Works Great with AndroidTeam's solution, however I found that I needed the ability to go back much like FrgmentTransaction.addToBackStack(null) But merely adding this will only cause the Fragment to be replaced without notifying the ViewPager. Combining the provided solution with this minor enhancement will allow you to return to the previous state by merely overriding the activity's onBackPressed() method. The biggest drawback is that it will only go back one at a time which may result in multiple back clicks

private ArrayList<Fragment> bFragments = new ArrayList<Fragment>();
private ArrayList<Integer> bPosition = new ArrayList<Integer>();

public void replaceFragmentsWithBackOut(ViewPager container, Fragment oldFragment, Fragment newFragment) {
    startUpdate(container);

    // remove old fragment

    if (mCurTransaction == null) {
         mCurTransaction = mFragmentManager.beginTransaction();
     }
    int position = getFragmentPosition(oldFragment);
     while (mSavedState.size() <= position) {
         mSavedState.add(null);
     }

     //Add Fragment to Back List
     bFragments.add(oldFragment);

     //Add Pager Position to Back List
     bPosition.add(position);

     mSavedState.set(position, null);
     mFragments.set(position, null);

     mCurTransaction.remove(oldFragment);

     // add new fragment

     while (mFragments.size() <= position) {
         mFragments.add(null);
     }
     mFragments.set(position, newFragment);
     mCurTransaction.add(container.getId(), newFragment);

    finishUpdate(container);

    // ensure getItem returns newFragemtn after calling handleGetItemInbalidated()
    handleGetItemInvalidated(container, oldFragment, newFragment);

    container.notifyItemChanged(oldFragment, newFragment);
 }


public boolean popBackImmediate(ViewPager container){
    int bFragSize = bFragments.size();
    int bPosSize = bPosition.size();

    if(bFragSize>0 && bPosSize>0){
        if(bFragSize==bPosSize){
            int last = bFragSize-1;
            int position = bPosition.get(last);

            //Returns Fragment Currently at this position
            Fragment replacedFragment = mFragments.get(position);               
            Fragment originalFragment = bFragments.get(last);

            this.replaceFragments(container, replacedFragment, originalFragment);

            bPosition.remove(last);
            bFragments.remove(last);

            return true;
        }
    }

    return false;       
}

希望这能帮助到一些人。

同样，就getFragmentPosition()而言，它几乎是反向的getItem()。你知道哪些片段去哪里，只是确保你返回正确的位置它将在。这里有一个例子:

    @Override
    protected int getFragmentPosition(Fragment fragment) {
            if(fragment.equals(originalFragment1)){
                return 0;
            }
            if(fragment.equals(replacementFragment1)){
                return 0;
            }
            if(fragment.equals(Fragment2)){
                return 1;
            }
        return -1;
    }

tl;dr:使用一个主机片段，负责替换其托管内容，并跟踪回溯导航历史(如在浏览器中)。

由于您的用例由固定数量的选项卡组成，我的解决方案工作得很好:想法是用自定义类HostFragment的实例填充ViewPager，这能够替换其托管内容并保持自己的回溯导航历史。要替换托管的片段，你需要调用hostfragment.replaceFragment()方法:

public void replaceFragment(Fragment fragment, boolean addToBackstack) {
    if (addToBackstack) {
        getChildFragmentManager().beginTransaction().replace(R.id.hosted_fragment, fragment).addToBackStack(null).commit();
    } else {
        getChildFragmentManager().beginTransaction().replace(R.id.hosted_fragment, fragment).commit();
    }
}

该方法所做的就是用id R.id替换框架布局。Hosted_fragment和提供给方法的片段。

查看我关于这个主题的教程，了解更多细节和GitHub上完整的工作示例!

