我希望我的代码在模拟器上运行时与在设备上运行时略有不同。(例如,使用10.0.2.2代替公共URL在开发服务器上自动运行。)检测Android应用程序何时在模拟器中运行的最佳方法是什么?


当前回答

这个方法对我有用

    public static boolean isRunningOnEmulator(String fingerprint, String hardware, String manufacturer) {
    boolean isEmulatorFingerprint = fingerprint.endsWith("test-keys");
    boolean isHardware = hardware.toLowerCase().contains("intel") || hardware.toLowerCase().contains("vbox");
    boolean isEmulatorManufacturer = manufacturer.equals("Genymotion")
            || manufacturer.equals("unknown");

    if (isHardware || isEmulatorFingerprint && isEmulatorManufacturer) {
        return true;
    } else {
        return false;
    }
}

其他回答

另一种选择是查看ro。硬件属性,看看它是否设置为金鱼。不幸的是,在Java中似乎没有一个简单的方法来做到这一点,但在C中使用property_get()是很简单的。

无论您使用哪种代码来进行模拟器检测,我都强烈建议编写单元测试来覆盖所有构建。指纹,构建。硬件和构建。您所依赖的制造商值。下面是一些测试示例:

@Test
public void testIsEmulatorGenymotion() throws Exception {
    assertThat(
            DeviceUtils.isRunningOnEmulator(
                    "generic/vbox86p/vbox86p:4.1.1/JRO03S/eng.buildbot.20150217.102902:userdebug/test-keys",
                    "vbox86", "Genymotion")).isTrue();

    assertThat(
            DeviceUtils.isRunningOnEmulator(
                    "generic/vbox86p/vbox86p:5.1/LMY47D/buildbot06092001:userdebug/test-keys", "vbox86",
                    "Genymotion")).isTrue();
}

@Test
public void testIsEmulatorDefaultAndroidEmulator() throws Exception {
    assertThat(
            DeviceUtils.isRunningOnEmulator(
                    "generic_x86/sdk_google_phone_x86/generic_x86:5.0.2/LSY66H/1960483:eng/test-keys", "goldfish",
                    "unknown")).isTrue();

    assertThat(
            DeviceUtils.isRunningOnEmulator(
                    "Android/sdk_google_phone_x86_64/generic_x86_64:6.0/MASTER/2469028:userdebug/test-keys",
                    "ranchu", "unknown")).isTrue();
}

@Test
public void testIsEmulatorRealNexus5() throws Exception {
    assertThat(
            DeviceUtils.isRunningOnEmulator("google/hammerhead/hammerhead:6.0.1/MMB29K/2419427:user/release-keys",
                    "hammerhead", "LGE")).isFalse();
}

...下面是我们的代码(为了简洁起见,删除了调试日志和注释):

public static boolean isRunningOnEmulator() {
    if (sIsRunningEmulator == null) {
        sIsRunningEmulator = isRunningOnEmulator(Build.FINGERPRINT, Build.HARDWARE, Build.MANUFACTURER);
    }

    return sIsRunningEmulator;
}

static boolean isRunningOnEmulator(String fingerprint, String hardware, String manufacturer) {
    boolean isEmulatorFingerprint = fingerprint.endsWith("test-keys");
    boolean isEmulatorManufacturer = manufacturer.equals("Genymotion")
            || manufacturer.equals("unknown");

    if (isEmulatorFingerprint && isEmulatorManufacturer) {
        return true;
    } else {
        return false;
    }
}

以下是我的解决方案(它只适用于在调试机器上运行web服务器): 我已经创建了一个后台任务,当应用程序启动时启动。它查找http://10.0.2.2,如果它存在,它将全局参数(IsDebug)更改为true。这是一种无声的方式来找出你在哪里跑步。

public class CheckDebugModeTask extends AsyncTask<String, Void, String> {
public static boolean IsDebug = false;

public CheckDebugModeTask()
{

}

@Override
protected String doInBackground(String... params) {     
  try {
    HttpParams httpParameters = new BasicHttpParams();
    int timeoutConnection = 1000;
    HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
    int timeoutSocket = 2000;
    HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);

    String url2 = "http://10.0.2.2";        
          HttpGet httpGet = new HttpGet(url2);
    DefaultHttpClient client = new DefaultHttpClient(httpParameters);

    HttpResponse response2 = client.execute(httpGet);
    if (response2 == null || response2.getEntity() == null || response2.getEntity().getContent() == null)
    return "";

    return "Debug";

} catch (Exception e) {
    return "";
}
}

@Override
protected void onPostExecute (String result)
{       
if (result == "Debug")
{
    CheckDebugModeTask.IsDebug = true;
}
}

从主活动onCreate:

CheckDebugModeTask checkDebugMode = new CheckDebugModeTask();
checkDebugMode.execute("");

Firebase Crashlytics是这样做的:

private static final String GOLDFISH = "goldfish";
private static final String RANCHU = "ranchu";
private static final String SDK = "sdk";
    
public static boolean isEmulator() {
    return Build.PRODUCT.contains(SDK)
        || Build.HARDWARE.contains(GOLDFISH)
        || Build.HARDWARE.contains(RANCHU);
}

由于Genymotion的底层模拟引擎是VirtualBox,这不会很快改变,我发现以下代码是最可靠的:

   public static boolean isGenymotion() {
        return Build.PRODUCT != null && Build.PRODUCT.contains("vbox");
}