如果要选择具有最小或最大属性值的对象。另一种方法是使用实现IComparable。

public struct Money : IComparable<Money>
{
   public Money(decimal value) : this() { Value = value; }
   public decimal Value { get; private set; }
   public int CompareTo(Money other) { return Value.CompareTo(other.Value); }
}

最大执行将是。

var amounts = new List<Money> { new Money(20), new Money(10) };
Money maxAmount = amounts.Max();

最小实现将是。

var amounts = new List<Money> { new Money(20), new Money(10) };
Money maxAmount = amounts.Min();

通过这种方式，您可以比较任何对象并在返回对象类型的同时获得Max和Min。

希望这能帮助到一些人。

另一种实现，可以使用可空的选择器键，如果没有找到合适的元素，则对于引用类型集合返回null。 例如，这对处理数据库结果很有帮助。

  public static class IEnumerableExtensions
  {
    /// <summary>
    /// Returns the element with the maximum value of a selector function.
    /// </summary>
    /// <typeparam name="TSource">The type of the elements of source.</typeparam>
    /// <typeparam name="TKey">The type of the key returned by keySelector.</typeparam>
    /// <param name="source">An IEnumerable collection values to determine the element with the maximum value of.</param>
    /// <param name="keySelector">A function to extract the key for each element.</param>
    /// <exception cref="System.ArgumentNullException">source or keySelector is null.</exception>
    /// <exception cref="System.InvalidOperationException">source contains no elements.</exception>
    /// <returns>The element in source with the maximum value of a selector function.</returns>
    public static TSource MaxBy<TSource, TKey>(this IEnumerable<TSource> source, Func<TSource, TKey> keySelector) => MaxOrMinBy(source, keySelector, 1);

    /// <summary>
    /// Returns the element with the minimum value of a selector function.
    /// </summary>
    /// <typeparam name="TSource">The type of the elements of source.</typeparam>
    /// <typeparam name="TKey">The type of the key returned by keySelector.</typeparam>
    /// <param name="source">An IEnumerable collection values to determine the element with the minimum value of.</param>
    /// <param name="keySelector">A function to extract the key for each element.</param>
    /// <exception cref="System.ArgumentNullException">source or keySelector is null.</exception>
    /// <exception cref="System.InvalidOperationException">source contains no elements.</exception>
    /// <returns>The element in source with the minimum value of a selector function.</returns>
    public static TSource MinBy<TSource, TKey>(this IEnumerable<TSource> source, Func<TSource, TKey> keySelector) => MaxOrMinBy(source, keySelector, -1);


    private static TSource MaxOrMinBy<TSource, TKey>
      (IEnumerable<TSource> source, Func<TSource, TKey> keySelector, int sign)
    {
      if (source == null) throw new ArgumentNullException(nameof(source));
      if (keySelector == null) throw new ArgumentNullException(nameof(keySelector));
      Comparer<TKey> comparer = Comparer<TKey>.Default;
      TKey value = default(TKey);
      TSource result = default(TSource);

      bool hasValue = false;

      foreach (TSource element in source)
      {
        TKey x = keySelector(element);
        if (x != null)
        {
          if (!hasValue)
          {
            value = x;
            result = element;
            hasValue = true;
          }
          else if (sign * comparer.Compare(x, value) > 0)
          {
            value = x;
            result = element;
          }
        }
      }

      if ((result != null) && !hasValue)
        throw new InvalidOperationException("The source sequence is empty");

      return result;
    }
  }

例子:

public class A
{
  public int? a;
  public A(int? a) { this.a = a; }
}

var b = a.MinBy(x => x.a);
var c = a.MaxBy(x => x.a);

你可以使用现有的linq扩展，比如MoreLinq。但如果你只需要这些方法，那么你可以使用这里的简单代码:

public static IEnumerable<T> MinBys<T>(this IEnumerable<T> collection, Func<T, IComparable> selector)
{
    var dict = collection.GroupBy(selector).ToDictionary(g => g.Key);
    return dict[dict.Keys.Min()];
}
public static IEnumerable<T> MaxBys<T>(this IEnumerable<T> collection, Func<T, IComparable> selector)
{
    var dict = collection.GroupBy(selector).ToDictionary(g => g.Key);
    return dict[dict.Keys.Max()];
}

People.Aggregate((curMin, x) => (curMin == null || (x.DateOfBirth ?? DateTime.MaxValue) <
    curMin.DateOfBirth ? x : curMin))

通过IEnumerable上的扩展函数返回对象和找到的最小值的方法。它接受一个可以对集合中的对象执行任何操作的Func:

public static (double min, T obj) tMin<T>(this IEnumerable<T> ienum, 
            Func<T, double> aFunc)
        {
            var okNull = default(T);
            if (okNull != null)
                throw new ApplicationException("object passed to Min not nullable");

            (double aMin, T okObj) best = (double.MaxValue, okNull);
            foreach (T obj in ienum)
            {
                double q = aFunc(obj);
                if (q < best.aMin)
                    best = (q, obj);
            }
            return (best);
        }

例子，对象是一个机场，我们想找到最近的机场到给定的(纬度，经度)。机场有纬度(纬度、纬度)功能。

(double okDist, Airport best) greatestPort = airPorts.tMin(x => x.dist(okLat, okLon));

我自己也在寻找类似的东西，最好不使用库或对整个列表进行排序。我的解决方案与问题本身相似，只是简化了一点。

var min = People.Min(p => p.DateOfBirth);
var firstBorn = People.FirstOrDefault(p => p.DateOfBirth == min);