我试图使用片段与一个ViewPager使用FragmentPagerAdapter。
我想要实现的是替换一个片段，位于ViewPager的第一页，与另一个。
寻呼机由两个页面组成。第一个是FirstPagerFragment，第二个是SecondPagerFragment。点击第一页的一个按钮。我想用NextFragment替换FirstPagerFragment。
下面是我的代码。
public class FragmentPagerActivity extends FragmentActivity {
static final int NUM_ITEMS = 2;
MyAdapter mAdapter;
ViewPager mPager;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.fragment_pager);
mAdapter = new MyAdapter(getSupportFragmentManager());
mPager = (ViewPager) findViewById(R.id.pager);
mPager.setAdapter(mAdapter);
}
/**
* Pager Adapter
*/
public static class MyAdapter extends FragmentPagerAdapter {
public MyAdapter(FragmentManager fm) {
super(fm);
}
@Override
public int getCount() {
return NUM_ITEMS;
}
@Override
public Fragment getItem(int position) {
if(position == 0) {
return FirstPageFragment.newInstance();
} else {
return SecondPageFragment.newInstance();
}
}
}
/**
* Second Page FRAGMENT
*/
public static class SecondPageFragment extends Fragment {
public static SecondPageFragment newInstance() {
SecondPageFragment f = new SecondPageFragment();
return f;
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
//Log.d("DEBUG", "onCreateView");
return inflater.inflate(R.layout.second, container, false);
}
}
/**
* FIRST PAGE FRAGMENT
*/
public static class FirstPageFragment extends Fragment {
Button button;
public static FirstPageFragment newInstance() {
FirstPageFragment f = new FirstPageFragment();
return f;
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
//Log.d("DEBUG", "onCreateView");
View root = inflater.inflate(R.layout.first, container, false);
button = (Button) root.findViewById(R.id.button);
button.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
FragmentTransaction trans = getFragmentManager().beginTransaction();
trans.replace(R.id.first_fragment_root_id, NextFragment.newInstance());
trans.setTransition(FragmentTransaction.TRANSIT_FRAGMENT_OPEN);
trans.addToBackStack(null);
trans.commit();
}
});
return root;
}
/**
* Next Page FRAGMENT in the First Page
*/
public static class NextFragment extends Fragment {
public static NextFragment newInstance() {
NextFragment f = new NextFragment();
return f;
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
//Log.d("DEBUG", "onCreateView");
return inflater.inflate(R.layout.next, container, false);
}
}
}
.．.这里是XML文件
fragment_pager.xml
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical" android:padding="4dip"
android:gravity="center_horizontal"
android:layout_width="match_parent" android:layout_height="match_parent">
<android.support.v4.view.ViewPager
android:id="@+id/pager"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:layout_weight="1">
</android.support.v4.view.ViewPager>
</LinearLayout>
first.xml
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/first_fragment_root_id"
android:orientation="vertical"
android:layout_width="match_parent"
android:layout_height="match_parent">
<Button android:id="@+id/button"
android:layout_width="wrap_content" android:layout_height="wrap_content"
android:text="to next"/>
</LinearLayout>
现在的问题是……我应该使用哪个ID
trans.replace(R.id.first_fragment_root_id, NextFragment.newInstance());
?
