I could be very wrong here, as I don't have a strong background in theoretical mathematics or functional programming, but from my brief foray into FP, it seems that currying tends to turn a function of N arguments into N functions of one argument, whereas partial application [in practice] works better with variadic functions with an indeterminate number of arguments. I know some of the examples in previous answers defy this explanation, but it has helped me the most to separate the concepts. Consider this example (written in CoffeeScript for succinctness, my apologies if it confuses further, but please ask for clarification, if needed):

# partial application
partial_apply = (func) ->
  args = [].slice.call arguments, 1
  -> func.apply null, args.concat [].slice.call arguments

sum_variadic = -> [].reduce.call arguments, (acc, num) -> acc + num

add_to_7_and_5 = partial_apply sum_variadic, 7, 5

add_to_7_and_5 10 # returns 22
add_to_7_and_5 10, 11, 12 # returns 45

# currying
curry = (func) ->
  num_args = func.length
  helper = (prev) ->
    ->
      args = prev.concat [].slice.call arguments
      return if args.length < num_args then helper args else func.apply null, args
  helper []

sum_of_three = (x, y, z) -> x + y + z
curried_sum_of_three = curry sum_of_three
curried_sum_of_three 4 # returns a function expecting more arguments
curried_sum_of_three(4)(5) # still returns a function expecting more arguments
curried_sum_of_three(4)(5)(6) # returns 15
curried_sum_of_three 4, 5, 6 # returns 15

这显然是一个人为的例子，但请注意，部分应用一个接受任意数量参数的函数允许我们使用一些初步数据来执行函数。curry函数与此类似，但允许我们分批执行N个参数的函数，直到，但只是直到，所有N个参数都被考虑。

再说一次，这是我从我读过的东西中得出的结论。如果有人不同意，我希望能就原因发表评论，而不是立即投反对票。另外，如果CoffeeScript很难阅读，请访问coffeescript.org，点击“尝试CoffeeScript”并粘贴我的代码来查看编译后的版本，这可能(希望)更有意义。谢谢!

局部套用

维基百科上说

curry是一种将带有多个参数的函数转换为带有单个参数的函数序列的技术。

例子

const add = (a, b) => a + b

const addC = (a) => (b) => a + b // curried function. Where C means curried

部分应用程序

文章刚刚好FP:部分应用

部分应用是将部分(而不是全部)参数应用到函数，并返回一个新函数等待其余参数。这些应用的参数存储在闭包中，并且将来对任何部分应用的返回函数仍然可用。

例子

const add = (a) => (b) => a + b

const add3 = add(3) // add3 is a partially applied function

add3(5) // 8

区别在于

咖喱是一种技术(模式) Partial application是一个带有一些预定义参数的函数(如前面示例中的add3)

这里还有其他很好的答案，但我相信Java中的这个例子(根据我的理解)可能对一些人有益:

public static <A,B,X> Function< B, X > partiallyApply( BiFunction< A, B, X > aBiFunction, A aValue ){
    return b -> aBiFunction.apply( aValue, b );
}

public static <A,X> Supplier< X > partiallyApply( Function< A, X > aFunction, A aValue ){
    return () -> aFunction.apply( aValue );
}

public static <A,B,X> Function<  A, Function< B, X >  > curry( BiFunction< A, B, X > bif ){
    return a -> partiallyApply( bif, a );
}

因此curry为您提供了一个单参数函数来创建函数，而partial-application则创建一个包装器函数，该包装器函数硬编码一个或多个参数。

如果你想复制和粘贴，下面的文件比较吵闹，但是使用起来比较友好，因为类型比较宽松:

public static <A,B,X> Function< ? super B, ? extends X > partiallyApply( final BiFunction< ? super A, ? super B, X > aBiFunction, final A aValue ){
    return b -> aBiFunction.apply( aValue, b );
}

public static <A,X> Supplier< ? extends X > partiallyApply( final Function< ? super A, X > aFunction, final A aValue ){
    return () -> aFunction.apply( aValue );
}

public static <A,B,X> Function<  ? super A,  Function< ? super B, ? extends X >  > curry( final BiFunction< ? super A, ? super B, ? extends X > bif ){
    return a -> partiallyApply( bif, a );
}

