbalidated()
       handleGetItemInbalidated(container, oldFragment, newFragment);

       container.notifyItemChanged(oldFragment, newFragment);
    }

protected abstract void handleGetItemInbalidated(View container, Fragment oldFragment, Fragment newFragment);
protected abstract int  getFragmentPosition(Fragment fragment);

handleGetItemInvalidated()确保下一次调用getItem()后返回newFragment getFragmentPosition()返回片段在适配器中的位置。

现在，替换片段调用

mAdapter.replaceFragmetns(mViewPager, oldFragment, newFragment);

如果你对一个示例项目感兴趣，请向我索取资源。

Works Great with AndroidTeam's solution, however I found that I needed the ability to go back much like FrgmentTransaction.addToBackStack(null) But merely adding this will only cause the Fragment to be replaced without notifying the ViewPager. Combining the provided solution with this minor enhancement will allow you to return to the previous state by merely overriding the activity's onBackPressed() method. The biggest drawback is that it will only go back one at a time which may result in multiple back clicks

private ArrayList<Fragment> bFragments = new ArrayList<Fragment>();
private ArrayList<Integer> bPosition = new ArrayList<Integer>();

public void replaceFragmentsWithBackOut(ViewPager container, Fragment oldFragment, Fragment newFragment) {
    startUpdate(container);

    // remove old fragment

    if (mCurTransaction == null) {
         mCurTransaction = mFragmentManager.beginTransaction();
     }
    int position = getFragmentPosition(oldFragment);
     while (mSavedState.size() <= position) {
         mSavedState.add(null);
     }

     //Add Fragment to Back List
     bFragments.add(oldFragment);

     //Add Pager Position to Back List
     bPosition.add(position);

     mSavedState.set(position, null);
     mFragments.set(position, null);

     mCurTransaction.remove(oldFragment);

     // add new fragment

     while (mFragments.size() <= position) {
         mFragments.add(null);
     }
     mFragments.set(position, newFragment);
     mCurTransaction.add(container.getId(), newFragment);

    finishUpdate(container);

    // ensure getItem returns newFragemtn after calling handleGetItemInbalidated()
    handleGetItemInvalidated(container, oldFragment, newFragment);

    container.notifyItemChanged(oldFragment, newFragment);
 }


public boolean popBackImmediate(ViewPager container){
    int bFragSize = bFragments.size();
    int bPosSize = bPosition.size();

    if(bFragSize>0 && bPosSize>0){
        if(bFragSize==bPosSize){
            int last = bFragSize-1;
            int position = bPosition.get(last);

            //Returns Fragment Currently at this position
            Fragment replacedFragment = mFragments.get(position);               
            Fragment originalFragment = bFragments.get(last);

            this.replaceFragments(container, replacedFragment, originalFragment);

            bPosition.remove(last);
            bFragments.remove(last);

            return true;
        }
    }

    return false;       
}

希望这能帮助到一些人。

同样，就getFragmentPosition()而言，它几乎是反向的getItem()。你知道哪些片段去哪里，只是确保你返回正确的位置它将在。这里有一个例子:

    @Override
    protected int getFragmentPosition(Fragment fragment) {
            if(fragment.equals(originalFragment1)){
                return 0;
            }
            if(fragment.equals(replacementFragment1)){
                return 0;
            }
            if(fragment.equals(Fragment2)){
                return 1;
            }
        return -1;
    }