如果我用r。id。first_fragment_root_id，替换工作，但Hierarchy Viewer显示一个奇怪的行为，如下所示。
一开始的情况是
更换后的情况是
正如你所看到的，有一些错误，我希望在替换片段后找到与第一张图片中相同的状态。
我做了一些类似于wize的事情，但在我的回答中，你可以随时在两个片段之间更改。在改变屏幕方向之类的时候，我遇到了一些问题。这是PagerAdapter的样子:
public class MyAdapter extends FragmentPagerAdapter
{
static final int NUM_ITEMS = 2;
private final FragmentManager mFragmentManager;
private Fragment mFragmentAtPos0;
private Map<Integer, String> mFragmentTags;
private boolean isNextFragment=false;
public MyAdapter(FragmentManager fm)
{
super(fm);
mFragmentManager = fm;
mFragmentTags = new HashMap<Integer, String>();
}
@Override
public Fragment getItem(int position)
{
if (position == 0)
{
if (isPager) {
mFragmentAtPos0 = new FirstPageFragment();
} else {
mFragmentAtPos0 = new NextFragment();
}
return mFragmentAtPos0;
}
else
return SecondPageFragment.newInstance();
}
@Override
public int getCount()
{
return NUM_ITEMS;
}
@Override
public Object instantiateItem(ViewGroup container, int position) {
Object obj = super.instantiateItem(container, position);
if (obj instanceof Fragment) {
// record the fragment tag here.
Fragment f = (Fragment) obj;
String tag = f.getTag();
mFragmentTags.put(position, tag);
}
return obj;
}
public void onChange(boolean isNextFragment) {
if (mFragmentAtPos0 == null)
mFragmentAtPos0 = getFragment(0);
if (mFragmentAtPos0 != null)
mFragmentManager.beginTransaction().remove(mFragmentAtPos0).commit();
if (!isNextFragment) {
mFragmentAtFlashcards = new FirstPageFragment();
} else {
mFragmentAtFlashcards = new NextFragment();
}
notifyDataSetChanged();
}
@Override
public int getItemPosition(Object object)
{
if (object instanceof FirstPageFragment && mFragmentAtPos0 instanceof NextFragment)
return POSITION_NONE;
if (object instanceof NextFragment && mFragmentAtPos0 instanceof FirstPageFragment)
return POSITION_NONE;
return POSITION_UNCHANGED;
}
public Fragment getFragment(int position) {
String tag = mFragmentTags.get(position);
if (tag == null)
return null;
return mFragmentManager.findFragmentByTag(tag);
}
}
我在适配器容器活动中实现的侦听器，用于在附加片段时将其放到片段中，这是活动:
public class PagerContainerActivity extends AppCompatActivity implements ChangeFragmentListener {
//...
@Override
public void onChange(boolean isNextFragment) {
if (pagerAdapter != null)
pagerAdapter.onChange(isNextFragment);
}
//...
}
然后在片段中放置侦听器，当附加调用它:
public class FirstPageFragment extends Fragment{
private ChangeFragmentListener changeFragmentListener;
//...
@Override
public void onAttach(Activity activity) {
super.onAttach(activity);
changeFragmentListener = ((PagerContainerActivity) activity);
}
@Override
public void onDetach() {
super.onDetach();
changeFragmentListener = null;
}
//...
//in the on click to change the fragment
changeFragmentListener.onChange(true);
//...
