下面的异常是什么意思;我该怎么解决呢?
这是代码:
Toast toast = Toast.makeText(mContext, "Something", Toast.LENGTH_SHORT);
这是例外:
java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare()
at android.os.Handler.<init>(Handler.java:121)
at android.widget.Toast.<init>(Toast.java:68)
at android.widget.Toast.makeText(Toast.java:231)
当前回答
Rxjava和RxAndroid用户:
public static void shortToast(String msg) {
Observable.just(msg)
.observeOn(AndroidSchedulers.mainThread())
.subscribe(message -> {
Toast.makeText(App.getInstance(), message, Toast.LENGTH_SHORT).show();
});
}
其他回答
Java 8
new Handler(Looper.getMainLooper()).post(() -> {
// Work in the UI thread
});
科特林
Handler(Looper.getMainLooper()).post{
// Work in the UI thread
}
GL
当我的回调函数试图显示一个对话框时，我也遇到了同样的问题。
我用活动中的专用方法解决了这个问题-在活动实例成员级别-使用runOnUiThread(..)
public void showAuthProgressDialog() {
runOnUiThread(new Runnable() {
@Override
public void run() {
mAuthProgressDialog = DialogUtil.getVisibleProgressDialog(SignInActivity.this, "Loading ...");
}
});
}
public void dismissAuthProgressDialog() {
runOnUiThread(new Runnable() {
@Override
public void run() {
if (mAuthProgressDialog == null || ! mAuthProgressDialog.isShowing()) {
return;
}
mAuthProgressDialog.dismiss();
}
});
}
你需要在UI线程上创建吐司。请看下面的例子。
runOnUiThread(new Runnable() {
public void run() {
Toast.makeText(activity, "YOUR_MESSAGE", Toast.LENGTH_SHORT).show();
}
});
要显示Toast消息，请参考这篇文章
Handler handler2;
HandlerThread handlerThread=new HandlerThread("second_thread");
handlerThread.start();
handler2=new Handler(handlerThread.getLooper());
现在handler2将使用一个不同于主线程的线程来处理消息。
下面是Kotlin使用Coroutine的解决方案:
通过MainScope()使用CoroutineScope扩展类:
class BootstrapActivity : CoroutineScope by MainScope() {}
然后简单地这样做:
launch {
// whatever you want to do in the main thread
}
不要忘记添加协程的依赖项:
org.jetbrains.kotlinx:kotlinx-coroutines-core:${Versions.kotlinCoroutines}
org.jetbrains.kotlinx:kotlinx-coroutines-android:${Versions.kotlinCoroutines}