Here's my relatively simple solution to this problem. The keys to this solution are to use FragmentStatePagerAdapter instead of FragmentPagerAdapter as the former will remove unused fragments for you while the later still retains their instances. The second is the use of POSITION_NONE in getItem(). I've used a simple List to keep track of my fragments. My requirement was to replace the entire list of fragments at once with a new list, but the below could be easily modified to replace individual fragments:

public class MyFragmentAdapter extends FragmentStatePagerAdapter {
    private List<Fragment> fragmentList = new ArrayList<Fragment>();
    private List<String> tabTitleList = new ArrayList<String>();

    public MyFragmentAdapter(FragmentManager fm) {
        super(fm);
    }

    public void addFragments(List<Fragment> fragments, List<String> titles) {
        fragmentList.clear();
        tabTitleList.clear();
        fragmentList.addAll(fragments);
        tabTitleList.addAll(titles);
        notifyDataSetChanged();
    }

    @Override
    public int getItemPosition(Object object) {
        if (fragmentList.contains(object)) {
            return POSITION_UNCHANGED;
        }
        return POSITION_NONE;
    }

    @Override
    public Fragment getItem(int item) {
        if (item >= fragmentList.size()) {
            return null;
        }
        return fragmentList.get(item);
    }

    @Override
    public int getCount() {
        return fragmentList.size();
    }

    @Override
    public CharSequence getPageTitle(int position) {
        return tabTitleList.get(position);
    }
}

经过研究，我找到了短代码的解决方案。 首先，在fragment上创建一个公共实例，如果fragment没有在方向改变上重新创建，则在onSaveInstanceState上删除你的fragment。

 @Override
public void onSaveInstanceState(Bundle outState) {
    if (null != mCalFragment) {
        FragmentTransaction bt = getChildFragmentManager().beginTransaction();
        bt.remove(mFragment);
        bt.commit();
    }
    super.onSaveInstanceState(outState);
}

替换viewpager中的片段是相当复杂的，但这是非常可能的，可以看起来超级光滑。首先，您需要让viewpager本身处理片段的删除和添加。发生的事情是，当你替换SearchFragment内部的片段时，你的viewpager保留它的片段视图。因此，您最终会得到一个空白页，因为当您试图替换它时，SearchFragment会被删除。

解决方案是在viewpager内部创建一个侦听器，它将处理在viewpager外部所做的更改，因此首先将这段代码添加到适配器的底部。

public interface nextFragmentListener {
    public void fragment0Changed(String newFragmentIdentification);
}

然后你需要在你的viewpager中创建一个私有类，当你想要改变你的片段时，它会成为一个监听器。例如，你可以加上这样的东西。注意，它实现了刚刚创建的接口。因此，无论何时调用此方法，它都将在下面的类中运行代码。

private final class fragmentChangeListener implements nextFragmentListener {


    @Override
    public void fragment0Changed(String fragment) {
        //I will explain the purpose of fragment0 in a moment
        fragment0 = fragment;
        manager.beginTransaction().remove(fragAt0).commit();

        switch (fragment){
            case "searchFragment":
                fragAt0 = SearchFragment.newInstance(listener);
                break;
            case "searchResultFragment":
                fragAt0 = Fragment_Table.newInstance(listener);
                break;
        }

        notifyDataSetChanged();
    }

这里主要有两点需要指出:

fragAt0 is a "flexible" fragment. It can take on whatever fragment type you give it. This allows it to become your best friend in changing the fragment at position 0 to the fragment you desire. Notice the listeners that are placed in the 'newInstance(listener)constructor. These are how you will callfragment0Changed(String newFragmentIdentification)`. The following code shows how you create the listener inside of your fragment. static nextFragmentListener listenerSearch; public static Fragment_Journals newInstance(nextFragmentListener listener){ listenerSearch = listener; return new Fragment_Journals(); }