}
最后是听众:
public interface changeFragmentListener {
void onChange(boolean isNextFragment);
}
Works Great with AndroidTeam's solution, however I found that I needed the ability to go back much like FrgmentTransaction.addToBackStack(null) But merely adding this will only cause the Fragment to be replaced without notifying the ViewPager. Combining the provided solution with this minor enhancement will allow you to return to the previous state by merely overriding the activity's onBackPressed() method. The biggest drawback is that it will only go back one at a time which may result in multiple back clicks
private ArrayList<Fragment> bFragments = new ArrayList<Fragment>();
private ArrayList<Integer> bPosition = new ArrayList<Integer>();
public void replaceFragmentsWithBackOut(ViewPager container, Fragment oldFragment, Fragment newFragment) {
startUpdate(container);
// remove old fragment
if (mCurTransaction == null) {
mCurTransaction = mFragmentManager.beginTransaction();
}
int position = getFragmentPosition(oldFragment);
while (mSavedState.size() <= position) {
mSavedState.add(null);
}
//Add Fragment to Back List
bFragments.add(oldFragment);
//Add Pager Position to Back List
bPosition.add(position);
mSavedState.set(position, null);
mFragments.set(position, null);
mCurTransaction.remove(oldFragment);
// add new fragment
while (mFragments.size() <= position) {
mFragments.add(null);
}
mFragments.set(position, newFragment);
mCurTransaction.add(container.getId(), newFragment);
finishUpdate(container);
// ensure getItem returns newFragemtn after calling handleGetItemInbalidated()
handleGetItemInvalidated(container, oldFragment, newFragment);
container.notifyItemChanged(oldFragment, newFragment);
}
public boolean popBackImmediate(ViewPager container){
int bFragSize = bFragments.size();
int bPosSize = bPosition.size();
if(bFragSize>0 && bPosSize>0){
if(bFragSize==bPosSize){
int last = bFragSize-1;
int position = bPosition.get(last);
//Returns Fragment Currently at this position
Fragment replacedFragment = mFragments.get(position);
Fragment originalFragment = bFragments.get(last);
this.replaceFragments(container, replacedFragment, originalFragment);
bPosition.remove(last);
bFragments.remove(last);
return true;
}
}
return false;
}
希望这能帮助到一些人。
同样，就getFragmentPosition()而言，它几乎是反向的getItem()。你知道哪些片段去哪里，只是确保你返回正确的位置它将在。这里有一个例子:
@Override
protected int getFragmentPosition(Fragment fragment) {
if(fragment.equals(originalFragment1)){
return 0;
}
if(fragment.equals(replacementFragment1)){
return 0;
}
if(fragment.equals(Fragment2)){
return 1;
}
return -1;
}
我按照@wize和@mdelolmo的答案，我得到了解决方案。由于吨。但是，我稍微调整了这些解决方案，以提高内存消耗。
我观察到的问题:
它们保存被替换的Fragment实例。在我的情况下，它是一个持有MapView的片段，我认为它的成本很高。所以，我维护FragmentPagerPositionChanged (POSITION_NONE或POSITION_UNCHANGED)而不是Fragment本身。
这是我的实现。
public static class DemoCollectionPagerAdapter extends FragmentStatePagerAdapter {
private SwitchFragListener mSwitchFragListener;
private Switch mToggle;
private int pagerAdapterPosChanged = POSITION_UNCHANGED;
private static final int TOGGLE_ENABLE_POS = 2;
public DemoCollectionPagerAdapter(FragmentManager fm, Switch toggle) {
super(fm);
mToggle = toggle;
mSwitchFragListener = new SwitchFragListener();
mToggle.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
@Override
public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
mSwitchFragListener.onSwitchToNextFragment();
}
});
}
@Override
public Fragment getItem(int i) {
switch (i)
{
case TOGGLE_ENABLE_POS:
if(mToggle.isChecked())
{
return TabReplaceFragment.getInstance();
}else
{
return DemoTab2Fragment.getInstance(i);
}
default:
return DemoTabFragment.getInstance(i);
}
}
@Override
public int getCount() {
return 5;
}
@Override
public CharSequence getPageTitle(int position) {
return "Tab " + (position + 1);
