我正在使用Redux进行状态管理。 如何将存储重置为初始状态?

例如,假设我有两个用户帐户(u1和u2)。 想象下面的一系列事件:

用户u1登录到应用程序并做了一些事情,所以我们在存储中缓存一些数据。 用户u1退出。 用户u2无需刷新浏览器即可登录应用。

此时,缓存的数据将与u1关联,我想清理它。

当第一个用户注销时,如何将Redux存储重置为初始状态?


当前回答

为什么不直接使用return module.exports.default();)

export default (state = {pending: false, error: null}, action = {}) => {
    switch (action.type) {
        case "RESET_POST":
            return module.exports.default();
        case "SEND_POST_PENDING":
            return {...state, pending: true, error: null};
        // ....
    }
    return state;
}

注意:确保你设置动作默认值为{},你是可以的,因为你不想在检查动作时遇到错误。在switch语句中输入。

其他回答

使用Redux Toolkit的方法:


export const createRootReducer = (history: History) => {
  const rootReducerFn = combineReducers({
    auth: authReducer,
    users: usersReducer,
    ...allOtherReducers,
    router: connectRouter(history),
  });

  return (state: Parameters<typeof rootReducerFn>[0], action: Parameters<typeof rootReducerFn>[1]) =>
    rootReducerFn(action.type === appActions.reset.type ? undefined : state, action);
};

丹·阿布拉莫夫的回答帮我破案了。然而,我遇到了一个案例,并不是整个州都需要清理。所以我是这样做的:

const combinedReducer = combineReducers({
    // my reducers 
});

const rootReducer = (state, action) => {
    if (action.type === RESET_REDUX_STATE) {
        // clear everything but keep the stuff we want to be preserved ..
        delete state.something;
        delete state.anotherThing;
    }
    return combinedReducer(state, action);
}

export default rootReducer;

我已经创建了清除状态的操作。因此,当我分派登出动作创建者时,我也分派动作来清除状态。

用户记录动作

export const clearUserRecord = () => ({
  type: CLEAR_USER_RECORD
});

注销操作创建器

export const logoutUser = () => {
  return dispatch => {
    dispatch(requestLogout())
    dispatch(receiveLogout())
    localStorage.removeItem('auth_token')
    dispatch({ type: 'CLEAR_USER_RECORD' })
  }
};

减速机

const userRecords = (state = {isFetching: false,
  userRecord: [], message: ''}, action) => {
  switch (action.type) {
    case REQUEST_USER_RECORD:
    return { ...state,
      isFetching: true}
    case RECEIVE_USER_RECORD:
    return { ...state,
      isFetching: false,
      userRecord: action.user_record}
    case USER_RECORD_ERROR:
    return { ...state,
      isFetching: false,
      message: action.message}
    case CLEAR_USER_RECORD:
    return {...state,
      isFetching: false,
      message: '',
      userRecord: []}
    default:
      return state
  }
};

我不确定这是否是最佳的?

首先,在应用程序启动时,减速机的状态是新鲜的,并带有默认的InitialState。

我们必须添加一个动作,调用APP初始加载持续默认状态。

当注销应用程序时,我们可以简单地重新分配默认状态,reducer将像新的一样工作。

APP主容器

  componentDidMount() {   
    this.props.persistReducerState();
  }

主APP减速器

const appReducer = combineReducers({
  user: userStatusReducer,     
  analysis: analysisReducer,
  incentives: incentivesReducer
});

let defaultState = null;
export default (state, action) => {
  switch (action.type) {
    case appActions.ON_APP_LOAD:
      defaultState = defaultState || state;
      break;
    case userLoginActions.USER_LOGOUT:
      state = defaultState;
      return state;
    default:
      break;
  }
  return appReducer(state, action);
};

注销时调用重置状态的动作

function* logoutUser(action) {
  try {
    const response = yield call(UserLoginService.logout);
    yield put(LoginActions.logoutSuccess());
  } catch (error) {
    toast.error(error.message, {
      position: toast.POSITION.TOP_RIGHT
    });
  }
}

使用Redux Toolkit和/或Typescript:

const appReducer = combineReducers({
  /* your app’s top-level reducers */
});

const rootReducer = (
  state: ReturnType<typeof appReducer>,
  action: AnyAction
) => {
/* if you are using RTK, you can import your action and use it's type property instead of the literal definition of the action  */
  if (action.type === logout.type) {
    return appReducer(undefined, { type: undefined });
  }

  return appReducer(state, action);
};