您可以在onPostExecute内部调用更改

private class SearchAsyncTask extends AsyncTask<Void, Void, Void>{

    protected Void doInBackground(Void... params){
        .
        .//some more operation
        .
    }
    protected void onPostExecute(Void param){

        listenerSearch.fragment0Changed("searchResultFragment");
    }

}

这将触发viewpager内部的代码来切换位置为零位fragAt0的片段，成为一个新的searchResultFragment。在viewpager发挥作用之前，还需要添加另外两个小部件。

一个是在viewpager的getItem重写方法中。

@Override
public Fragment getItem(int index) {

    switch (index) {
    case 0:
        //this is where it will "remember" which fragment you have just selected. the key is to set a static String fragment at the top of your page that will hold the position that you had just selected.  

        if(fragAt0 == null){

            switch(fragment0){
            case "searchFragment":
                fragAt0 = FragmentSearch.newInstance(listener);
                break;
            case "searchResultsFragment":
                fragAt0 = FragmentSearchResults.newInstance(listener);
                break;
            }
        }
        return fragAt0;
    case 1:
        // Games fragment activity
        return new CreateFragment();

    }

现在，如果没有这最后一块，你仍然会得到一张白纸。有点蹩脚，但它是viewPager的必要部分。你必须重写viewpager的getItemPosition方法。通常这个方法将返回POSITION_UNCHANGED，它告诉viewpager保持所有内容相同，因此永远不会调用getItem来将新的片段放在页面上。这里有一个你可以做的例子

public int getItemPosition(Object object)
{
    //object is the current fragment displayed at position 0.  
    if(object instanceof SearchFragment && fragAt0 instanceof SearchResultFragment){
        return POSITION_NONE;
    //this condition is for when you press back
    }else if{(object instanceof SearchResultFragment && fragAt0 instanceof SearchFragment){
        return POSITION_NONE;
    }
        return POSITION_UNCHANGED
}

如我所说，代码非常复杂，但您基本上必须为您的情况创建一个自定义适配器。我所提到的内容将使更改片段成为可能。这可能需要很长时间来消化一切，所以我会有耐心，但一切都会有意义的。这是完全值得花时间的，因为它可以做出一个非常漂亮的应用程序。

这里是处理后退按钮的块。你把这个放到MainActivity中

 public void onBackPressed() {
    if(mViewPager.getCurrentItem() == 0) {
        if(pagerAdapter.getItem(0) instanceof FragmentSearchResults){
            ((Fragment_Table) pagerAdapter.getItem(0)).backPressed();
        }else if (pagerAdapter.getItem(0) instanceof FragmentSearch) {
            finish();
        }
    }

您需要在FragmentSearchResults中创建一个名为backPressed()的方法，该方法调用fragment0changed。这与我之前展示的代码一起处理按下后退按钮。祝您在更改viewpager的代码中好运。这需要大量的工作，据我所知，没有任何快速的适应。就像我说的，你基本上是在创建一个自定义viewpager适配器，并让它使用侦听器处理所有必要的更改

这就是我实现目标的方法。

首先，在viewPager标签中添加Root_fragment，你想在其中实现按钮点击片段事件。例子;

@Override
public Fragment getItem(int position) {
  if(position==0)
      return RootTabFragment.newInstance();
  else
      return SecondPagerFragment.newInstance();
}

首先，RootTabFragment应该包含FragmentLayout来改变片段。

<FrameLayout xmlns:android="http://schemas.android.com/apk/res/android"
   xmlns:tools="http://schemas.android.com/tools"
   android:id="@+id/root_frame"
   android:layout_width="match_parent"
   android:layout_height="match_parent">
</FrameLayout>

然后，在RootTabFragment onCreateView内部，实现FirstPagerFragment的fragmentChange

getChildFragmentManager().beginTransaction().replace(R.id.root_frame, FirstPagerFragment.newInstance()).commit();

在那之后，实现onClick事件为您的按钮在FirstPagerFragment和使片段改变像那样再次。

getChildFragmentManager().beginTransaction().replace(R.id.root_frame, NextFragment.newInstance()).commit();

希望这对你们有帮助。