".Last()"对我不起作用，所以我不得不这样做:

Dictionary<string, string> iterativeDictionary = someOtherDictionary;
var index = 0;
iterativeDictionary.ForEach(kvp => 
    index++ == iterativeDictionary.Count ? 
        /*it's the last item */ :
        /*it's not the last item */
);

一个老式的for循环怎么样?

for (int i = 0; i < Model.Results.Count; i++) {

     if (i == Model.Results.Count - 1) {
           // this is the last item
     }
}

或者使用Linq和foreach:

foreach (Item result in Model.Results)   
{   
     if (Model.Results.IndexOf(result) == Model.Results.Count - 1) {
             // this is the last item
     }
}

foreach (DataRow drow in ds.Tables[0].Rows)
            {
                cnt_sl1 = "<div class='col-md-6'><div class='Slider-img'>" +
                          "<div class='row'><img src='" + drow["images_path"].ToString() + "' alt='' />" +
                          "</div></div></div>";
                cnt_sl2 = "<div class='col-md-6'><div class='Slider-details'>" +
                          "<p>" + drow["situation_details"].ToString() + "</p>" +
                          "</div></div>";
                if (i == 0)
                {
                    lblSituationName.Text = drow["situation"].ToString();
                }
                if (drow["images_position"].ToString() == "0")
                {
                    content += "<div class='item'>" + cnt_sl1 + cnt_sl2 + "</div>";
                    cnt_sl1 = "";
                    cnt_sl2 = "";
                }
                else if (drow["images_position"].ToString() == "1")
                {
                    content += "<div class='item'>" + cnt_sl2 + cnt_sl1 + "</div>";
                    cnt_sl1 = "";
                    cnt_sl2 = "";
                }
                i++;
            }

如何将foreach转换为对最后一个元素做出反应:

List<int> myList = new List<int>() {1, 2, 3, 4, 5};
Console.WriteLine("foreach version");
{
    foreach (var current in myList)
    {
        Console.WriteLine(current);
    }
}
Console.WriteLine("equivalent that reacts to last element");
{
    var enumerator = myList.GetEnumerator();
    if (enumerator.MoveNext() == true) // Corner case: empty list.
    {
        while (true)
        {
            int current = enumerator.Current;

            // Handle current element here.
            Console.WriteLine(current);

            bool ifLastElement = (enumerator.MoveNext() == false);
            if (ifLastElement)
            {
                // Cleanup after last element
                Console.WriteLine("[last element]");
                break;
            }
        }
    }
    enumerator.Dispose();
}

迭代器实现没有提供这一点。您的集合可能是一个IList，可以通过O(1)中的索引访问。在这种情况下，你可以使用一个普通的for循环:

for(int i = 0; i < Model.Results.Count; i++)
{
  if(i == Model.Results.Count - 1) doMagic();
}

如果您知道计数，但不能通过索引访问(因此，result是一个ICollection)，您可以通过在foreach的主体中增加i并将其与长度进行比较来进行计数。

所有这些都不是完美的优雅。克里斯的解决方案可能是我迄今为止见过的最好的。

正如Shimmy所指出的，使用Last()可能会导致性能问题，例如，如果您的集合是LINQ表达式的实时结果。为了防止多次迭代，你可以使用“ForEach”扩展方法，如下所示:

var elements = new[] { "A", "B", "C" };
elements.ForEach((element, info) => {
    if (!info.IsLast) {
        Console.WriteLine(element);
    } else {
        Console.WriteLine("Last one: " + element);
    }
});

扩展方法看起来像这样(作为额外的奖励，它还会告诉你索引，如果你在看第一个元素):

public static class EnumerableExtensions {
    public delegate void ElementAction<in T>(T element, ElementInfo info);

    public static void ForEach<T>(this IEnumerable<T> elements, ElementAction<T> action) {
        using (IEnumerator<T> enumerator = elements.GetEnumerator())
        {
            bool isFirst = true;
            bool hasNext = enumerator.MoveNext();
            int index = 0;
            while (hasNext)
            {
                T current = enumerator.Current;
                hasNext = enumerator.MoveNext();
                action(current, new ElementInfo(index, isFirst, !hasNext));
                isFirst = false;
                index++;
            }
        }
    }

    public struct ElementInfo {
        public ElementInfo(int index, bool isFirst, bool isLast)
            : this() {
            Index = index;
            IsFirst = isFirst;
            IsLast = isLast;
        }

        public int Index { get; private set; }
        public bool IsFirst { get; private set; }
        public bool IsLast { get; private set; }
    }
}