}
@Override
public int getItemPosition(Object object) {
// This check make sures getItem() is called only for the required Fragment
if (object instanceof TabReplaceFragment
|| object instanceof DemoTab2Fragment)
return pagerAdapterPosChanged;
return POSITION_UNCHANGED;
}
/**
* Switch fragments Interface implementation
*/
private final class SwitchFragListener implements
SwitchFragInterface {
SwitchFragListener() {}
public void onSwitchToNextFragment() {
pagerAdapterPosChanged = POSITION_NONE;
notifyDataSetChanged();
}
}
/**
* Interface to switch frags
*/
private interface SwitchFragInterface{
void onSwitchToNextFragment();
}
}
演示链接在这里..https://youtu.be/l_62uhKkLyM
出于演示目的，在位置2处使用了两个片段TabReplaceFragment和DemoTab2Fragment。在所有其他情况下，我使用DemoTabFragment实例。
解释:
我将Switch从Activity传递到DemoCollectionPagerAdapter。基于这个开关的状态，我们将显示正确的片段。当开关检查被更改时，我调用SwitchFragListener的onSwitchToNextFragment方法，其中我将pagerAdapterPosChanged变量的值更改为POSITION_NONE。查看更多关于POSITION_NONE的信息。这将使getItem无效，我有逻辑实例化正确的片段在那里。抱歉，如果解释得有点乱的话。
再次感谢@wize和@mdelolmo的原创想法。
希望这对你有帮助。：）
如果这个实现有任何缺陷，请告诉我。那将对我的项目大有帮助。
我做了一些类似于wize的事情，但在我的回答中，你可以随时在两个片段之间更改。在改变屏幕方向之类的时候，我遇到了一些问题。这是PagerAdapter的样子:
public class MyAdapter extends FragmentPagerAdapter
{
static final int NUM_ITEMS = 2;
private final FragmentManager mFragmentManager;
private Fragment mFragmentAtPos0;
private Map<Integer, String> mFragmentTags;
private boolean isNextFragment=false;
public MyAdapter(FragmentManager fm)
{
super(fm);
mFragmentManager = fm;
mFragmentTags = new HashMap<Integer, String>();
}
@Override
public Fragment getItem(int position)
{
if (position == 0)
{
if (isPager) {
mFragmentAtPos0 = new FirstPageFragment();
} else {
mFragmentAtPos0 = new NextFragment();
}
return mFragmentAtPos0;
}
else
return SecondPageFragment.newInstance();
}
@Override
public int getCount()
{
return NUM_ITEMS;
}
@Override
public Object instantiateItem(ViewGroup container, int position) {
Object obj = super.instantiateItem(container, position);
if (obj instanceof Fragment) {
// record the fragment tag here.
Fragment f = (Fragment) obj;
String tag = f.getTag();
mFragmentTags.put(position, tag);
}
return obj;
}
public void onChange(boolean isNextFragment) {
if (mFragmentAtPos0 == null)
mFragmentAtPos0 = getFragment(0);
if (mFragmentAtPos0 != null)
mFragmentManager.beginTransaction().remove(mFragmentAtPos0).commit();
if (!isNextFragment) {
mFragmentAtFlashcards = new FirstPageFragment();
} else {
mFragmentAtFlashcards = new NextFragment();
}
notifyDataSetChanged();
}
@Override
public int getItemPosition(Object object)
{
if (object instanceof FirstPageFragment && mFragmentAtPos0 instanceof NextFragment)
return POSITION_NONE;
if (object instanceof NextFragment && mFragmentAtPos0 instanceof FirstPageFragment)
return POSITION_NONE;
return POSITION_UNCHANGED;
}
public Fragment getFragment(int position) {
String tag = mFragmentTags.get(position);
if (tag == null)
return null;
return mFragmentManager.findFragmentByTag(tag);
}
}
我在适配器容器活动中实现的侦听器，用于在附加片段时将其放到片段中，这是活动:
public class PagerContainerActivity extends AppCompatActivity implements ChangeFragmentListener {
//...
@Override
public void onChange(boolean isNextFragment) {
if (pagerAdapter != null)
pagerAdapter.onChange(isNextFragment);
}
//...
}
然后在片段中放置侦听器，当附加调用它:
public class FirstPageFragment extends Fragment{
private ChangeFragmentListener changeFragmentListener;
//...
@Override
public void onAttach(Activity activity) {
super.onAttach(activity);
changeFragmentListener = ((PagerContainerActivity) activity);
}
@Override
public void onDetach() {
super.onDetach();
changeFragmentListener = null;
}
//...
//in the on click to change the fragment
changeFragmentListener.onChange(true);
//...
}
最后是听众:
public interface changeFragmentListener {
void onChange(boolean isNextFragment);
}
