下面哪个比较好?

a instanceof B

or

B.class.isAssignableFrom(a.getClass())

我所知道的唯一区别是,当'a'为空时,第一个返回false,而第二个抛出异常。除此之外,它们总是给出相同的结果吗?


当前回答

在性能“2”方面(与JMH):

class A{}
class B extends A{}

public class InstanceOfTest {

public static final Object a = new A();
public static final Object b = new B();

@Benchmark
@BenchmarkMode(Mode.AverageTime)
@OutputTimeUnit(TimeUnit.NANOSECONDS)
public boolean testInstanceOf()
{
    return b instanceof A;
}

@Benchmark
@BenchmarkMode(Mode.AverageTime)
@OutputTimeUnit(TimeUnit.NANOSECONDS)
public boolean testIsInstance()
{
    return A.class.isInstance(b);
}

@Benchmark
@BenchmarkMode(Mode.AverageTime)
@OutputTimeUnit(TimeUnit.NANOSECONDS)
public boolean testIsAssignableFrom()
{
    return A.class.isAssignableFrom(b.getClass());
}

public static void main(String[] args) throws RunnerException {
    Options opt = new OptionsBuilder()
            .include(InstanceOfTest.class.getSimpleName())
            .warmupIterations(5)
            .measurementIterations(5)
            .forks(1)
            .build();

    new Runner(opt).run();
}
}

它给:

Benchmark                            Mode  Cnt  Score   Error  Units
InstanceOfTest.testInstanceOf        avgt    5  1,972 ? 0,002  ns/op
InstanceOfTest.testIsAssignableFrom  avgt    5  1,991 ? 0,004  ns/op
InstanceOfTest.testIsInstance        avgt    5  1,972 ? 0,003  ns/op

因此,我们可以得出结论:instanceof as fast as isInstance() and isAssignableFrom() not far(+0.9%的执行时间)。所以无论你选择什么都没有真正的区别

其他回答

还有一个不同之处。如果要测试的类型(Class)是动态的,例如,作为方法参数传递,那么instanceof将不会为你切割它。

boolean test(Class clazz) {
   return (this instanceof clazz); // clazz cannot be resolved to a type.
}

但是你可以:

boolean test(Class clazz) {
   return (clazz.isAssignableFrom(this.getClass())); // okidoki
}

哎呀,这个答案已经讲过了。也许这个例子对某人有帮助。

Instanceof也不能用于基本类型或泛型类型。如下代码所示:

//Define Class< T > type ... 

Object e = new Object();

if(e instanceof T) {
  // Do something.
}

错误是:不能对类型参数t执行instanceof检查,而是使用它的erasure对象,因为进一步的泛型类型信息将在运行时被擦除。

由于删除运行时引用的类型擦除而无法编译。然而,下面的代码将编译:

if( type.isAssignableFrom(e.getClass())){
  // Do something.
}

在性能“2”方面(与JMH):

class A{}
class B extends A{}

public class InstanceOfTest {

public static final Object a = new A();
public static final Object b = new B();

@Benchmark
@BenchmarkMode(Mode.AverageTime)
@OutputTimeUnit(TimeUnit.NANOSECONDS)
public boolean testInstanceOf()
{
    return b instanceof A;
}

@Benchmark
@BenchmarkMode(Mode.AverageTime)
@OutputTimeUnit(TimeUnit.NANOSECONDS)
public boolean testIsInstance()
{
    return A.class.isInstance(b);
}

@Benchmark
@BenchmarkMode(Mode.AverageTime)
@OutputTimeUnit(TimeUnit.NANOSECONDS)
public boolean testIsAssignableFrom()
{
    return A.class.isAssignableFrom(b.getClass());
}

public static void main(String[] args) throws RunnerException {
    Options opt = new OptionsBuilder()
            .include(InstanceOfTest.class.getSimpleName())
            .warmupIterations(5)
            .measurementIterations(5)
            .forks(1)
            .build();

    new Runner(opt).run();
}
}

它给:

Benchmark                            Mode  Cnt  Score   Error  Units
InstanceOfTest.testInstanceOf        avgt    5  1,972 ? 0,002  ns/op
InstanceOfTest.testIsAssignableFrom  avgt    5  1,991 ? 0,004  ns/op
InstanceOfTest.testIsInstance        avgt    5  1,972 ? 0,003  ns/op

因此,我们可以得出结论:instanceof as fast as isInstance() and isAssignableFrom() not far(+0.9%的执行时间)。所以无论你选择什么都没有真正的区别

用一些例子来证明它怎么样?

@Test
public void isInstanceOf() {
    Exception anEx1 = new Exception("ex");
    Exception anEx2 = new RuntimeException("ex");
    RuntimeException anEx3 = new RuntimeException("ex");

    //Base case, handles inheritance
    Assert.assertTrue(anEx1 instanceof Exception);
    Assert.assertTrue(anEx2 instanceof Exception);
    Assert.assertTrue(anEx3 instanceof Exception);

    //Other cases
    Assert.assertFalse(anEx1 instanceof RuntimeException);
    Assert.assertTrue(anEx2 instanceof RuntimeException);
    Assert.assertTrue(anEx3 instanceof RuntimeException);
}

@Test
public void isAssignableFrom() {
    Exception anEx1 = new Exception("ex");
    Exception anEx2 = new RuntimeException("ex");
    RuntimeException anEx3 = new RuntimeException("ex");

    //Correct usage = The base class goes first
    Assert.assertTrue(Exception.class.isAssignableFrom(anEx1.getClass()));
    Assert.assertTrue(Exception.class.isAssignableFrom(anEx2.getClass()));
    Assert.assertTrue(Exception.class.isAssignableFrom(anEx3.getClass()));

    //Incorrect usage = Method parameter is used in the wrong order
    Assert.assertTrue(anEx1.getClass().isAssignableFrom(Exception.class));
    Assert.assertFalse(anEx2.getClass().isAssignableFrom(Exception.class));
    Assert.assertFalse(anEx3.getClass().isAssignableFrom(Exception.class));
}

这完全取决于代码中此时可用的内容。我不建议使用isAssignableFrom如果你正在使用一个实际的对象-有一个更好的选择。下面是一份根据你所拥有的产品进行排名的推荐列表:

如果你有一个对象a,并且你在编译时知道类型B: a instanceof实例 如果你有一个对象a,你不知道类型B,但你有一个对象B: .isInstance b.getClass () () 如果你有一个对象a,在编译时没有类型或实例化对象,但你有一个类对象class <?> someBClass: someBClass.isInstance (a) 如果你没有实例化对象,但是你有两个Class<?>对象: someBClass.isAssignableFrom (someAClass)。

假设你从列表的顶部开始,然后往下做,每一种方法都是实现目标的最简单的方法,根据我自己的研究,我相信你也会得到最好的表现。