注意:本文摘自f# Basics，这是一篇非常好的介绍性文章，供。net开发人员学习函数式编程。

Currying means breaking a function with many arguments into a series of functions that each take one argument and ultimately produce the same result as the original function. Currying is probably the most challenging topic for developers new to functional programming, particularly because it is often confused with partial application. You can see both at work in this example: let multiply x y = x * y let double = multiply 2 let ten = double 5 Right away, you should see behavior that is different from most imperative languages. The second statement creates a new function called double by passing one argument to a function that takes two. The result is a function that accepts one int argument and yields the same output as if you had called multiply with x equal to 2 and y equal to that argument. In terms of behavior, it’s the same as this code: let double2 z = multiply 2 z Often, people mistakenly say that multiply is curried to form double. But this is only somewhat true. The multiply function is curried, but that happens when it is defined because functions in F# are curried by default. When the double function is created, it’s more accurate to say that the multiply function is partially applied. The multiply function is really a series of two functions. The first function takes one int argument and returns another function, effectively binding x to a specific value. This function also accepts an int argument that you can think of as the value to bind to y. After calling this second function, x and y are both bound, so the result is the product of x and y as defined in the body of double. To create double, the first function in the chain of multiply functions is evaluated to partially apply multiply. The resulting function is given the name double. When double is evaluated, it uses its argument along with the partially applied value to create the result.

I could be very wrong here, as I don't have a strong background in theoretical mathematics or functional programming, but from my brief foray into FP, it seems that currying tends to turn a function of N arguments into N functions of one argument, whereas partial application [in practice] works better with variadic functions with an indeterminate number of arguments. I know some of the examples in previous answers defy this explanation, but it has helped me the most to separate the concepts. Consider this example (written in CoffeeScript for succinctness, my apologies if it confuses further, but please ask for clarification, if needed):

# partial application
partial_apply = (func) ->
  args = [].slice.call arguments, 1
  -> func.apply null, args.concat [].slice.call arguments

sum_variadic = -> [].reduce.call arguments, (acc, num) -> acc + num

add_to_7_and_5 = partial_apply sum_variadic, 7, 5

add_to_7_and_5 10 # returns 22
add_to_7_and_5 10, 11, 12 # returns 45

# currying
curry = (func) ->
  num_args = func.length
  helper = (prev) ->
    ->
      args = prev.concat [].slice.call arguments
      return if args.length < num_args then helper args else func.apply null, args
  helper []

sum_of_three = (x, y, z) -> x + y + z
curried_sum_of_three = curry sum_of_three
curried_sum_of_three 4 # returns a function expecting more arguments
curried_sum_of_three(4)(5) # still returns a function expecting more arguments
curried_sum_of_three(4)(5)(6) # returns 15
curried_sum_of_three 4, 5, 6 # returns 15

这显然是一个人为的例子，但请注意，部分应用一个接受任意数量参数的函数允许我们使用一些初步数据来执行函数。curry函数与此类似，但允许我们分批执行N个参数的函数，直到，但只是直到，所有N个参数都被考虑。

再说一次，这是我从我读过的东西中得出的结论。如果有人不同意，我希望能就原因发表评论，而不是立即投反对票。另外，如果CoffeeScript很难阅读，请访问coffeescript.org，点击“尝试CoffeeScript”并粘贴我的代码来查看编译后的版本，这可能(希望)更有意义。谢谢!

我假设大多数问这个问题的人已经熟悉了基本概念，所以他们没有必要谈论这个。重叠是令人困惑的部分。

您可能能够充分使用这些概念，但您将它们一起理解为伪原子无定形的概念模糊。现在缺少的是知道它们之间的界限在哪里。

与其定义它们是什么，不如简单地强调它们的不同之处——边界。

curry是在定义函数的时候。

部分应用程序是在调用函数时。

应用程序是调用函数的数学术语。

部分应用程序需要调用一个curry函数并获得一个函数作为返回类型。